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Ask QuestionPosted by Arpita Chakravarty 5 years ago
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Posted by A@Kash Kumar 5 years ago
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Jaya Jeevan 5 years ago
Gaurav Seth 5 years ago
sin 100° + cos 100°
= sin100° + cos(90°+10°)
[cos 10° becomes sin 10°]
= sin100° + sin 10°
by the formula,
sin C + sin D = 2cos sin
= 2cos sin
= 2cos sin
= 2cos55° + sin45°
= 2cos55° + 1/√2
=√2.√2 cos55° .1/√2
= √2cos55°
Posted by A@Kash Kumar 5 years ago
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Gaurav Seth 5 years ago
A n s w e r : Maximum value is 1/2 and minimum value is -1/2.
EXPLANATION:
sin cos x = 1/2(2 sin x cos x)
= sin 2x/2
Hence, the Maximum value is 1/2 and minimum value is -1/2.
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Smita Mohapatra 5 years ago
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? S. S. ? 5 years ago
? S. S. ? 5 years ago
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Krishnapriya Kumaran 4 years, 9 months ago
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Gaurav Seth 5 years ago
The answer is 26 [most probably]
First find x
3[x]+2 = 2[x+4] [given]
3x + 2 = 2x + 8
3x - 2x = 8 - 2
therefore x = 6
Now, y=3[x]+2 or y = 2[x+4]
Putting the value of x ,
we get y = 20
now x+y = 20 + 6
= 26
Posted by Sanjana Mishra Ankleshwar,Bharuch 5 years ago
- 1 answers
Gaurav Seth 5 years ago
We have to show that P(A ∩ B) = P(A) ∩ P(B)
LHS:
Let x ∈ P(A ∩ B)
=> x ∈ (A ∩ B)
=> x ∈ A and x ∈ B .............1
RHS:
x ∈ P(A) ∩ P(B)
=> x ∈ A and x ∈ B ............2
From equation 1 and 2, we get
P(A ∩ B) = P(A) ∩ P(B)
Hence proved.
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? S. S. ? 5 years ago
Posted by Parmeshwar Rathore Rathore 5 years ago
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Gaurav Seth 5 years ago
If u equals to {1, 2, 3, 4,.....,10} is the universal set for the two sets a={2,3,4,5} and b={1,2,3,4,5,6} then verify that (a u b)" equals to a" n b"
Given
a = { 2, 3, 4, 5 } and b = { 1, 2, 3, 4, 5, 6 }
Then
a ∪ b = [ everything in one or the other ]
= { 1, 2, 3, 4, 5, 6 }
so
( a ∪ b )' = [ the complement, so everything in u that's not in a∪b ]
= { 7, 8, 9, 10 }. ...(*)
Also
a' = { 1, 6, 7, 8, 9, 10 } and b' = { 7, 8, 9, 10 }
so
a' ∩ b' = [ those elements in both a' and b' ]
= { 7, 8, 9, 10 }. ...(**)
The sets at (*) and (**) are the same, verifying the relationship
( a ∪ b )' = a' ∩ b'.
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Siddarth Asati Asati 5 years ago
Tec Om 5 years ago
B=(6,7)
X is the universal set for A and B { X =(1,2,3,4...10)} B'={1,2,3,4,5,8,9,10}
from LHS side
{1,2,5} intersection{1,2,3,4,5,8,9,10}
{1,2,5} (which is equal to A)
Hence it is proved
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Gaurav Seth 5 years ago
QUESTION
Write the relation R = {(x, x3): x is a prime number less than 10} in roster form.
SOLUTION
R = {(x, x3): x is a prime number less than 10}
The prime numbers less than 10 are 2, 3, 5, and 7.
∴R = {(2, 8), (3, 27), (5, 125), (7, 343)}
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