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  • 2 answers

Neha Prasad 3 years, 9 months ago

Vector/unit vector

Mannu Dahiya 3 years, 9 months ago

Magnitude of vector=vector/unit vector
  • 1 answers

Kashish Garg 3 years, 9 months ago

Unlike solid and liquid state, molecules in gaseous state show random motion. That is the reason, gases take the shape of container and spread quickly in space. The random motion of molecules in the gaseous state is due to high kinetic energy in molecules. They have weak intermolecular interactions between them.
  • 3 answers

Mashira Rubab 3 years, 9 months ago

[MLT-2]

Varun Agarwal 3 years, 9 months ago

Okay thank you

Priyanshu Dubey 3 years, 9 months ago

It is an acceleration therefore it's dimensional formula will be equal to dimensional formula of acceleration
  • 4 answers

Tejaswini Rajput 3 years, 9 months ago

Foot , pound, time

Arisha Fatma 3 years, 9 months ago

In thus system,unit if length is foot,the unit of mass is pound and the unit of time is second

Mannu Dahiya 3 years, 9 months ago

Foot(length) Pound(mass) Second(time). This critria was followed by Britishers by which earlier we also used it after the independence of Indians from them as we were also habitual of their culture.

Anjan Karthi 3 years, 9 months ago

FPS system is the System of units and measurements which are of British origin. The three major units in this system are FEET for length (ft), POUNDS for mass (pd) and SECOND for time (sec).
  • 2 answers

Anjan Karthi 3 years, 9 months ago

g at the depth = g at surface (1-d/r) = 9.8 (1- 640/6400000 ) = 9.8 (1 - 1/10000) = 9.8 (9999/10000) = 9.799 m/s^2.//

Devil Dada 3 years, 9 months ago

34
  • 1 answers

Harmanpreet Kaur 3 years, 9 months ago

Y=FL/A∆L Given,A=5×10^-5m2,Y=2×10^11 nm^-2,L=X ,∆L=2L-L=L Putting the values in formulà F=YA∆L/L F=10^7N
  • 2 answers

Anjan Karthi 3 years, 9 months ago

L' = 2L. T' = 2 T. (where, L' and T' are the new units of length and time). Therefore, Numerical value of new g ie, g' = a = L'/T' = 2L/2T = L/T. // Therefore, g' = g.

ᥬ JaຮWaηth᭄ 3 years, 9 months ago

Sorry I don't know
  • 1 answers

Vasudha Vasudha 3 years, 9 months ago

Assuming u=0 and constant g=10ms−2 the work done by the grativational force is Wg=mgh =2×10−3×10×103=20J (b) ΔK=12mV2−0 =12×2×10−3×40×40 =1.6J From the work-energy theorem Δk=Wg+Wr where Wr is the work done by the opposing resistive force. 1.6=20+Wr Wr=−18.4J
  • 2 answers

Mannu Dahiya 3 years, 9 months ago

Unsubscribe kr dia becoz of u not liked my comment

Mannu Dahiya 3 years, 9 months ago

Ho gya Like my comment
  • 1 answers

Vasudha Vasudha 3 years, 9 months ago

The scalar product of a and b is: a · b = |a||b| cosθ We can remember this formula as: “The modulus of the first vector, multiplied by the modulus of the second vector, multiplied by the cosine of the angle between them
  • 4 answers

Naman Patel 3 years, 9 months ago

No

Anjan Karthi 3 years, 9 months ago

No, it depends upon how we apply Sign conventions in the situation. If we take downwards as -ve and upwards as +ve, then g becomes -ve and when we take downwards as +ve and upwards as -ve, then g would be positive.

Sneha Sneha 3 years, 9 months ago

Yes it would be because acceleration due Gravity is always downwards in -ve y axis

Vasudha Vasudha 3 years, 9 months ago

Towards the center of the Earth, the gravity is defined to the be negative. At all points on the trajectory of a projectile, the gravitational acceleration points in the same direction, which is downwards toward the center of the Earth. So, the sign for the gravitational acceleration is always negative.
  • 1 answers

Shivani Choudhary 3 years, 10 months ago

Give the common name of periplanata American
  • 5 answers

Srishti Soumya 3 years, 10 months ago

Potential energy

Abhinav Maurya 3 years, 10 months ago

C

Nidhi Sharma 3 years, 10 months ago

Please tell the exact one!!

Jyoti Sharma 3 years, 10 months ago

A

Mansi Gupta 3 years, 10 months ago

C
  • 1 answers

Jyoti Sharma 3 years, 10 months ago

The current will change direction as the electron passes through the circular loop
  • 1 answers

Vasudha Vasudha 3 years, 9 months ago

|A+B−→−−−|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ Complete answer: Let the two vectors be |A→| and |B→|. θ be the angle between both the vectors. Both the vectors have the same magnitude. ∴|A→|=|A→| …(1) Let the resultant have magnitude equal to vector A. Thus, the resultant is given by, |A→|=|B→|=|A+B−→−−−| …(2) The magnitude of resultant of two vectors is given by, |A+B−→−−−|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ …(3) From the equation. (2) and equation. (3) we get, |A→|=|A→|2+|B→|2+2|A→||B→|cosθ−−−−−−−−−−−−−−−−−−−−−−−√ Squaring both the sides we get, ⇒|A→|2=|A→|2+|B→|2+2|A→||B→|cosθ Substituting equation. (1) in above equation we get, |A→|2=|A→|2+|A→|2+2|A→||A→|cosθ ⇒|A→|2=2|A→|2+2|A→||A→|cosθ ⇒−|A→|2=2|A→||A→|cosθ ⇒cosθ=−12 ⇒θ=cos−1(12) ⇒θ=120° Hence, the angle between the two vectors is 120°.
  • 1 answers

Anjan Karthi 3 years, 9 months ago

F = n × ma = n × mv/t. Therefore, n = F/mv = 144 × 1000 / 1200 × 40 = 3//
  • 1 answers

Anjan Karthi 3 years, 9 months ago

LHS →v = [LT^-1]. RHS → √GM/R = { [M^-1L^3T^-2] [M] / [L] }^1/2 = { [L^2T^-2] }^1/2 = [LT^-1]. Therefore, LHS = RHS.
  • 0 answers
  • 1 answers

Anjan Karthi 3 years, 10 months ago

Vo = √GM/R+h = √6.67 × 10^-11 × 6 × 10^24 / 6.4 × 10^6 + 400 = 40.02 × 10^13 / 6400 × 10^3 + 400 = 40.02 × 10^13 / 400 (16001) = 40.02 × 10^13 / 6400400 = 40.02 × 10^13 / 6.4004 × 10^6 = 6.25 × 10^7 m/s. //
  • 1 answers

Anjan Karthi 3 years, 10 months ago

KE required = 1/2 × m × Ve^2 = 5000 × 2 × 6.67 × 10^-11 × 6 × 10^24 / 6.4 × 10^6 × 2 = 400.2 × 10^16 / 12.8 × 10^6 = 31.265 × 10^10 J//
  • 0 answers
  • 1 answers

Ankul Prajapati 3 years, 10 months ago

Light year
  • 1 answers

Vijay Vishwakarma 3 years, 10 months ago

All non zero no. Are SF
  • 0 answers
  • 3 answers

Aditya Dubey 3 years, 10 months ago

5 waat

Ragini Gupta 3 years, 10 months ago

Work = 600j Time = 2 min = 2×60= 120 sec Power = work/time = 600/120 = 5 j/s = 5 watt

Yogiraj Vidhyarthi 3 years, 10 months ago

5watt

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