CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let the value of x in 3x+y=1 be 1 suppose (assumed) 3+y=1 y=3-1 y=2 Now in eq.px+2y=5 y=2 px+2(2)=5 px+4=5 Let x be 1 p+4=5 p=5-4 p=1 Please correct me if i am wrong

0Thank You

ANSWER

Any one can connect with me on my fb account for study materials Name- Aditya kumar At/po - Bihar begusarai

Posted by Aditya Jha 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Aditya Jha 7 years, 2 months ago

Hii

0Thank You

Harsh Singh 7 years, 3 months ago

Me Harsh Ràj

1Thank You

ANSWER

Find 5⃣ rational number between 3by5and 4by5.

Posted by Yashpal Raikwar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Himanshu Sharma 7 years, 3 months ago

Let ,x=3by5 and y=4by5. D=(Y-xupon N+1) formula. N is the number, whose find you. 4by5-3by5 upon 5+1. 3-4/5/6= -1by30 D= -1by30. then, X+d=3by5+(-1by30)=17by30. X+2d=3by5+(-1×2by30)=16by30 X+3d=? X+4d=? X+5d=? Please try again you Thanks

0Thank You

ANSWER

Find the value using suitable properties? 7265×7265-7265×265

Posted by Raaghib Rahim 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Vaibhav Parmar 7 years, 3 months ago

but yogita +7265 and -7265 toh cut ho sakte h na

0Thank You

Yogita Ingle 7 years, 3 months ago

7265 × 7265 - 7265 × 265
= 7265(7265 - 265)
= 7265(7000)
= 50855000

1Thank You

ANSWER

What is basic professional thoerme in Ch-6

Posted by Kuljeet Singh Solanki 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Mayank Chhabra 7 years, 3 months ago

Its basic propotionality theorm i.e., A line drawn parallel to one side of triangle intersects to sides in same ratio

0Thank You

Sushil Kumar 7 years, 3 months ago

All therom are good . But 6.1 and 6.8 i think more inportant and use full in many questions

0Thank You

ANSWER

In triangle pqr angle q = 90 and sin r = 3/5 write the value of cos p

Posted by Awais Ibrahim 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Mayank Chhabra 7 years, 3 months ago

Let pq=3x & pr=5x Cos p =adj/hypt. =3/5

0Thank You

Rakesh Kumar Tiwari 7 years, 3 months ago

R+P=90° =› P=90-R =› cosP=cos(90-R) = sinR = 3/5

0Thank You

ANSWER

value of sin2A+cos2A

Posted by Atul Rajput 7 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Mayank Chhabra 7 years, 3 months ago

Is it sin2A&cos2A or sin2(sq) A+cos 2(sq)A

0Thank You

Kuljeet Singh Solanki 7 years, 3 months ago

2Thank You

Atul Rajput 7 years, 3 months ago

1Thank You

ANSWER

The zeroes of quadratic polynomial x2-x-4 find the value of 1 / alpha plus 1 / beta- alpha*beta pls help to solve this ques

Posted by Nurav Nurav 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

F(x)=x²-x-4

here a=1,b=-1,c=-4

Now {tex}\mathrm\alpha\;\mathrm{and}\;\mathrm\beta{/tex} are zeros of f(x)
Sum of zeroes = α + β {tex}=-\frac ba{/tex}=-{tex}\frac{-1}{1}{/tex}=1
Product of the zeroes = αβ = {tex}\frac ca{/tex}={tex}\frac{-4}{1}=-4{/tex}
{tex}\frac1{\mathrm\alpha}+\frac1{\mathrm\beta}-\mathrm{αβ}=\frac{\mathrm\alpha+\mathrm\beta-\mathrm\alpha^2\mathrm\beta^2}{\mathrm{αβ}}=\frac{1-(-4)^2}{-4}{/tex}
{tex}=\frac{1-16}{-4}=\frac{-15}{-4}=\frac{15}4{/tex}

0Thank You

ANSWER

xcube+1uponxcube=110 find x+1uponx

Posted by Siddhant Chaudhry 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is the common difference of an ap if its nth term is 7n -1

Posted by Prisha Rana 7 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Mayank Chhabra 7 years, 3 months ago

1Thank You

Mohd Zubair 7 years, 3 months ago

1Thank You

ANSWER

1/α +1/β =

Posted by Royal Riya Shah 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajesh Sriuttam Panigrahi 7 years, 3 months ago

α+β/αβ

4Thank You

ANSWER

A fraction becomes 4.5 if 1 is added to both numerator and denominator if however 5 is subtracted from both numerator and denominator the fraction becomes 1.2 what is the fraction

