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find the equation of the circle …

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find the equation of the circle which passes through the centre of the circle x square plus y square + 8 x + 10 Y - 7 equal to zero and is concentric with the circle 2 X square + 2 Y square minus 8 x minus 12 minus 9 equal to zero

    • Posted by Vaibhav Malhotra 6 years, 2 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Chandrashekhar Wankhede 6 years, 2 months ago

    General eqn of circle is sqr(x) + sqr(y) + 2gx + 2fy + c = 0 , center = ( -g , - f) , Find the center of both given circles by comparing their eqn with general eqn. Before comparing second eqn, modify second eqn by dividing it by 2. Find the distance between both centers. This distance will be radius of required circle. Center of required circle will be same as center of second equation. Find equation of required circle by using sqr(X - x1) + sqr (Y - y1) = Sqr (radius), where (x1, y1) is center of second given circle..

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