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Ask QuestionPosted by Mohd Zaid 7 years ago
- 0 answers
Posted by Nancy Rajput 7 years ago
- 3 answers
Gaurav Seth 7 years ago
a) The number of ways in which at least two of them are in the wrong envelopes
</header>


=15+40+135+264+265
=719
b) The number of ways in which all letters be placed in the wrong envelopes
= 6! (
)
=720
=720(
)
=360-120+30-6+1
=265
Posted by Amit Kandari 7 years ago
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Posted by Akina Chishi♥ 7 years ago
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Yakshi ? 7 years ago
Posted by Vanshika Dhama 7 years ago
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Posted by Vanshika Dhama 7 years ago
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Posted by Gulshan Raj 7 years ago
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Yakshi ? 7 years ago
Yakshi ? 7 years ago
Posted by Sapna Nag 7 years ago
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Posted by Aman Kumar Singh 7 years ago
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Posted by Priyesh Oraon 7 years ago
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Ram Kushwah 7 years ago
18 rev =18×2π=36π rad in 60 sec
So in 1 sec angle moved
=36π/60=3/5π radians
Posted by Varshini Selva Murugan 7 years ago
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Posted by Raju Bhai 7 years ago
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Posted by Nitesh Jha 7 years ago
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Priya Dharshini ? 7 years ago
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Aryan Garg 7 years ago
Posted by Anjali Jangra 7 years ago
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Posted by Harsh Kumar 7 years ago
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Posted by Ankit Singh 7 years ago
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Priya Dharshini ? 7 years ago
Posted by Annu Chaudhary 7 years ago
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Posted by Himanshu Maheshwari 7 years ago
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Posted by Deepak Kumar 7 years ago
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Posted by Anuj Kumar 7 years ago
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Ankit Singh 7 years ago
Yakshi ? 7 years ago
Posted by Being Happy.. 7 years ago
- 2 answers
Gaurav Seth 7 years ago
Let Ф = π/8
2Ф = π/4
tan 2Ф = 1 = 2 tan Ф / [ 1 - tan² Ф ]
1 - tan² Ф = 2 tan Ф
tan² Ф + 2 tan Ф - 1 = 0
tan Ф = 1/2 [ -2 +- √(4 +4) ] = -1 +- √2
tan π/8 is > 0 So, tan π/8 = √2 - 1
Posted by Gauri Singhal 7 years ago
- 4 answers
Dev ..... 7 years ago
Harsh Mishra 7 years ago
Posted by Sidharth Kt 5 years, 9 months ago
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