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Use quadratic formula First find D D=b^2-4ac (3√3)^2 -4×1×6 27-24 =3 Now apply value of D in quadratic formula (-3√3)^2+-√3÷2 27+-√3÷2 Hence roots are 27+√3÷2 and 27-√3÷2

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Deepesh Patel 7 years, 1 month ago

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a/b×x+b/a×y=(a-b)

Posted by Devendra Bairwa 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Half the perimeter of a rectangular garden, whose length is 4m more than its width, is 36m. Find the dimensions of the garden

Posted by Keerthana Gigi 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 1 month ago

20,16

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I can't understand the lesson 'similar triangles'.Please explain me

Posted by Amaan Ahmed 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove thatsin theta(1+tantheta)+costheta(1+cottheta)=sectheta + cosectheta

Posted by Humayun Hassan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Payal Jena 7 years, 1 month ago

LHS =sin theta (1+sin theta /cos theta) +cos theta (1+cos theta /sin theta) =sin theta /cos theta (sin theta +cos theta) +cos theta /sin theta (sin theta +costheta) =( sin theta +costheta) (sin theta /cos theta +cos theta /sin theta) =sin theta +costheta /sin theta *costheta) =1/cos theta +1/sin theta =sec theta+cosec theta=RHS(proved) Hope this will help you ☺️

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Avika Chaudhary 7 years, 1 month ago

Brain is the part of our body inside our head that controls our thoughts feelings and movements.???

2Thank You

Sohail Khan 7 years, 1 month ago

What is brain

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ANSWER

If p (9a-2,6) divided the line segment join A ( 3a+1,-3 ) and B (8a, 5) in the ratio 3: 1 find the value of a and b

Posted by Ak Baadshah 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Chesta Pawan Manchanda 7 years, 1 month ago

Where is the b

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Ayush Maurya 7 years, 1 month ago

In this question there is no 'b'. So, according to the question 'a' is -1

0Thank You

Deepak Baranwal 7 years, 1 month ago

kutta kamina lathakhor

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ANSWER

What is real name

Posted by Abhay Randhawa 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Panchal Manthan 7 years, 1 month ago

Original name

1Thank You

Rajeev Kumar Choudhary 7 years, 1 month ago

A main name who describe himself or herself.☺️☺️☺️☺️☺️☺️

1Thank You

Deepak Baranwal 7 years, 1 month ago

by which a person can describe himself

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No its complete equation

Posted by Rashid ¥€$ 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Dgukb

Posted by Soumya Ranjan Samantaray 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Ik month di salary 45000 ..ik din ch 8 ghante kam karda..ta ik ghante di kini salary hau??

Posted by Simran Kaur 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Praanshu Joshi 7 years, 1 month ago

Let the month had 30 days for which he works . Salary for 1 day=45000/30=1500 That is salary for 8 working hrs is 1500 Salary for 1 hour=1500/8=187.5

1Thank You

ANSWER

X^2 -- (root2 +1)x +root2 = 0

Posted by Anjali Kumari??? 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Praanshu Joshi 7 years, 1 month ago

X=√2 or x=1

2Thank You

ANSWER

{(√3+2√3-4)÷(2√3)}÷(4+√3+2√3)÷2√3

Posted by Neeraj Kumar Soni 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Kunal J 7 years, 1 month ago

43 - 36√3÷ 11

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ANSWER

Any tips and tricks for preparation of board exam? I want to get science stream ?

Posted by Radhika :) Mishra:} 7 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

Abhay Sharma 7 years, 1 month ago

First do board exams and then see medical stream.

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Abhi H 7 years, 1 month ago

Dont take much stress and sit for studies 24 hrs

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Chesta Pawan Manchanda 7 years, 1 month ago

Do hardwork as much as you can do . And be prepare yourself for science stream.and let me tell you one thing ,if you are thinking about science stream so don't change your mind at that time because the same thing has been happened to me.