Posted by Money Kanwar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let numerator of fraction is x and denominator is y.
Let the fraction be {tex}\frac { x } { y }.{/tex}
Then, according to the given conditions, we have
If 1 is added to both numerator and denominator then fraction becomes {tex}\frac { 4 } { 5 }{/tex}.
{tex}\frac { x + 1 } { y + 1 } = \frac { 4 } { 5 } {/tex}
{tex}\Rightarrow{/tex} 5x +5 =4y + 4
{tex}\Rightarrow{/tex} 5x - 4y + 1=0 ...... (i)
If 5 is subtracted from both numerator and denominator, the fraction becomes {tex}\frac { 1 } {2}{/tex}.
{tex}\frac { x - 5 } { y - 5 } = \frac { 1 } { 2 }{/tex}
{tex}\Rightarrow{/tex} 2x - 10 = y - 5
{tex}\Rightarrow{/tex} 2x - y - 5=0 ........ (ii)
From (i) and (ii)
By using cross-multiplication, we have
{tex}\frac { x } { - 4 \times - 5 - ( - 1 ) \times 1 } = \frac { - y } { 5 \times - 5 - 2 \times 1 } = \frac { 1 } { 5 \times - 1 - 2 \times - 4 }{/tex}
{tex}\Rightarrow \quad \frac { x } { 20 + 1 } = \frac { y } { 25 + 2 } = \frac { 1 } { - 5 + 8 }{/tex}
{tex}\Rightarrow \quad \frac { x } { 21 } = \frac { y } { 27 } = \frac { 1 } { 3 } {/tex}
{tex}\Rightarrow x = \frac { 21 } { 3 } = 7 \text { and } y = \frac { 27 } { 3 } = 9{/tex}

Hence, the given fraction is 7/9.

0Thank You

ANSWER

X/2+y=0.8 7/x+y/2=10 Find x and y value

Posted by Jayant Arora 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

{tex}\frac{x}{2}{/tex} + y = 0.8
{tex}\Rightarrow{/tex} x + 2y = 1.6
{tex}\Rightarrow{/tex} x = 1.6 - 2y ...........(i)
and {tex}\frac{7}{x+\frac{y}{2}}=10{/tex}
{tex} \Rightarrow \frac{14}{2 x+y}{/tex} = 10
{tex}\Rightarrow{/tex} 20x + 10y = 14
{tex}\Rightarrow{/tex} 10x + 5y = 7 ..........(ii)
Put (i) in (ii), we get
10(1.6 - 2y) + 5y = 7
{tex}\Rightarrow{/tex} 16 - 20y + 5y = 7
{tex}\Rightarrow{/tex} -15y = -9
{tex}\Rightarrow{/tex} y = {tex}\frac{9}{15}{/tex} = 0.6
Put y = 0.6 in equation (i), we get
x = 1.6 - 2(0.6)
x = 0.4
Hence x = 0.4 and y = 0.6 is the solution of given system of equations.

0Thank You

ANSWER

X2+y3+z

Posted by Roushan Kumar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove that tangent is perpendicular to radius

Posted by Pabitra Swain 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajesh Sriuttam Panigrahi 7 years, 3 months ago

Google srarch

1Thank You

ANSWER

Explain why 3×-5×7+7 is a composite number.

Posted by Ziya Ferzin 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have, (3 × 5 × 7) + 7 = 105 + 7 = 112

Prime factors of 112 = 2 × 2 × 2 × 2 × 7 = 2^{4 {tex} \times {/tex}} 7

So, it is the product of prime factors 2 and 7, i.e. it has factors other than 1 and itself. Hence, it is a composite number.

0Thank You

ANSWER

The height of a cone is 32 cm . A small cone is cut off at the top by a parallel to its base. If its volume be 1/64 of the volume of the given cone , find at what height above the base is the secton made.

Posted by Ayush Aswal 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Range of sinx

Posted by Sachin Tushar 7 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sachin Tushar 7 years, 3 months ago

-1,1

2Thank You

ANSWER

For which value of k will the following pair of linear equations

Posted by Danish Rana 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Is their any trick to solve trignometric problems??

Posted by Manya Singh 7 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Mayank Chhabra 7 years, 3 months ago

Sin=per./hypt Cos =base/hypt Tan=per./base Cosec =h/p Sec=h/b Cot=b/h U can learn this like Pandit bhole prasad hr hr bhole I don't know any other triick

1Thank You

$#@|\|@¥@ Khan 7 years, 3 months ago

Yaaaa Learn all the identities

0Thank You

Angel Chaubey 7 years, 3 months ago

Yes,practice is the only way to solve trignometric problems.

1Thank You

ANSWER

Where do u live

Posted by Mayank Chhabra 7 years, 3 months ago

CBSE > Class 10 > Mathematics