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  • 1 answers

Sehaj Gamer? 5 years, 1 month ago

?‍♂️?‍♀️?‍♀️ pls complete your question before sending the question
  • 1 answers

Kunal Jadhav 5 years, 1 month ago

In mathematics, the trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths. They are widely used in all sciences that are related to geometry, such as navigation, solid mechanics, celestial mechanics, geodesy, and many others.
  • 2 answers

Sehaj Gamer? 5 years, 1 month ago

1088 is right answer ? this question start from 5th class u don't know how to solve this problem

Gaurav Seth 5 years, 1 month ago

P = Rs. 800 [Amount deposited]

T = 3 years

R = 12%

 

S.I. = PRT/100

S.I. = 800 × 3 × 12/100

S.I. = 8 × 3 × 12

S.I. = 288

 

Amount recieved = Rs. 288 + Rs. 800 {Principal + Simple Interest}

Rs. 1088

  • 2 answers

Nitish Kumar 5 years, 1 month ago

Minus root 1

Shubham Parashar 5 years, 1 month ago

Root -1
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  • 0 answers
  • 2 answers

Sehaj Gamer? 5 years, 1 month ago

Use the formulas Sn=n/2(a+l)

Yogita Ingle 5 years, 1 month ago

The series of odd integers from 1 to 2001 is,1,3,5,7..............,2001

a=1

d=3−1=2

l=2001

an​ = a+(n−1)d

2001=1+(n−1)2

2000=2(n−1)

∴n=1001

Sn​=n/2 ​[a+l]

=1001/2 ​[1+2001]

=10,02,001

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  • 1 answers

Ameen Hussain 5 years, 1 month ago

31'=31/60 1*31/60*π/180
  • 1 answers

Gaurav Seth 5 years, 1 month ago

Let r cos θ = –1 and r sin θ = 1

On squaring and adding, we obtain r2 (cos2 θ + sin2 θ) = 1+ 1

⇒ r2 (cos2 θ + sinθ) = 2

⇒ r2 = 2       [cosθ + sin2 θ = 1]

This is the required polar form.

  • 1 answers

Rohit Kumar 5 years, 1 month ago

Solve karna ka bad kya aayega
  • 3 answers

Pk ⚔️ 5 years, 1 month ago

?

Aadya Singh 5 years, 1 month ago

5t2-10t-15
=5(t2- 2t-3 )
=5 (t2 - 3t + t - 3)
=5 [t(t-3) +1(t-3)]
= 5 (t+1) (t-3) ?

Aadya Singh 5 years, 1 month ago

(t+1) (t-3)
  • 3 answers

Aadya Singh 5 years, 1 month ago

1 radian = (180/π )°
3 radian = 180×3/π = (540/π) °

Athmapriya P 5 years, 1 month ago

3π×180/π=540°

Aadya Singh 5 years, 1 month ago

540/π
  • 1 answers

Gaurav Seth 5 years, 1 month ago

Prove the following identites

sec4x - sec2x = tan4x + tan2x

SOLUTION

LHS = sec4x - sec2x

= sec2x(sec2x - 1)

= (tan2x + 1)(tan2x) (∵ sec2x - tan2x = 1)

= tan4x + tan2x

=RHS

Hence proved.

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  • 4 answers

Sehaj Gamer? 5 years, 1 month ago

Go go cbse.nic.in or any cbse website three lines are show at the top bottom click on it and then list appears select rd sharma sol then it gives answers of the entire book Either you can download the app doubtnut scan question and it will send you videos of the question and if u have any query then u can solve it after watching it ??

Ruhi Rao 5 years, 1 month ago

Hii, you can also get the rd Sharma solution of NCERT solutions...

Aarav Ninama 5 years, 1 month ago

1. 5 question 4

Shruti Padhan 5 years, 1 month ago

byju's
  • 0 answers
  • 2 answers

Nishant Kumar 5 years, 1 month ago

-seca

Dεερακ Ȿιηɠꜧ 5 years, 1 month ago

Cos (90-a)
  • 3 answers

Saloni Kashyap ? 5 years, 1 month ago

Vinay Kumar..tum is app pr hi bhj do baki sb ki bhi help ho jayegi .. ?

Monty Dalal 5 years, 1 month ago

Msg me on insta - dalalsahab.01 my id i will provide you syllabus

Saloni Kashyap ? 5 years, 1 month ago

@Royal.. okk
  • 3 answers

?? 5 years, 1 month ago

thanks royal?

?? 5 years, 1 month ago

Oh sry Sadul siso?...Mene first time Sadul name suna...I thought boy name hoga ??

?? 5 years, 1 month ago

yes bro...of course!?✌

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