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Harmat Raj Purohit 7 years, 1 month ago

eat your teachers ****

2Thank You

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A 2 digit number is such that the product of the digit is 14 when 45 is added to the number, the digit are reserved. Find the number

Posted by Suroop Shah 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Praanshu Joshi 7 years, 1 month ago

Let no. Be 10x+y A.T.Q xy=14 Also 10x+y+45=10y+x Solving these two equations we get x=2;y=7 No. =10x+y=10×2+7=27

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Harmat Raj Purohit 7 years, 1 month ago

27 27+45=72

1Thank You

ANSWER

A cistern. Internally measure 159cm×120cm×110cm has 129600cm^3of water

Posted by Deepshikha Shukla 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Satish Singh 7 years, 1 month ago

Bhghh

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The sum of first 4 of an AP is 1/2. The sum of next 4 terms

Posted by Rashid ¥€$ 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Chesta Pawan Manchanda 7 years, 1 month ago

Where is the sum of next four terms

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Chesta Pawan Manchanda 7 years, 1 month ago

Your question is incomplete rashid

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It is true that there will two question paper for maths..

Posted by Neha Prajapati 7 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

Neha Prajapati 7 years, 1 month ago

If I have take PCB so which Question paper I should choose

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Panchal Manthan 7 years, 1 month ago

OH | really. .....................?

1Thank You

Chesta Pawan Manchanda 7 years, 1 month ago

Yes it is true you can opt any one of them but let me tell you one thing always choose tuff question paper that will help in your studies

1Thank You

Apurv Gautam 7 years, 1 month ago

It is true but not for the year 2018 _ 19 . CBSE just planned for it . It is not for our board exams.

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If ax^2+bx+6 does not have two distinct real roots then find the value of 3a+b

Posted by Khushi Garg 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the mean and mode age in years for the following frequency distribution Age (in years). No of persons 10-19. 8 20-29. 8 30-39 10 40-49 14 50-59. 28 60-69. 12

Posted by Pallavi Kumari 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

A quadrilateral is drawn to circumscribe a circle . please tell me what is the meaning of circumscribe?

Posted by Lorial Brail 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Subjeet Sahow 7 years, 1 month ago

It means that the quadrilateral is drawen outside the circle such that the boundary of quadrilateral is touch the 4 points of circle

2Thank You

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Vgjk Bh

Posted by Deepanshu Kumar 5 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If x=3 is one root of the following quadratic equation x2-2kx-6=0then find the value of k

Posted by Abhishek Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Ankeet Pandey 7 years, 1 month ago

1/2

3Thank You

ANSWER

The tops of two poles of height 25 m and 35m are connected by a wire which make an angle of elevation of 30 degree at the top of 25m pole . Find the length of the wire

Posted by Aryan Roy 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Praanshu Joshi 7 years, 1 month ago

20 meters

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Tushar Kumar 7 years, 1 month ago

20met

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A.K. Mahi ? 7 years, 1 month ago

Length of wire = 20 m.

3Thank You

ANSWER

In a family of 3 children, find the probability of having at least one boy

Posted by Kashif Khan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

Praanshu Joshi 7 years, 1 month ago

7/8

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Tushar Kumar 7 years, 1 month ago

1/3

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Auroshree Mishra 7 years, 1 month ago

P (boy)=1/3

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A.K. Mahi ? 7 years, 1 month ago

P(at least one boy) = 7/8.

