Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Sanjana Mishra Ankleshwar,Bharuch 4 years, 5 months ago
- 1 answers
Posted by Aadya Singh 4 years, 5 months ago
- 1 answers
Posted by Aadya Singh 4 years, 5 months ago
- 0 answers
Posted by Aadya Singh 4 years, 5 months ago
- 1 answers
Posted by Santosh Hial 4 years, 5 months ago
- 5 answers
? S. S. ? 4 years, 5 months ago
Posted by Parmeshwar Rathore Rathore 4 years, 5 months ago
- 1 answers
Gaurav Seth 4 years, 5 months ago
If u equals to {1, 2, 3, 4,.....,10} is the universal set for the two sets a={2,3,4,5} and b={1,2,3,4,5,6} then verify that (a u b)" equals to a" n b"
Given
a = { 2, 3, 4, 5 } and b = { 1, 2, 3, 4, 5, 6 }
Then
a ∪ b = [ everything in one or the other ]
= { 1, 2, 3, 4, 5, 6 }
so
( a ∪ b )' = [ the complement, so everything in u that's not in a∪b ]
= { 7, 8, 9, 10 }. ...(*)
Also
a' = { 1, 6, 7, 8, 9, 10 } and b' = { 7, 8, 9, 10 }
so
a' ∩ b' = [ those elements in both a' and b' ]
= { 7, 8, 9, 10 }. ...(**)
The sets at (*) and (**) are the same, verifying the relationship
( a ∪ b )' = a' ∩ b'.
Posted by Swarna Sri Rajini 4 years, 5 months ago
- 2 answers
Smita Mohapatra 4 years, 5 months ago
Posted by Aadya Singh 4 years, 5 months ago
- 1 answers
Posted by Jyoti Pal 4 years, 5 months ago
- 3 answers
Posted by Ff Sedn 4 years, 5 months ago
- 1 answers
Posted by ⠀ 4 years, 5 months ago
- 4 answers
Posted by Pooja Singh 4 years, 5 months ago
- 2 answers
Siddarth Asati Asati 4 years, 5 months ago
Tec Om 4 years, 5 months ago
B=(6,7)
X is the universal set for A and B { X =(1,2,3,4...10)} B'={1,2,3,4,5,8,9,10}
from LHS side
{1,2,5} intersection{1,2,3,4,5,8,9,10}
{1,2,5} (which is equal to A)
Hence it is proved
Posted by Apoorva Reddy Gagginepalli 4 years, 5 months ago
- 1 answers
Posted by Vansh Sama 4 years, 5 months ago
- 1 answers
Gaurav Seth 4 years, 5 months ago
Q : Find the equation of the set of points P, the sum of whose distances from A (4, 0, 0) and B (-4, 0, 0) is equal to 10?
Answer:
Posted by Aadya Singh 4 years, 5 months ago
- 1 answers
Posted by Aadya Singh 4 years, 5 months ago
- 1 answers
Posted by Raj Raj 4 years, 5 months ago
- 2 answers
Posted by ⠀ 4 years, 5 months ago
- 3 answers
Posted by Swati Singh 4 years, 5 months ago
- 2 answers
अविरल श्रीवास्तव 4 years, 5 months ago
Posted by ⠀ 4 years, 5 months ago
- 0 answers
Posted by ⠀ 4 years, 5 months ago
- 0 answers
Posted by ⠀ 4 years, 5 months ago
- 2 answers
Posted by Shweta Vishwakarma 4 years, 5 months ago
- 0 answers
Posted by Aadya Singh 4 years, 5 months ago
- 0 answers
Posted by Varunpal Singh Rathore 4 years, 5 months ago
- 0 answers
Posted by Tanu Saini 4 years, 5 months ago
- 2 answers
Gaurav Seth 4 years, 5 months ago
LHS = sin²(6x) - sin²(4x)
Use the formula,
(a² - b²) = (a - b)(a + b)
= (sin6x -sin4x)(sin6x +sin4x)
Now,
Use the formula,
sinC + sinD = 2sin(C+D)/2.cos(C-D)/2
sinC - sinD = 2cos(C+D)/2.sin(C-D)/2
={2cos(6x+4x)/2.sin(6x-4x)/2}{2sin(6x+4x)/2.cos(6x-4x)/2}
={2cos5x.sinx}{2sin5x.cosx}
={2sin5x.cos5x}{2sinx.cosx}
Use the formula,
sin2A = 2sinA.cosA
= sin2(5x).sin2(x)
= sin10x.sin2x =RHS
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 4 years, 5 months ago
We have to show that P(A ∩ B) = P(A) ∩ P(B)
LHS:
Let x ∈ P(A ∩ B)
=> x ∈ (A ∩ B)
=> x ∈ A and x ∈ B .............1
RHS:
x ∈ P(A) ∩ P(B)
=> x ∈ A and x ∈ B ............2
From equation 1 and 2, we get
P(A ∩ B) = P(A) ∩ P(B)
Hence proved.
1Thank You