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  • 2 answers

Neha Prasad 4 years ago

Vector/unit vector

Mannu Dahiya 4 years ago

Magnitude of vector=vector/unit vector
  • 1 answers

Kashish Garg 4 years ago

Unlike solid and liquid state, molecules in gaseous state show random motion. That is the reason, gases take the shape of container and spread quickly in space. The random motion of molecules in the gaseous state is due to high kinetic energy in molecules. They have weak intermolecular interactions between them.
  • 3 answers

Mashira Rubab 4 years ago

[MLT-2]

Varun Agarwal 4 years ago

Okay thank you

Priyanshu Dubey 4 years ago

It is an acceleration therefore it's dimensional formula will be equal to dimensional formula of acceleration
  • 4 answers
Foot , pound, time

Arisha Fatma 4 years ago

In thus system,unit if length is foot,the unit of mass is pound and the unit of time is second

Mannu Dahiya 4 years ago

Foot(length) Pound(mass) Second(time). This critria was followed by Britishers by which earlier we also used it after the independence of Indians from them as we were also habitual of their culture.

Anjan Karthi 4 years ago

FPS system is the System of units and measurements which are of British origin. The three major units in this system are FEET for length (ft), POUNDS for mass (pd) and SECOND for time (sec).
  • 2 answers

Anjan Karthi 4 years ago

g at the depth = g at surface (1-d/r) = 9.8 (1- 640/6400000 ) = 9.8 (1 - 1/10000) = 9.8 (9999/10000) = 9.799 m/s^2.//

Devil Dada 4 years ago

34
  • 1 answers
Y=FL/A∆L Given,A=5×10^-5m2,Y=2×10^11 nm^-2,L=X ,∆L=2L-L=L Putting the values in formulà F=YA∆L/L F=10^7N
  • 2 answers

Anjan Karthi 4 years ago

L' = 2L. T' = 2 T. (where, L' and T' are the new units of length and time). Therefore, Numerical value of new g ie, g' = a = L'/T' = 2L/2T = L/T. // Therefore, g' = g.
Sorry I don't know
  • 1 answers

Vasudha Vasudha 4 years ago

Assuming u=0 and constant g=10ms−2 the work done by the grativational force is Wg=mgh =2×10−3×10×103=20J (b) ΔK=12mV2−0 =12×2×10−3×40×40 =1.6J From the work-energy theorem Δk=Wg+Wr where Wr is the work done by the opposing resistive force. 1.6=20+Wr Wr=−18.4J
  • 2 answers

Mannu Dahiya 4 years ago

Unsubscribe kr dia becoz of u not liked my comment

Mannu Dahiya 4 years ago

Ho gya Like my comment
  • 1 answers

Vasudha Vasudha 4 years ago

The scalar product of a and b is: a · b = |a||b| cosθ We can remember this formula as: “The modulus of the first vector, multiplied by the modulus of the second vector, multiplied by the cosine of the angle between them
  • 4 answers

Naman Patel 4 years ago

No

Anjan Karthi 4 years ago

No, it depends upon how we apply Sign conventions in the situation. If we take downwards as -ve and upwards as +ve, then g becomes -ve and when we take downwards as +ve and upwards as -ve, then g would be positive.

Sneha Sneha 4 years ago

Yes it would be because acceleration due Gravity is always downwards in -ve y axis

Vasudha Vasudha 4 years ago

Towards the center of the Earth, the gravity is defined to the be negative. At all points on the trajectory of a projectile, the gravitational acceleration points in the same direction, which is downwards toward the center of the Earth. So, the sign for the gravitational acceleration is always negative.
  • 1 answers
Give the common name of periplanata American
  • 5 answers

Srishti Soumya 4 years ago

Potential energy

Abhinav Maurya 4 years, 1 month ago

C

Nidhi Sharma 4 years, 1 month ago

Please tell the exact one!!

Jyoti Sharma 4 years, 1 month ago

A

Mansi Gupta 4 years, 1 month ago

C
  • 1 answers

Jyoti Sharma 4 years, 1 month ago

The current will change direction as the electron passes through the circular loop
  • 1 answers

Vasudha Vasudha 4 years ago

|A+B−→−−−|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ Complete answer: Let the two vectors be |A→| and |B→|. θ be the angle between both the vectors. Both the vectors have the same magnitude. ∴|A→|=|A→| …(1) Let the resultant have magnitude equal to vector A. Thus, the resultant is given by, |A→|=|B→|=|A+B−→−−−| …(2) The magnitude of resultant of two vectors is given by, |A+B−→−−−|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ …(3) From the equation. (2) and equation. (3) we get, |A→|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ Squaring both the sides we get, ⇒|A→|2=|A→|2+|B→|2+2|A→||B→|cosθ Substituting equation. (1) in above equation we get, |A→|2=|A→|2+|A→|2+2|A→||A→|cosθ ⇒|A→|2=2|A→|2+2|A→||A→|cosθ ⇒−|A→|2=2|A→||A→|cosθ ⇒cosθ=−12 ⇒θ=cos−1(12) ⇒θ=120° Hence, the angle between the two vectors is 120°.
  • 1 answers

Anjan Karthi 4 years ago

F = n × ma = n × mv/t. Therefore, n = F/mv = 144 × 1000 / 1200 × 40 = 3//
  • 1 answers

Anjan Karthi 4 years ago

LHS →v = [LT^-1]. RHS → √GM/R = { [M^-1L^3T^-2] [M] / [L] }^1/2 = { [L^2T^-2] }^1/2 = [LT^-1]. Therefore, LHS = RHS.
  • 0 answers
  • 1 answers

Anjan Karthi 4 years, 1 month ago

Vo = √GM/R+h = √6.67 × 10^-11 × 6 × 10^24 / 6.4 × 10^6 + 400 = 40.02 × 10^13 / 6400 × 10^3 + 400 = 40.02 × 10^13 / 400 (16001) = 40.02 × 10^13 / 6400400 = 40.02 × 10^13 / 6.4004 × 10^6 = 6.25 × 10^7 m/s. //
  • 1 answers

Anjan Karthi 4 years, 1 month ago

KE required = 1/2 × m × Ve^2 = 5000 × 2 × 6.67 × 10^-11 × 6 × 10^24 / 6.4 × 10^6 × 2 = 400.2 × 10^16 / 12.8 × 10^6 = 31.265 × 10^10 J//
  • 0 answers
  • 1 answers

Ankul Prajapati 4 years, 1 month ago

Light year
  • 1 answers

Vijay Vishwakarma 4 years, 1 month ago

All non zero no. Are SF
  • 0 answers
  • 3 answers

Aditya Dubey 4 years, 1 month ago

5 waat

Ragini Gupta 4 years, 1 month ago

Work = 600j Time = 2 min = 2×60= 120 sec Power = work/time = 600/120 = 5 j/s = 5 watt

Yogiraj Vidhyarthi 4 years, 1 month ago

5watt

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