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    • Posted by Vishakha Yadav 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Vasudha Vasudha 3 years, 4 months ago

    The scalar product of a and b is: a · b = |a||b| cosθ We can remember this formula as: “The modulus of the first vector, multiplied by the modulus of the second vector, multiplied by the cosine of the angle between them

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    • Posted by Pooja Tarai 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 4 answers

    Naman Patel 3 years, 4 months ago

    No

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    Anjan Karthi 3 years, 4 months ago

    No, it depends upon how we apply Sign conventions in the situation. If we take downwards as -ve and upwards as +ve, then g becomes -ve and when we take downwards as +ve and upwards as -ve, then g would be positive.

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    Sneha Sneha 3 years, 4 months ago

    Yes it would be because acceleration due Gravity is always downwards in -ve y axis

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    Vasudha Vasudha 3 years, 4 months ago

    Towards the center of the Earth, the gravity is defined to the be negative. At all points on the trajectory of a projectile, the gravitational acceleration points in the same direction, which is downwards toward the center of the Earth. So, the sign for the gravitational acceleration is always negative.

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    • Posted by Kiran Kumari 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Shivani Choudhary 3 years, 4 months ago

    Give the common name of periplanata American

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    • Posted by Nidhi Sharma 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 5 answers

    Srishti Soumya 3 years, 4 months ago

    Potential energy

    0Thank You

    Anupriya Maurya 3 years, 4 months ago

    C

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    Nidhi Sharma 3 years, 4 months ago

    Please tell the exact one!!

    0Thank You

    Jyoti Sharma 3 years, 4 months ago

    A

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    Mansi Gupta 3 years, 4 months ago

    C

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    • Posted by Ganesan Sankar 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Jyoti Sharma 3 years, 4 months ago

    The current will change direction as the electron passes through the circular loop

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    • Posted by Cilestina Lepcha 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Vasudha Vasudha 3 years, 4 months ago

    |A+B−→−−−|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ Complete answer: Let the two vectors be |A→| and |B→|. θ be the angle between both the vectors. Both the vectors have the same magnitude. ∴|A→|=|A→| …(1) Let the resultant have magnitude equal to vector A. Thus, the resultant is given by, |A→|=|B→|=|A+B−→−−−| …(2) The magnitude of resultant of two vectors is given by, |A+B−→−−−|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ …(3) From the equation. (2) and equation. (3) we get, |A→|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ Squaring both the sides we get, ⇒|A→|2=|A→|2+|B→|2+2|A→||B→|cosθ Substituting equation. (1) in above equation we get, |A→|2=|A→|2+|A→|2+2|A→||A→|cosθ ⇒|A→|2=2|A→|2+2|A→||A→|cosθ ⇒−|A→|2=2|A→||A→|cosθ ⇒cosθ=−12 ⇒θ=cos−1(12) ⇒θ=120° Hence, the angle between the two vectors is 120°.

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    • Posted by Muskan Johal 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 0 answers
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    • Posted by Ansh Saurav Kashyap 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 3 years, 4 months ago

    F = n × ma = n × mv/t. Therefore, n = F/mv = 144 × 1000 / 1200 × 40 = 3//

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    • Posted by Bholu Rahar 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Mahak Maddhhesiya 3 years, 4 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Dimpal Kumari Mali B 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 3 years, 4 months ago

    LHS →v = [LT^-1]. RHS → √GM/R = { [M^-1L^3T^-2] [M] / [L] }^1/2 = { [L^2T^-2] }^1/2 = [LT^-1]. Therefore, LHS = RHS.

