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  • 1 answers

Ankit Kumar Sain 3 years, 10 months ago

Solution verified Verified by Toppr At t=0..50s the x−and y- coordinates are x=v 0x t ​ =(9.0ms −1 )(0.50s)=4.5m y=− 2 1 ​ gt 2 =− 2 1 ​ (10ms −2 )(0.50s) 2 =− 4 5 ​ m the negative value of y shows that this time the motorcycles is below its starting point. The motorcycle's distance from the origin at this time. r= x 2 +y 2 ​ = ( 2 9 ​ ) 2 +( 4 5 ​ ) 2 ​ = 4 349 ​ ​ m The components of velocity at this time are v x ​ =v 0x ​ =9.0ms −1 v y ​ =−gt=(−10ms −2 )(0.50s)=−5ms −1 The speed (magnitude of the velocity ) at this time is v= v x 2 ​ +v y 2 ​ ​ = (9.0ms −1 ) 2 +(−5ms −1) 2 ​ = 106 ​ ms −1
  • 1 answers

Ankit Kumar Sain 3 years, 10 months ago

Solution verified Verified by Toppr Since he makes his strokes normal to the river current, the movement of the river will have no effect on the time of crossing the bank. The time will be, T= Speed Distance ​ = 4 1 ​ hr=0.25hr=15min. In the same time, he will go down by Distance=Speed x time=3km/hr x 0.25hr=0.75km=750m
  • 1 answers

Ankit Kumar Sain 3 years, 10 months ago

Answer: hola mate here is ur answer a) x = V0 cos(35°) t 30 = V0 cos(35°) t t = 30 / V0 cos(35°) 1.8 = -(1/2) 9.8 (30 / V0 cos(35°))2 + V0 sin(35°)(30 / V0cos(35°)) V0 cos(35°) = 30 √ [ 9.8 / 2(30 tan(35°)-1.8) ] V0 = 18.3 m/s b) t = x / V0 cos(35°) = 2.0 s tq♥️
  • 1 answers

Shahid Ahmed 3 years, 10 months ago

Ask ur classmates
  • 2 answers

Aseem Mahajan 3 years, 10 months ago

A is true R is false. That uncertainty is error

Ankit ............ 3 years, 10 months ago

Both are true
  • 3 answers

Edutainment Harsh 3 years, 10 months ago

A projectile motion is a motion in body is moving horizontally and vertically as well or simply it is a 2- dimensional motion

Rahul Parul 3 years, 10 months ago

Eg. Neeraj chopra throw javelin Kicked football

Rahul Parul 3 years, 10 months ago

A projectile is a name given to a body which is thrown with the initial velocity and then allow to move under the action alone.
  • 3 answers

Deepanshu Varshney 3 years, 10 months ago

We can write Dimentional Formula of any unit using mass, length and time.

Mannu Dahiya 3 years, 10 months ago

It is in the form of MLT( mass, length, time)

Jp Saigirisha 3 years, 10 months ago

(M°d°T-1}
  • 5 answers

Anjan Karthi 3 years, 10 months ago

Cannot be determined.

Sakshi Bharadwaj 3 years, 10 months ago

0

Vasudha Vasudha 3 years, 10 months ago

0

Ankit Rawat 3 years, 10 months ago

0

Karan Dubey 3 years, 10 months ago

1
  • 3 answers

Manish Rajput 3 years, 10 months ago

When the lawn roller is pulled, the normal component decreases that means the cosine component of force decreases. ... This will increase the frictional force. Therefore we can say that it is easier to pull

Mannu Dahiya 3 years, 10 months ago

While pulling, by weight we can pull, =netforce=weight-fsinTheta(vertically along x-axis). While pushing, by weight and also force is also applied on that to make it push, =net force=weight+Fsintheta

Vasudha Vasudha 3 years, 10 months ago

When the lawn roller is pulled, the normal component decreases that means the cosine component of force decreases. ... This will increase the frictional force. Therefore we can say that it is easier to pull the lawn roller than to push it because the normal component of force decreases when the lawn roller is pulled.
  • 1 answers

Ankit Kumar Sain 3 years, 10 months ago

Given, u=0m/s, Vertical componenet of initial velocity s=4.9cm=0.049m g=9.8m/s 2 d=25m Applying 2nd equation of motion in vertical direction s=ut+ 2 1 ​ gt 2 s=0×+ 2 1 ​ gt 2 s= 2 1 ​ gt 2 t= g 2s ​ ​ = 9.8 2×0.049 ​ ​ t=0.1sec Velocity, v= t d ​ v= 0.1 25 ​ =250m/s
  • 2 answers

Vasudha Vasudha 3 years, 10 months ago

Motion in a plane is called a motion in two dimensions. Its examples are projectile motion, circular motion. For the analysis of such motion, our reference is an origin and two co-ordinate axes viz: X and Y-axis and scalar and vector physical quantities

Mansi Joshi 3 years, 10 months ago

Motion in a plane line
  • 1 answers

Priya Tomar 3 years, 11 months ago

A black hole is an area of such immense gravity that nothing—not even light—can escape from it.
  • 0 answers
  • 4 answers

Mansi Joshi 3 years, 10 months ago

velocity changes at uniform rate If the velocity of an object changes at a uniform rate, then the acceleration that causes the change in velocity is called uniform acceleration or constant acceleration. For example, the force of gravity imparts an acceleration uniformly which is called acceleration due to gravity. Hence,option B is correct.

Divya. Kumari 3 years, 11 months ago

It will be increased

Ansh Dwivedi 3 years, 11 months ago

Yess

Anjan Karthi 3 years, 11 months ago

(a) will be increasing
  • 0 answers
  • 1 answers

Mannu Dahiya 3 years, 11 months ago

2πr/2 (for circumference of semicircle) = 22/7*7=22
  • 3 answers

Heena Kangtani 3 years, 11 months ago

Clear your concept Solve ncert question and some extra question which is available on this app Practice every day And do revision compulsory

Mannu Dahiya 3 years, 11 months ago

Through notes

Vikas Singh 3 years, 11 months ago

By reading the book
  • 1 answers

Rihan Khan 3 years, 11 months ago

Learn topic table
  • 2 answers

Sia ? 3 years, 11 months ago

The first states that a body continues in a state of rest or uniform motion in a straight line unless it is acted on by an external force.

Ashok Kumar 3 years, 11 months ago

First law= if any object in motion wants to be in motion, if any object in rest wants to be in rest unless, until external force applied on it. It is also called inertial law of motion... Second law= the rate of change of momentum is directly proportional to the applied external force... According to this law force is defines as product of mass and acceleration.. Third law= every action their is equal and opposite reaction , it is also called as action reaction pair...
  • 2 answers

Anjan Karthi 3 years, 11 months ago

Hope it helps. ?

Anjan Karthi 3 years, 11 months ago

If the forces are F1 = F2, then R^2 = 3 F1F2 = 3 F1^2. Therefore, F1^2 + F2^2 + 2F1F2cos θ = 3F1^2. Or, 2F1^2 + 2F1^2 cos θ = 3F1^2. 2F1^2 (1 + cos θ) = 3F1^2. cos θ = 3/2 -1 = 1/2. Therefore, angle = cos^-1 (1/2) = 60//

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