No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 2 answers

Harish Thori 4 years, 10 months ago

It is centre of body where mass of whole body concerntrated

Yogita Ingle 4 years, 10 months ago

The centre of mass of a body or a system of particles is defined as “A single point at which the whole mass of the body or system is imagined to be concentrated and all the applied forces acts at that point.”

  • 3 answers

A.T'S Gaming 4 years, 10 months ago

Thabkyou

Prateek .. 4 years, 10 months ago

she is the best..

Yogita Ingle 4 years, 10 months ago

Let uniform acceleration be a

Acceleration is defined as rate of change of velocity

  ......................(1)
where v is velocity of an object at time t

By integrating above ewqn.(1) , we get

where u is velocity at time t = 0 and v is velocity after time t seconds

from above integration we get ,  v - u = a t   or  v = u + ( a t )  ...................... (2)

velocity is defined as rate of change of displacement 

 ...................(3)

Where S is distance travelled.

By integrating above equation (2) , we get

Where xo is initial position and x is position after time t

x - xo = u t + (1/2) a t2 .................. (4)

If the object travelled a distance S staring from initial velocity u and attained final velocity v after travelling distance S in time t , then we have

S = (1/2) ( u+v ) t  ...............(5)

Let us substitute t from eqn.(2) in eqn.(5) as  t = [ ( v - u ) / a ] , then we have

S = (1/2) ( u + v ) [ ( v - u ) /a ]    or  v2 = u2 + ( 2 a S )  ..................  (6)

Eqn.(2) , eqn.(4) and eqn.(6) are equations of motion

  • 1 answers

Yogita Ingle 4 years, 10 months ago

When the ball is thrown vertically upward its velocity decreases as it moves upward due to the gravitational force acting on it downwards and thus the graph slopes downwards with a negative gradient.

When it reaches a certain height, that is at a stationary point, the velocity becomes zero and at this point the graph cuts the x axis.

The ball then comes back with an increasing velocity from zero to its initial position and at this point the graph slopes downwards from the x axis.

  • 3 answers

Abirami Kamalbabu 4 years, 10 months ago

The maximum value of static friction when the object just begins to move is called limiting friction.

Vansh Jain 4 years, 10 months ago

Maximum value of static friction

Yogita Ingle 4 years, 10 months ago

The amount of friction that can be applied between two surfaces is limited and if the forces acting on the body are made sufficiently great, the motion will occur. Hence, we can define limiting friction as the maximum value of static friction that comes into play when the body is just at the point of sliding over the surface of another body. Limiting friction is the product of normal force and coefficient of limiting friction. Mathematically, this is represented as

F=muN

Here,mu is the coefficient of limiting friction and N is the normal force

The limiting friction is always opposite to the motion of the object.

  • 1 answers

Dev Singh 4 years, 10 months ago

F=m×a
  • 3 answers

Sakshi Pathak 4 years, 10 months ago

When displacement occurs in the direction of applied force it is known as the work done. W=F*s

Varsha Baboria 4 years, 10 months ago

Work is defined as the product of force (F) and the actual distance (S) moved by the body in the direction of application force. It is a scalar quantity. In mathematics, work = force ×distance i.e, W = F×S

Yogita Ingle 4 years, 10 months ago

Work is said to be done when a force applied on the body displaces the body through a certain distance in the direction of applied force.
It is measured by the product of the force and the distance moved in the direction of the force, i.e., W = F-S

  • 3 answers

Abirami Kamalbabu 4 years, 10 months ago

Dyne is the cgs unit of force Newton is the SI unit of force 1 N = 10^5 dyne

Harish Thori 4 years, 10 months ago

Cgs unit of force

Royal Thakur ? 4 years, 10 months ago

Unit of force...
  • 1 answers

Yogita Ingle 4 years, 10 months ago

mN means milli newton, 1 mN =  {tex}{{10}^{-3}}{/tex}  N.
Nm means Newton-metre.
nm means nanometer, 1 nm =  {tex}{{10}^{-9}}{/tex}  m.

  • 1 answers

Sakshi Pathak 4 years, 10 months ago

Do you have the answer ??? Means, since the values are not given so it can be....... I = mr²
  • 1 answers

Sia ? 4 years, 5 months ago

Please ask question with complete information.

  • 4 answers

Sakshi Pathak 4 years, 10 months ago

(10x1/2)/10+10√3 = 5/(10+5√3) =5/5(2+√3) = 1/(2+√3)

Harish Thori 4 years, 10 months ago

Ans is 10/10+5√3

Sakshi Pathak 4 years, 10 months ago

But cos 30°= √3/2 So it will be (10+10X√3/2)

Dεερακ Ȿιηɠꜧ 4 years, 10 months ago

(10×1/2) / (10+10×1/2) =
5/(10+5) = 1/3 =
0.333333333...... ans
  • 2 answers

Hemant Chauhan 4 years, 10 months ago

pta ni ?

Dεερακ Ȿιηɠꜧ 4 years, 10 months ago

mere paas ak tarika hai, let's talk in a subject where no report is active ??
  • 0 answers
  • 1 answers

Abirami Kamalbabu 4 years, 10 months ago

As the body continues to move without change in velocity, we consider it as zero impulse. This can be proved numerically. m1 = m2 = 0.05 kg U1 = V1 = 6m/s U2 = V2 = -6 m/s Impulse = Force × time =ma × t = m( v-u)/t × t = m(v - u) Impulse on 2 by 1 = m1 (v1 -u1) = m1(0) =0 Impulse on 1 by 2 = m2(v2-u2) =0
  • 1 answers

Yogita Ingle 4 years, 11 months ago

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics.

Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

  • Displacement (denoted by Δx)
  • Initial velocity (v0)
  • Final velocity (denoted by v)
  • Time interval (denoted by t)
  • Constant acceleration (denoted by a)
  • 3 answers

Ankit Sharma 4 years, 10 months ago

??same to you??

? S.S. ? 4 years, 11 months ago

Same to uh?

Dhruv ... 4 years, 11 months ago

??
  • 1 answers

? S.S. ? 4 years, 11 months ago

?!
  • 2 answers

Har Har Mahadev 🙏 4 years, 11 months ago

You to

Pk Singh 4 years, 11 months ago

Happy deepawali

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App