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    • Posted by Arman Verma 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Soniya Rana 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 3 years, 5 months ago

    Vo = √GM/R+h = √6.67 × 10^-11 × 6 × 10^24 / 6.4 × 10^6 + 400 = 40.02 × 10^13 / 6400 × 10^3 + 400 = 40.02 × 10^13 / 400 (16001) = 40.02 × 10^13 / 6400400 = 40.02 × 10^13 / 6.4004 × 10^6 = 6.25 × 10^7 m/s. //

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    • Posted by Soniya Rana 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Yash Babre 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 3 years, 5 months ago

    KE required = 1/2 × m × Ve^2 = 5000 × 2 × 6.67 × 10^-11 × 6 × 10^24 / 6.4 × 10^6 × 2 = 400.2 × 10^16 / 12.8 × 10^6 = 31.265 × 10^10 J//

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    • Posted by Manisha Pathak 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Manisha Pathak 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ankul Prajapati 3 years, 4 months ago

    Light year

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    • Posted by Saloni Taank 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Vijay Vishwakarma 3 years, 4 months ago

    All non zero no. Are SF

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    • Posted by Tenzin Choney 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Palak Singh 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 3 answers

    Aditya Dubey 3 years, 5 months ago

    5 waat

    0Thank You

    Ragini Gupta 3 years, 5 months ago

    Work = 600j Time = 2 min = 2×60= 120 sec Power = work/time = 600/120 = 5 j/s = 5 watt

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    Yogiraj Vidhyarthi 3 years, 5 months ago

    5watt

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    • Posted by Mohit Yadav 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    ?Shreya.Kamalakar✔️ Naik 3 years, 5 months ago

    kyxs

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    • Posted by Pranjali Thakre 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 3 years, 5 months ago

    1 joules = 10^7 ergs.

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    • Posted by Nivedita Corner 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Anjan Karthi 3 years, 5 months ago

    Horizontal force = new W cosθ - W sinθ

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    • Posted by Nivedita Corner 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Nivedita Corner 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Aman Yadav 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 0 answers
    ANSWER

    • Posted by Shrishti Mishra 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ankit Kumar Sain 3 years, 5 months ago

    Solution verified Verified by Toppr At t=0..50s the x−and y- coordinates are x=v 0x t ​ =(9.0ms −1 )(0.50s)=4.5m y=− 2 1 ​ gt 2 =− 2 1 ​ (10ms −2 )(0.50s) 2 =− 4 5 ​ m the negative value of y shows that this time the motorcycles is below its starting point. The motorcycle's distance from the origin at this time. r= x 2 +y 2 ​ = ( 2 9 ​ ) 2 +( 4 5 ​ ) 2 ​ = 4 349 ​ ​ m The components of velocity at this time are v x ​ =v 0x ​ =9.0ms −1 v y ​ =−gt=(−10ms −2 )(0.50s)=−5ms −1 The speed (magnitude of the velocity ) at this time is v= v x 2 ​ +v y 2 ​ ​ = (9.0ms −1 ) 2 +(−5ms −1) 2 ​ = 106 ​ ms −1

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    • Posted by Nikita Jain 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ankit Kumar Sain 3 years, 5 months ago

    Solution verified Verified by Toppr Since he makes his strokes normal to the river current, the movement of the river will have no effect on the time of crossing the bank. The time will be, T= Speed Distance ​ = 4 1 ​ hr=0.25hr=15min. In the same time, he will go down by Distance=Speed x time=3km/hr x 0.25hr=0.75km=750m

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    • Posted by Rahul Parul 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Ankit Kumar Sain 3 years, 5 months ago

    Answer: hola mate here is ur answer a) x = V0 cos(35°) t 30 = V0 cos(35°) t t = 30 / V0 cos(35°) 1.8 = -(1/2) 9.8 (30 / V0 cos(35°))2 + V0 sin(35°)(30 / V0cos(35°)) V0 cos(35°) = 30 √ [ 9.8 / 2(30 tan(35°)-1.8) ] V0 = 18.3 m/s b) t = x / V0 cos(35°) = 2.0 s tq♥️

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    • Posted by Ankit Kumar Sain 3 years, 5 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Shahid Ahmed 3 years, 5 months ago

    Ask ur classmates

    1Thank You

    ANSWER

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