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  • 1 answers

Gaurav Seth 5 years ago

The graphical representation of 2x+ y= 6 is given in the figure below.
This line divides the xy-plane in two half planes, I and II.
Select a point (not on the line), which lies in one of the half planes, to determine whether the point satisfies the given inequality or not.
We select the point as (0, 0).
It is observed that,
2(0) + 0 ≥ 6 or 0 ≥ 6, which is false.
Therefore, half plane I is not the solution region of the given inequality.
Also, it is evident that any point on the line satisfies the given inequality.
Thus, the solution region of the given inequality is the shaded half plane II including the points on the line.
This can be represented as follows.

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  • 2 answers

Ff Sedn 5 years ago

5π/12 radian

Ff Sedn 5 years ago

75°=75xπ/180 = 5π/12 Hence 75°=5π/12
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Tec Om 5 years ago

8-9i
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5 years ago

That is not true and satisfactory for me . Even you know the change...
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Saloni ? 5 years ago

Thanks?....

Gaurav Seth 5 years ago

Let A = (5,– 1,1) 

B = (7,– 4, 7) 

C = (1, – 6, 10) 

D = (– 1, – 3, 4) 

Then the position vectors of A,B,C,D are

∴ ABCD forms a Rhombus.

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? S. S. ? 5 years ago

180°+90°=270°...I hope you are asking for converting it into degree....
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Khushank Singh 5 years ago

Sin theta/cosec theta+ cos theta/ sec theta main Cosec ko1/sin aur sec ko 1/cos main convert karenge Phir sin/1/sin ho jayega +cos/1/cos ho jaega Phir sin×sin+cos×cos then Sin^2theta+cos^2theta=1 H.P
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Khushank Singh 5 years ago

Great

Saloni ? 5 years ago

See ncert book ?....
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Tec Om 5 years ago

Just use the quadratic formula -b+-√b2-4ac/2a
  • 3 answers

Irshad Ali 5 years ago

=10+0+0+17 =10+17 =27

Sudipta Munda 5 years ago

0

Yogita Ingle 5 years ago

5×2+0×5+8×0+9+8

= 10+0×5+8×0+9+8

= 10 +8×0+9 + 8

= 10 + 9 + 8

= 19 + 8

= 27

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Gaurav Seth 5 years ago

7, 77, 777, 7777 ….to n terms.         
Sn=7+77+777+7777+……+to n terms      
introducing 9       
  = (7/9) [9+99+999+……+ to n terms]              
= (7/9) [(10-1) + (100-1) + (1000-1) +……...+ to n term]               
= (7/9) [10+100+1000+……... n terms – (1+1+1+1+…… n terms)             
  = (7/9) [10+100+1000+………n terms –n]     
 Here      a=10, r=10             
 = (7/9) [10(10n-1)/ (9) - n]

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