No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 5 answers

Dipesh Goyal 7 years, 3 months ago

I nk u must get fail

Afia Chauhan 7 years, 3 months ago

all the bst for your exams

Pratyush Krishnan 7 years, 3 months ago

Nannayi score cheyyu!!( All the best!!) ?

Krishna Priya Vijayan 7 years, 3 months ago

Tomorrow I have unit test

Radhika :) Mishra:} 7 years, 3 months ago

Yeah?????
  • 4 answers

Mayank Chhabra 7 years, 3 months ago

Its from28th

Rakesh Pragna 7 years, 3 months ago

No it is near

Raunak _ Pandey ?? 7 years, 3 months ago

Nupe

Manasvi Kakuste 7 years, 3 months ago

No ..... Not yet .... Yours ?
  • 1 answers

Sia ? 6 years, 6 months ago

Let a be the first term and d be the common difference of the given AP. Then, in general the mth and nth terms can be written as 
Tm = a + (m - 1) d and Tn = a + (n - 1)d respectively.
According to the question,we are given that,

 (m.Tm) = (n.Tn)

{tex}\Rightarrow{/tex} m.{a + (m - 1)d} = n.{a + (n - 1)d}
{tex}\Rightarrow{/tex} a.(m - n) + {(m2 - n2) - (m - n)} . d = 0
{tex}\Rightarrow{/tex} (m - n).{a + (m + n - 1)}d.
{tex}\Rightarrow{/tex} (m - n).Tm+n = 0
{tex}\Rightarrow{/tex}Tm+n = 0 [{tex}\because{/tex} (m-n){tex}\neq{/tex}0].
Hence, the (m + n)th term is zero.

  • 3 answers

Raunak _ Pandey ?? 7 years, 3 months ago

Hi

Komal Tanwar 7 years, 3 months ago

It's cbse

Ranveer Singh 7 years, 3 months ago

Hi cbsc
  • 5 answers

Sandhya Sreedhar 7 years, 3 months ago

All the best shreya

Raunak _ Pandey ?? 7 years, 3 months ago

Have a chill pil

Anshika Mittal 7 years, 3 months ago

Mineis nahi mine

Anshika Mittal 7 years, 3 months ago

Mineis on 17th October well best of luck

. . 7 years, 3 months ago

Me to...
  • 1 answers

Sia ? 6 years, 6 months ago

Given polynomial is p(x) = 2x3 - 6x2 + 5x - 7
Let {tex}\alpha{/tex} = (a - b), {tex} \beta{/tex} = a and {tex}\gamma{/tex} = ( a + b) 
Now, {tex} \alpha + \beta + \gamma{/tex} = {tex}-\frac{(-6)}{2}{/tex} =  3
⇒  ( a - b) + a + (a + b ) = 3
⇒ a - b + a + a + b = 3
⇒  3a = 3 
⇒ a = 3/3
⇒  a = 1
So the value of a in given polynomial is 1.

  • 5 answers

Anshika Mittal 7 years, 3 months ago

Formula for common difference is T2-T1 =term 2 -term1 =4-2 = 2 Hence common difference is 2

Vaibhav Parmar 7 years, 3 months ago

2

Gurpreet Singh 7 years, 3 months ago

Thus the common difference is 2 of given AP

Gurpreet Singh 7 years, 3 months ago

Common difference,d=term 2-term1 That is d=4-2=2 Thus

Raunak _ Pandey ?? 7 years, 3 months ago

2
  • 1 answers

Anshika Mittal 7 years, 3 months ago

Yes of course the person who is giving solution or any answer of any question will not give you wrong
  • 2 answers

Gurpreet Singh 7 years, 3 months ago

By euclid's division algorithm we know that a =bq+r as in the question it is given as 4q+1;then b=4 and as we know 0<r<b. Then r =0;1;2;3 1) when r=0 a=4q+0 a=4q 2)when r=1 a=4q+1 Hence proved that 3)when r=2 a=4q+2 4)when r=3 a=4q+3 Hence proved

Sumit Katariya 7 years, 3 months ago

2
  • 1 answers

Shreyansh Shukla 7 years, 3 months ago

2AB if 2 is not power or AB² if 2 is a power
  • 2 answers

Vaibhav Parmar 7 years, 3 months ago

2/6=1/3.