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ANSWER

If m^th term

Posted by Umesh Sharma 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let a and d be the first term and common difference respectively of the given A.P. Then
a_n = a + (n - 1)d
{tex}\frac { 1 } { n } ={/tex} m^th term
{tex}\Rightarrow \frac { 1 } { n } {/tex}= a + ( m - 1 ) d ...(i)
{tex}\frac { 1 } { m }{/tex}= nth term
{tex}\Rightarrow \frac { 1 } { m } {/tex}= a + ( n - 1 ) d ...(ii)
On subtracting equation (ii) from equation (i), we get
{tex}\frac { 1 } { n } - \frac { 1 } { m } = {/tex} [a+ (m-1) d] -[ a+ (n -1)d]
= a + md - d - a - nd + d
{tex}= ( m - n ) d{/tex}
{tex} \Rightarrow \frac { m - n } { m n } = ( m - n ) d {/tex}
{tex}\Rightarrow d = \frac { 1 } { m n }{/tex}
Putting d = {tex}\frac { 1 } { m n }{/tex} in equation (i), we get
{tex}\frac { 1 } { n } = a + \frac { ( m - 1 ) } { m n } {/tex}
{tex}\Rightarrow \frac { 1 } { n } = a + \frac { 1 } { n } - \frac { 1 } { m n } {/tex}
{tex}\Rightarrow a = \frac { 1 } { m n }{/tex}
{tex}\therefore{/tex} (mn)^th term = a + (mn - 1) d
= {tex}\frac { 1 } { m n } + ( m n - 1 ) \frac { 1 } { m n } {/tex}{tex}\left[ \because a = \frac { 1 } { m n } = d \right]{/tex}
= {tex}\frac { 1 } { m n } + \frac { mn } { m n } - \frac { 1 } { m n }{/tex}
= 1

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ANSWER

Prove that opposite sides of quadrilateral circumscribing a circle subtend supplement ary angles at the centre of the circle

Posted by Abhi H 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given: ABCD is a quadrilateral circumscribing a circle whose centre is O.
To prove:

{tex}\angle{/tex}AOB + {tex}\angle{/tex}COD = 180^o
{tex}\angle{/tex}BOC + {tex}\angle{/tex}AOD = 180^o

Construction: Join OP, OQ, OR and OS.

Proof: Since tangents from an external point to a circle are equal.
{tex}\therefore{/tex} AP = AS,
BP = BQ ........ (i)
CQ = CR
DR = DS
In {tex}\triangle{/tex}OBP and {tex}\triangle{/tex}OBQ,
OP = OQ [Radii of the same circle]
OB = OB [Common]
BP = BQ [From eq. (i)]
{tex}\therefore{/tex} {tex}\triangle{/tex}OPB {tex}\cong{/tex} {tex}\triangle{/tex}OBQ [By SSS congruence criterion]
{tex}\therefore{/tex} {tex}\angle{/tex}1 = {tex}\angle{/tex}2 [By C.P.C.T.]
Similarly, {tex}\angle{/tex}3 = {tex}\angle{/tex}4, {tex}\angle{/tex}5 = {tex}\angle{/tex}6, {tex}\angle{/tex}7 = {tex}\angle{/tex}8
Since, the sum of all the angles round a point is equal to 360^o.
{tex}\therefore{/tex} {tex}\angle{/tex}1 + {tex}\angle{/tex}2 + {tex}\angle{/tex}3 + {tex}\angle{/tex}4+ {tex}\angle{/tex}5 + {tex}\angle{/tex}6 + {tex}\angle{/tex}7 + {tex}\angle{/tex}8 = 360^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}1 + {tex}\angle{/tex}1 + {tex}\angle{/tex}4 + {tex}\angle{/tex}4+ {tex}\angle{/tex}5 + {tex}\angle{/tex}5 + {tex}\angle{/tex}8 + {tex}\angle{/tex}8 = 360^o
{tex}\Rightarrow{/tex} 2 ({tex}\angle{/tex}1 + {tex}\angle{/tex}4 + {tex}\angle{/tex}5 + {tex}\angle{/tex}8) = 360^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}1 + {tex}\angle{/tex}4 + {tex}\angle{/tex}5 + {tex}\angle{/tex}8 = 180^o
{tex}\Rightarrow{/tex} ({tex}\angle{/tex}1 + {tex}\angle{/tex}5) + ({tex}\angle{/tex}4 + {tex}\angle{/tex}8) = 180^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}AOB + {tex}\angle{/tex}COD = 180^o
Similarly we can prove that
{tex}\angle{/tex}BOC + {tex}\angle{/tex}AOD = 180^o

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Page 946 of 1971

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