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    • Posted by Sathwika Panigrahi 4 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Abirami Kamalbabu 4 years ago

    The maximum value of static friction when the object just begins to move is called limiting friction.

    0Thank You

    Vansh Jain 4 years ago

    Maximum value of static friction

    1Thank You

    Yogita Ingle 4 years ago

    The amount of friction that can be applied between two surfaces is limited and if the forces acting on the body are made sufficiently great, the motion will occur. Hence, we can define limiting friction as the maximum value of static friction that comes into play when the body is just at the point of sliding over the surface of another body. Limiting friction is the product of normal force and coefficient of limiting friction. Mathematically, this is represented as

    F=muN

    Here,mu is the coefficient of limiting friction and N is the normal force

    The limiting friction is always opposite to the motion of the object.

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    • Posted by Lokesh Dhillon 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Swati Gaur 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Dev Singh 4 years ago

    F=m×a

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    • Posted by Ruhaan Kadri 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sakshi Pathak 4 years ago

    From which chapter is this question??

    0Thank You

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    • Posted by Kiran Limbu 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Ankit Verma 4 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Sakshi Pathak 4 years ago

    When displacement occurs in the direction of applied force it is known as the work done. W=F*s

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    Varsha Baboria 4 years ago

    Work is defined as the product of force (F) and the actual distance (S) moved by the body in the direction of application force. It is a scalar quantity. In mathematics, work = force ×distance i.e, W = F×S

    0Thank You

    Yogita Ingle 4 years ago

    Work is said to be done when a force applied on the body displaces the body through a certain distance in the direction of applied force.
    It is measured by the product of the force and the distance moved in the direction of the force, i.e., W = F-S

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    • Posted by Muskan Kanwar 4 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Abirami Kamalbabu 4 years ago

    Dyne is the cgs unit of force Newton is the SI unit of force 1 N = 10^5 dyne

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    Harish Thori 4 years ago

    Cgs unit of force

    0Thank You

    Royal Thakur ? 4 years ago

    Unit of force...

    2Thank You

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    • Posted by Shifana Sudheer 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Yogita Ingle 4 years ago

    mN means milli newton, 1 mN =  {tex}{{10}^{-3}}{/tex}  N.
    Nm means Newton-metre.
    nm means nanometer, 1 nm =  {tex}{{10}^{-9}}{/tex}  m.

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    • Posted by Diksha Bawa 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sakshi Pathak 4 years ago

    Do you have the answer ??? Means, since the values are not given so it can be....... I = mr²

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    • Posted by Avantika Mase 3 years, 7 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sia ? 3 years, 7 months ago

    Please ask question with complete information.

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    • Posted by Kartavya Sharma 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Sakshi Pathak 4 years ago

    CBSE > Class 11 > Physics
    • 4 answers

    Sakshi Pathak 4 years ago

    (10x1/2)/10+10√3 = 5/(10+5√3) =5/5(2+√3) = 1/(2+√3)

    0Thank You

    Harish Thori 4 years ago

    Ans is 10/10+5√3

    0Thank You

    Sakshi Pathak 4 years ago

    But cos 30°= √3/2 So it will be (10+10X√3/2)

    0Thank You

    Dεερακ Ȿιηɠꜧ 4 years ago

    (10×1/2) / (10+10×1/2) =
    5/(10+5) = 1/3 =
    0.333333333...... ans

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    • Posted by Aadya Singh 4 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Hemant Chauhan 4 years ago

    pta ni ?

    1Thank You

    Dεερακ Ȿιηɠꜧ 4 years ago

    mere paas ak tarika hai, let's talk in a subject where no report is active ??

