No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers
Ncert ,page no. 166. Ex -4. I think you understsnd .
  • 0 answers
  • 7 answers
R d sharma questions are good. But not solutions i would say.i use to solve exercise example and ncert exemplar questions which are marked in it. It is realy a good book and it is not possible to do whole book for me.... i am using rd sharma from 9

Harsh Mishra 7 years ago

Yeah!!! I have also heard alot about R.D. Sharma even I had used it in 9th and 10th. But!!! In 11th , I never bothered to buy that Ramayana size book ?..... ? ???????????

Ankit Singh 7 years ago

Good

Sunila Sharma 7 years ago

Kaafi jayada question de Rekha ha, aur bhut kuch outside the syllabus me se bhi ha, ncert ke bhi kaafi question cover kare hua ha, nice book but insane to solve

Yakshi ? 7 years ago

Of course......mainey toh book ka size dekhkar e reject kr diya usey........suna bhot hai uskey baarey mein......lekin......kabhi try nai kiya.....mujhey ncert aur apney teacher ka padhaya hua e sufficient lagta hai.....???

Aman Kumar 7 years ago

Initially,.. quantity of question dekh k hi hallat kharab but one day I made my mind and solved more than 50-60 questions..after that I really like it..??

Ankit Singh 7 years ago

Nice experience after solving rd Sharma
  • 1 answers

Deepak Singh 7 years ago

First value of a=7,16/25=1+b×b/49,b×b/49=-9/25,b=-21/5,hence the equation is x²/49-25y²/441=-1
  • 2 answers

Yogita Ingle 7 years ago

(23 + 13) - 0 + 333 (-789 + 799)
= (23 + 13) - 0 + 333 (10)
= 36 + 3330
= 3366

Abdul Kalam 7 years ago

-297
  • 2 answers

Dev ..... 7 years ago

(5,infinity)

Karan Yadav 7 years ago

Find it domain
  • 1 answers
Let three no be a/r,a,ar Then, a/r+a+ar=63. (I) And a/r×a=3/4×ar a/r=3/4×r a=3/4×r^2. (II) Putting (II) in (I) we get 3/4×r+3/4×r^2+3/4×r^3=63 r^3+r^2+r=84 r^3+r^2+r-84=0 On solving this equation we get r=4 and a=12 The required number is 3,12,48
  • 1 answers

Amit Kumar 7 years ago

Maths for all
  • 3 answers

Ankit Singh 7 years ago

Great answer

Yakshi ? 7 years ago

Wait wait wait......i did not tell u something.....that is.......let (-1-1-1-1.....)=n and as u know sum of infinity.......as 10+10^2+10^3.......= [{10^(n+1) - 10} /9] -n........so.......ur answer will be......5/9[ {10^(n+1) - 10 -9n}/9]

Yakshi ? 7 years ago

In first part......1) 5+55+555........u can take 5 as common then it will be = 5( 1+11+111....) = now....multiply and divide it by 9.....then u will get....(5/9){9+99+999.......} .....u can write 9 as (10-1) and 99 as (100-1) and so on......so .....it will be......(5/9){ 10-1 + 100-1 + 1000 -1............}......in this case there will be two parts...... in first one u will find sum of all the " 1" in this....and in second one u will write 100 as 10^2 ......1000 as 10^3...and so on then find sum of (10+10^2+10^3.......).......then u will get......
  • 3 answers

Neha Singh 7 years ago

It's answer is pi by 180

Neha Singh 7 years ago

yes

Neha Gurjar 7 years ago

If limit x tends to 0 the
  • 7 answers

Amit Kumar 7 years ago

Very ezee

Yakshi ? 7 years ago

Neha i m serious ........when u will get solution plz....try to tell me this question is looking tricky......????

Neha Singh 7 years ago

Please apply BODMAS rule

Ankit Singh 7 years ago

??????

Ankit Singh 7 years ago

Yes u are right yakshi

Yakshi ? 7 years ago

Sorry i think this is out of our syllabus and don't know the reason.....???

Yakshi ? 7 years ago

???
  • 1 answers

Aditya Sharma 7 years ago

√9–x² Domain: 9–x² > 0 (3+x)(3–x)>0 Domain belongs to [–3,+3] RANGE: –3<x<+3 [0,3]
  • 1 answers

Aditya Sharma 7 years ago

1/365 is the very correct answer.............. For knowing the birthday of both the friends on same day, we need to multiply the probabilities, i.e., (365/365)×(1/365)
  • 2 answers

Nikhil Tyagi 7 years ago

Grt but x pwr 5

Gaurav Seth 7 years ago

Answer:

dydx=cos(x5)⋅5x4

Explanation:

y=sinx5

Using the chain rule:

If y=y(u) and u=u(x) then, dydx=(dydu)⋅(dudx)

y=sinu
dydx=cosu

u=x5
dudx=5x4

Therefore,
dydx=(dydu)⋅(dudx)
dydx=cosu⋅5x4

Substitute u back in and rearrange:
dydx=cos(x5)⋅5x4

  • 1 answers

Aditya Sharma 7 years ago

= lim x→–2 (x+2).(x+2)²/(x+2)(x–2) = lim x→–2 (x+2)²/(x–2) =(–2+2)²/(–2–2) =0/–4 =0

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App