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Chandrashekhar Wankhede 7 years, 10 months ago

Divide numerator and denominator of given function by (x-2) . Use standard limit for numerator as well as denominator , Lim x-->a ( X power n - a power n) /(x-a) = n * (a power (n-1))
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Piyush Singh 7 years, 10 months ago

Tan 2/x-pie/2 =π/2
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Chandrashekhar Wankhede 7 years, 10 months ago

Pl post questions..
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Piyush Singh 7 years, 10 months ago

Sin/cos (πcosQ)=cos/sin(πsinQ)

Chandrashekhar Wankhede 7 years, 10 months ago

cos (pi-pi/4)= cos (135)= - cos (45) = - (1/root 2)
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Chandrashekhar Wankhede 7 years, 10 months ago

ncr= npr / r! 120 = 720 / r! r! = 720 / 120 = 6 = 3*2*1 = 3! r = 3
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Chirag Bhardwaj 7 years, 10 months ago

2sinA+B/2cosA-B/2
A+b
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Chandrashekhar Wankhede 7 years, 10 months ago

General eqn of circle is sqr(x) + sqr(y) + 2gx + 2fy + c = 0 , center = ( -g , - f) , Find the center of both given circles by comparing their eqn with general eqn. Before comparing second eqn, modify second eqn by dividing it by 2. Find the distance between both centers. This distance will be radius of required circle. Center of required circle will be same as center of second equation. Find equation of required circle by using sqr(X - x1) + sqr (Y - y1) = Sqr (radius), where (x1, y1) is center of second given circle..
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Chandrashekhar Wankhede 7 years, 10 months ago

There are will be two lines passing through (2,-2) and making angle of 45 degree with given line x - y +5 = 0 forming diagram of isosceles triangle. slope of given line = tan theta = 1 , that means it is making an angle of 45 degree with positive X axis in anticlockwise direction. The first line passing through (2,-2) which is making 45 with given line will be parallel to X axis and it's equation will be Y = - 2. Other line will be parallel to Y axis and it's equation will be X = 2

Chirag Bhardwaj 7 years, 10 months ago

x-y=4
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Mansi Gupta 7 years, 10 months ago

(X+1)^2=(x+1)(x+1)=x=-1,-1
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Divyanshu Gupta 7 years, 10 months ago

r-2+2r-2 =34 r=38/3 r=12.6
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Chandrashekhar Wankhede 7 years, 10 months ago

Use Venn diagram or consider some set values for a, b, c
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Chandrashekhar Wankhede 7 years, 10 months ago

nth term of given series = an = square of (2n), Therefore, sn= a1+a2+a3+......+an = 4(sqr(1)+sqr(2)+sqr(3)+......sqr(n)) Using identity , sum of square of n natural numbers = n(n+1)(2n+1)/6 Sn= 4n(n+1)(2n+1)/6
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Chandrashekhar Wankhede 7 years, 10 months ago

Nth term of this series = an = n(n+1)(n+2)/6 = (1/6) *(cube(n)+ 3*sqr(n)+ 2n). Now sum of all n terms = sum of cubes of first n natural numbers + 3* ( sum of Squares of first n natural numbers + 2 ( sum of first n natural numbers).. Use standard identities of sum of first n natural numbers, sum of squares of first n natural numbers, sum of cubes of first n natural numbers..

Ishjoyt Alag 7 years, 10 months ago

you can find answer but you have to know n terms formula is n ( n +1)÷2

Cool K 7 years, 10 months ago

See the ques. Is wronge it is not a A.P. and not an G.P.
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