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Posted by Deachan Chuskit 5 years ago
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Gaurav Seth 5 years ago
The graphical representation of 2x+ y= 6 is given in the figure below.
This line divides the xy-plane in two half planes, I and II.
Select a point (not on the line), which lies in one of the half planes, to determine whether the point satisfies the given inequality or not.
We select the point as (0, 0).
It is observed that,
2(0) + 0 ≥ 6 or 0 ≥ 6, which is false.
Therefore, half plane I is not the solution region of the given inequality.
Also, it is evident that any point on the line satisfies the given inequality.
Thus, the solution region of the given inequality is the shaded half plane II including the points on the line.
This can be represented as follows.

Posted by Tarun Kumar 5 years ago
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Posted by Ꭰʀ_Ꭰɪꜱꮢᴇꜱᴘᴄᴛ . 5 years ago
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Gaurav Seth 5 years ago
Let A = (5,– 1,1)
B = (7,– 4, 7)
C = (1, – 6, 10)
D = (– 1, – 3, 4)
Then the position vectors of A,B,C,D are
∴ ABCD forms a Rhombus.
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Posted by Hrushikesh Panugrahi 5 years ago
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? S. S. ? 5 years ago
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Khushank Singh 5 years ago
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Yogita Ingle 5 years ago
5×2+0×5+8×0+9+8
= 10+0×5+8×0+9+8
= 10 +8×0+9 + 8
= 10 + 9 + 8
= 19 + 8
= 27
Posted by Aditya Aditya 5 years ago
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Posted by Jaya Jeevan 5 years ago
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Gaurav Seth 5 years ago
7, 77, 777, 7777 ….to n terms.
Sn=7+77+777+7777+……+to n terms
introducing 9
= (7/9) [9+99+999+……+ to n terms]
= (7/9) [(10-1) + (100-1) + (1000-1) +……...+ to n term]
= (7/9) [10+100+1000+……... n terms – (1+1+1+1+…… n terms)
= (7/9) [10+100+1000+………n terms –n]
Here a=10, r=10
= (7/9) [10(10n-1)/ (9) - n]

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Har Har Mahadev 🙏 5 years ago
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