Archit Dutta 7 years, 3 months ago

2/6=1/3
  • 2 answers

Gautam Mishra 7 years, 3 months ago

No, the first term is 105 and last term is 994

Hariom Tiwari 7 years, 3 months ago

128 is ans
  • 1 answers

Sia ? 6 years, 6 months ago


We have, AB = 16 cm
{tex} \therefore{/tex} AL = BL = 8 cm [Perpendicular from the centre of the circle to a chord bisects it]
In {tex}\triangle{/tex}OLB, we have,
OB2 = OL2 + LB2
{tex} \Rightarrow{/tex} 102 = OL2 + 82
{tex} \Rightarrow{/tex} OL2 = 100 - 64 = 36
{tex} \Rightarrow{/tex} OL = 6 cm
Let PL = x and PB = y. Then, OP = (x + 6) cm.
Now, {tex} \angle PBO = 90^\circ{/tex}  as tangent makes a right angle with the radius of the circle at the point of contact.
In {tex}\triangle{/tex}'s PLB and OBP, we have,
PB2 = PL2 + BL2 and OP2 = OB2 + PB2
{tex} \Rightarrow{/tex} y2 = x2 + 64 and (x + 6)2 = 100 + y2 [Substituting the value of y2 in second equation]
{tex} \Rightarrow{/tex} (x + 6)2 = 100 + x2 + 64
{tex} \Rightarrow{/tex} 12x = 128
{tex}\Rightarrow x = \frac{{32}}{3}cm{/tex}
{tex} \therefore{/tex} y2 = x2 + 64
{tex} \Rightarrow {y^2} = {\left( {\frac{{32}}{3}} \right)^2} + 64 = \frac{{1600}}{9}{/tex}
{tex} \Rightarrow y = \frac{{40}}{3}cm{/tex}
Therefore, {tex} PA = PB = \frac{{40}}{3}cm{/tex}

  • 2 answers

Mahesh Kumar Yadav 7 years, 3 months ago

Here tan A =3 and cosA =4

Hariom Tiwari 7 years, 3 months ago

COt 7 t an 7
  • 1 answers

Archit Dutta 7 years, 3 months ago

a=bq×r A=4q×r (where q is any poistive no.) 0<=r>4 r=0,1,2,3 Put r in a=bq+r (4q+0)cube =64q^3 =4(16q^3) =4m(m=16q^3) (4q+1)cube Do like (4q+0)cube
  • 1 answers

Aditya Singh 7 years, 3 months ago

5040
  • 2 answers

Satyam Singh 7 years, 3 months ago

A

Akshay Chaudhay 7 years, 3 months ago

(a+b)3+c3 now put the (a+b)3 formula you will get your answer
  • 7 answers

$#@|\|@¥@ Khan 7 years, 3 months ago

16

Arockia Joshua 7 years, 3 months ago

That's wright answer is 16

Harsh Naik 7 years, 3 months ago

16

Sachin Singh 7 years, 3 months ago

16

Yogita Ingle 7 years, 3 months ago

8 + 8  × 8 ÷ 8
= 8 + 8  × 1
= 8 + 8

= 16

Sunil Kumar 7 years, 3 months ago

Using rule of BODMAS . Its answer is 16

Rajan Kumar 7 years, 3 months ago

16
  • 3 answers

Aachal Singh 7 years, 3 months ago

Still they are going on .yours over?

Harsh Naik 7 years, 3 months ago

Half yearly exam is over Aachal..

Aachal Singh 5 years, 8 months ago

Hi
  • 2 answers

Divya Keshav 7 years, 3 months ago

tan4a here 4 is the power of tanA(tan ki power 4)

Sachin Singh 7 years, 3 months ago

1
  • 2 answers

Divya Keshav 7 years, 3 months ago

10

Sachin Singh 7 years, 3 months ago

-2
  • 3 answers

Sachin Singh 7 years, 3 months ago

101001.09.0099.00999

Polo .... 7 years, 3 months ago

10,001.090099009

Yogita Ingle 7 years, 3 months ago

10001.09009

  • 1 answers

Gurpreet Singh 7 years, 3 months ago

Trigonometry is a basic subject of maths if you know all formulas of trigonometry you can do any questions of it.There are 75percent chances that it come out of ncert?
  • 1 answers

Polo .... 7 years, 3 months ago

255 = 43×5+40 43 = 40×1+3 40 = 3×13+1 3 = 1×3+0 Thus, HCF (255,43) = 1
  • 5 answers

Shubham Goyal 7 years, 3 months ago

No NCERT is not sufficient for board exam to bring good marks.You can just pass

Devanshi Grover 7 years, 3 months ago

NCERT is the base but its importance to practice from other reference books also....

Ayushi Choudhary 7 years, 3 months ago

I don't think soo?

Mohit Kashyap 7 years, 3 months ago

Ofcourse

Prithviraj Chouhan 7 years, 3 months ago

Yess bro
  • 1 answers

Ritika????? Kaim 7 years, 3 months ago

English me bhi ki ja sakti h .main bhi hindi medium me hi hu juber khan ??

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App