    3Thank You

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    • Posted by Sujata Sheikh 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Tamanna Abbasi 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Tamanna Abbasi 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Abirami Kamalbabu 4 years ago

    As the body continues to move without change in velocity, we consider it as zero impulse. This can be proved numerically. m1 = m2 = 0.05 kg U1 = V1 = 6m/s U2 = V2 = -6 m/s Impulse = Force × time =ma × t = m( v-u)/t × t = m(v - u) Impulse on 2 by 1 = m1 (v1 -u1) = m1(0) =0 Impulse on 1 by 2 = m2(v2-u2) =0

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    • Posted by Royal Thakur ? 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Yogita Ingle 4 years ago

    The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics.

    Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

    These equations link five kinematic variables:

    • Displacement (denoted by Δx)
    • Initial velocity (v0)
    • Final velocity (denoted by v)
    • Time interval (denoted by t)
    • Constant acceleration (denoted by a)

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    • Posted by Diya Vijay 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sakshi Pathak 4 years ago

    Applying conservation of linear momentum... Recoil velocity of the gun = 0.2m/s

    1Thank You

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    • Posted by Har Har Mahadev 🙏 4 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Ankit Sharma 4 years ago

    ??same to you??

    0Thank You

    ? S.S. ? 4 years ago

    Same to uh?

    1Thank You

    Dhruv ... 4 years ago

    ??

    1Thank You

    ANSWER

    • Posted by Saloni Pandey 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    ? S.S. ? 4 years ago

    ?!

    0Thank You

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    • Posted by Saloni Pandey 4 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Har Har Mahadev 🙏 4 years ago

    You to

    0Thank You

    Pk Singh 4 years ago

    Happy deepawali

    4Thank You

    ANSWER

    • Posted by Varaprasad Mamidisetti 4 years ago

    CBSE > Class 11 > Physics
    • 1 answers

    Yogita Ingle 4 years ago

    In rotation the body's centre of mass does not undergo any translation motion. In other words the centre of mass will remain at on place. Like a top spinning on its axis.

    In circular motion the body's centre of mass goes around a fixed centre maintaining a constant distance from it. Which means the centre of mass is actually going through a translation motion. For example an ant sitting on the circumference of the spinning top in the above example.

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    The zeroth law of thermodynamics states that ‘two systems in thermal equilibrium with a third system separately are in thermal equilibrium with each other’. The Zeroth Law leads to the concept of temperature. 2. Internal energy of a system is the sum of kinetic energies and potential energies of the molecular constituents of the system. It does not include the over-all kinetic energy of the system. Heat and work are two modes of energy transfer to the system. Heat is the energy transfer arising due to temperature difference between the system and the surroundings. Work is energy transfer brought about by other means, such as moving the piston of a cylinder containing the gas, by raising or lowering some weight connected to it. 3. The first law of thermodynamics is the general law of conservation of energy applied to any system in which energy transfer from or to the surroundings (through heat and work) is taken into account. It states that ∆Q = ∆U + ∆W where ∆Q is the heat supplied to the system, ∆W is the work done by the system and ∆U is the change in internal energy of the system. Now suppose η R < ηI i.e. if R were to act as an engine it would give less work output than that of I i.e. W < W ′ for a given Q1 . With R acting like a refrigerator, this would mean Q2 = Q1 – W > Q1 – W ′. Thus, on the whole, the coupled I-R system extracts heat (Q1 – W) – (Q1 – W ′) = (W ′ – W ) from the cold reservoir and delivers the same amount of work in one cycle, without any change in the source or anywhere else. This is clearly against the Kelvin-Planck statement of the Second Law of Thermodynamics. Hence the assertion ηI > η R is wrong. No engine can have efficiency greater than that of the Carnot engine. A similar argument can be constructed to show that a reversible engine with one particular substance cannot be more efficient than the one using another substance. The maximum efficiency of a Carnot engine given by Eq. (12.32) is independent of the nature of the system performing the Carnot cycle of operations. Thus we are justified in using an ideal gas as a system in the calculation of efficiency η of a Carnot engine. The ideal gas has a simple equation of state, which allows us to readily calculate η, but the final result for η, [Eq. (12.32)], is true for any Carnot engine. This final remark shows that in a Carnot cycle, 2 1 2 1 T T = Q Q (12.33) is a universal relation independent of the nature of the system. Here Q1 and Q2 are respectively, the heat absorbed and released isothermally (from the hot and to the cold reservoirs) in a Carnot engine. Equation (12.33), can, therefore, be used as a relation to define a truly universal thermodynamic temperature scale that is independent of any particular properties of the system used in the Carnot cycle. Of course, for an ideal gas as a working substance, this universal temperature is the same as the ideal gas temperature introduced in section 12.11. I R W Fig. 12.12 An irreversible engine (I) coupled to a reversible refrigerator (R). If W ′ > W, this would amount to extraction of heat W′ – W from the sink and its full conversion to work, in contradiction with the Second Law of Thermodynamics. 2020-21

