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  • 1 answers

Ameen Hussain 4 years, 5 months ago

31'=31/60 1*31/60*π/180
  • 1 answers

Gaurav Seth 4 years, 5 months ago

Let r cos θ = –1 and r sin θ = 1

On squaring and adding, we obtain r2 (cos2 θ + sin2 θ) = 1+ 1

⇒ r2 (cos2 θ + sinθ) = 2

⇒ r2 = 2       [cosθ + sin2 θ = 1]

This is the required polar form.

  • 1 answers

Rohit Kumar 4 years, 5 months ago

Solve karna ka bad kya aayega
  • 3 answers

Pk ⚔️ 4 years, 5 months ago

?

Aadya Singh 4 years, 5 months ago

5t2-10t-15
=5(t2- 2t-3 )
=5 (t2 - 3t + t - 3)
=5 [t(t-3) +1(t-3)]
= 5 (t+1) (t-3) ?

Aadya Singh 4 years, 5 months ago

(t+1) (t-3)
  • 3 answers

Aadya Singh 4 years, 5 months ago

1 radian = (180/π )°
3 radian = 180×3/π = (540/π) °

Athmapriya P 4 years, 5 months ago

3π×180/π=540°

Aadya Singh 4 years, 5 months ago

540/π
  • 1 answers

Gaurav Seth 4 years, 5 months ago

Prove the following identites

sec4x - sec2x = tan4x + tan2x

SOLUTION

LHS = sec4x - sec2x

= sec2x(sec2x - 1)

= (tan2x + 1)(tan2x) (∵ sec2x - tan2x = 1)

= tan4x + tan2x

=RHS

Hence proved.

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  • 4 answers

Sehaj Gamer? 4 years, 5 months ago

Go go cbse.nic.in or any cbse website three lines are show at the top bottom click on it and then list appears select rd sharma sol then it gives answers of the entire book Either you can download the app doubtnut scan question and it will send you videos of the question and if u have any query then u can solve it after watching it ??

Ruhi Rao 4 years, 5 months ago

Hii, you can also get the rd Sharma solution of NCERT solutions...

Aarav Ninama 4 years, 5 months ago

1. 5 question 4

Shruti Padhan 4 years, 5 months ago

byju's
  • 0 answers
  • 2 answers

Nishant Kumar 4 years, 5 months ago

-seca

Dεερακ Ȿιηɠꜧ 4 years, 5 months ago

Cos (90-a)
  • 3 answers

Saloni Kashyap ? 4 years, 5 months ago

Vinay Kumar..tum is app pr hi bhj do baki sb ki bhi help ho jayegi .. ?

Monty Dalal 4 years, 5 months ago

Msg me on insta - dalalsahab.01 my id i will provide you syllabus

Saloni Kashyap ? 4 years, 5 months ago

@Royal.. okk
  • 3 answers

?? 4 years, 5 months ago

thanks royal?

?? 4 years, 5 months ago

Oh sry Sadul siso?...Mene first time Sadul name suna...I thought boy name hoga ??

?? 4 years, 5 months ago

yes bro...of course!?✌
  • 1 answers

?? 4 years, 5 months ago

Power set of A, P(A) = {∅, {1}, {2},{3},{1,2},{2,3},{1,3},{1,2,3}}
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  • 2 answers

Sehaj Gamer? 4 years, 5 months ago

Padho kuch sone se kuch nhi hoga

?Tamanna ?? 4 years, 5 months ago

Ji gautam Kumar hm apki puri hlp krege??????
  • 0 answers
  • 3 answers

Saloni Kashyap ? 4 years, 5 months ago

@S.A.l.O.N.I.. yes 11th class

Saloni ? 4 years, 5 months ago

Abhijeet..11th class

Abhijeet Kumar Maurya 4 years, 5 months ago

For which class
  • 4 answers

J Suranjana 4 years, 5 months ago

Hi friend

Shashwat Singh 4 years, 5 months ago

???... Heyy!! How are uhh?

Har Har Mahadev 🙏 4 years, 5 months ago

It's looking like ice cream ?

Har Har Mahadev 🙏 4 years, 5 months ago

Hi
  • 4 answers

Har Har Mahadev 🙏 4 years, 5 months ago

Mental ability of thinking high....

Shashwat Singh 4 years, 5 months ago

Hey Deepak... How did u do it? ?

Manik Jamatia 4 years, 5 months ago

Math is continue process

Dishu Hooda 4 years, 5 months ago

MATHS = Mentaly Affected Teachers Harrassing StudentsMATHS = Meri Atma Tujhe Hamesa Satayegi
  • 1 answers

Tanisha Chawla 4 years, 5 months ago

Yes
  • 0 answers
  • 0 answers
  • 4 answers

Shashwat Singh 4 years, 5 months ago

Dishu Hooda 4 years, 5 months ago

It is output of the function .

Shashwat Singh 4 years, 5 months ago

Thanks ?

Athmapriya P 4 years, 5 months ago

The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range. Domain: all x-values that are to be used (independent values). Range: all y-values that are used (dependent values).
  • 0 answers
  • 1 answers

Gaurav Seth 4 years, 5 months ago

Left Hand Side = 

By applying the following identity of,



And, for the denominator's side, applying this identity,



Now,





Divide the following numbers  therefore,



Now, cancelling out the common factor of:  and dividing the numbers: ,

Therefore, by the following trigonometric identity: 

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