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Dεερακ Ȿιηɠꜧ 5 years, 1 month ago
= \left(\dfrac{16}{0} \right)
= \left(\dfrac{3x^2 +2x + 1}{(x+1)(x-1)} \right)
= I don't know what to do next ???
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Vatsal Lad 5 years, 1 month ago
0Thank You