    • Posted by Badal Barasiya 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by B S 4 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Chitresh Khandal 4 years ago

    PA+qB+rC is this the answer

    1Thank You

    Kalki Kalki 4 years ago

    Open App  Salaam Rocky Bhai PLAY Chal ne ka hukum Ruk ne ka hukum Zindagi pe hukum Maut pe hukum Bandook pe hukum Dushman pe hukum Leharon pe hukum Bombai pe hukum Jaan Bambai ka, jaan Bambai ka Jaan Bambai ka jaane re Iski aankhon mein aankh na daalo Noch leta hai praan ve Aag toofan jab bhi milta hai Aisa barood paida hota hai Aye Khuda zara dekho Logon ke dil mein sultan dekho Dushman ko yeh hai shaitan dekho Aye Khuda zara roko Ruk ne wala karta Mud ne wala karta Bombai ki galiyan bhi Ghabra ke yun bolenge saala Salaam Rocky bhai Rock, Rock, Rocky Salaam Rocky bhai Salaam Rocky Bhai Salam Rocky bhai Ilaaka tera bhai Tu hai sabka bhai music........ Maa ne dua diya tum to panga liya jeetoge tum duniya khuda hairaan hoga maksad pura hoga ulta tairon dariyan kaun isko rokega kaha se layega fauj ko ek me bhi himmat bhi nahi hai panga lene ko jab bhi jaada hai haath loha hai jag ko bechain karne ka ye funda hai hat zara khatra hai apne wala karza murne wala karza mumbai ki galiyan bhi ghabra ke bolegi saala Salaam Rocky bhai Rock, Rock, Rocky Salaam Rocky bhai Salaam Rocky Bhai Salam Rocky bhai Ilaaka tera bhai Tu hai sabka bhai

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    • Posted by Prastuti Shukla 4 years ago

    CBSE > Class 11 > Physics
    • 2 answers

    Ashish Chauhan 4 years ago

    D=S×T D=90×-3 D=-270 m

    0Thank You

    Ashish Chauhan 4 years ago

    V= u+at O=90+30t t= -90/30 t = -3 s

    0Thank You

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    • Posted by Surjalata Singh 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Dhruv ... 4 years ago

    CBSE > Class 11 > Physics
    • 4 answers

    Legendary 4 years ago

    ?

    0Thank You

    Aadya Singh 4 years ago

    ??

    1Thank You

    Dhruv ... 4 years ago

    ??

    0Thank You

    Legendary 4 years ago

    Feastival

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    • Posted by Usha M.R 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Jyoti Singh 4 years ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Saloni Choudhary 4 years ago

    CBSE > Class 11 > Physics
    • 3 answers

    Saloni Choudhary 3 years, 10 months ago

    ??

    0Thank You

    Saloni Choudhary 4 years ago

    Thanks

    2Thank You

    Yogita Ingle 4 years ago

    Scalar products can be found by taking the component of one vector in the direction of the other vector and multiplying it with the magnitude of the other vector”. It can be defined as: Scalar product or dot product is an algebraic operation that takes two equal-length sequences of numbers and returns a single number.

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