CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

To construct: A line segment of length 8 cm and taking A as centre, to draw a circle of radius 4 cm and taking B as centre, draw another circle of radius 3 cm. Also, to construct tangents to each circle from the centre to the other circle.
Steps of Construction :

Bisect BA. Let M be the mid-point of BA.
Taking M as centre and MA as radius, draw a circle. Let it intersects the given circle at the points P and Q.
Join BP and BQ.
Then, BP and BQ are the required two tangents from B to the circle with centre A.
Again, Let M be the mid-point of AB.
Taking M as centre and MB as radius, draw a circle. Let it intersects the given circle at the points R and S.
Join AR and AS.
Then, AR and AS are the required two tangents from A to the circle with centre B.
Justification: Join BP and BQ.
Then {tex}\angle APB{/tex} being an angle in the semicircle is 90^o.
{tex} \Rightarrow BP \bot AP{/tex}
Since AP is a radius of the circle with centre A, BP has to be a tangent to a circle with centre A. Similarly, BQ is also a tangent to the circle with centre A.
Again join AR and AS.
Then {tex}\angle ARB{/tex} being an angle in the semicircle is 90^o.
{tex} \Rightarrow AR \bot BR{/tex}
Since BR is a radius of the circle with centre B, AR has to be a tangent to a circle with centre B. Similarly, AS is also a tangent to the circle with centre B.

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Perimeter of a circel

Posted by Nishant Hussain 7 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

??Amrit ???????? ????Thakur???????? 7 years, 1 month ago

Spelling of circle c i r c l e

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Ananya Sharma 7 years, 1 month ago

2πr

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Kunal Mishra 7 years, 1 month ago

2 pie r is the perimiter

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Shan? .Va 7 years, 1 month ago

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A train has to be covered 200 km distance with an average speed.Let the speed increased by 8km/h, it would take 1h less. Find the average speed?

Posted by Anurag Kumar 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find term from end of the ap 17,14,11........-40

Posted by Yash Gandharv 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Sujal Rai 7 years, 1 month ago

Given AP:17,14,11,..........-40 a=17 d=14-17 = -3 Tn= -40 n=? Now, Tn=a+(n-1)d -40=17+(n-1)(-3) -40 -17=(n-1)(-3) -57= -3n+3 -57-3= -3n -60 =-3n -60/-3= n 20=n Or n=20 I Think its help you.

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Harshita Srivastava 7 years, 1 month ago

The nth term from the end of the AP is 20

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Prove root 4 is irrational

Posted by Sachin Raj 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Praanshu Joshi 7 years, 1 month ago

Root 4 is rational

1Thank You

Sujal Rai 7 years, 1 month ago

No, root 4 is not a irrational number because we can write its, root 4=root 2×2 Root 4= 2 So, 2 is a rational number (hence proved)

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Posted by Vikas Rawat 7 years, 1 month ago

CBSE > Class 10 > Mathematics

4 answers

??Amrit ???????? ????Thakur???????? 7 years, 1 month ago

Circles

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M I 7 years, 1 month ago

Bhai google pe seach karle??

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Saurabh Singh Harariya 7 years, 1 month ago

Just sel up

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Anurag Aswal 5 years, 8 months ago

Gobar

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Posted by Ajit Rai 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Ananya Sharma 7 years, 1 month ago

Trignometric ratios signs

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The internal and external diameters of a hollow hemisphere vessel are 42cm and 45.5cm , respectively. Find its capacity and also its outer curved surface area.

Posted by Gujjar Fagna 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Rohan Verma 5 years, 8 months ago

Guss

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ANSWER

Prove that the sum of the squares of diagonals of a parallelogram is equal to the sum of the squares of its sides.

Posted by Gujjar Fagna 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Hamza Hasan 7 years, 1 month ago

Answer, In parallelogram ABCD, AB = CD, BC = AD Draw perpendiculars from C and D on AB as shown. In right angled ΔAEC, AC2 = AE2 + CE2 [By Pythagoras theorem] ⇒ AC2 = (AB + BE)2 + CE2 ⇒ AC2 = AB2 + BE2 + 2 AB × BE + CE2 → (1) From the figure CD = EF (Since CDFE is a rectangle) But CD= AB ⇒ AB = CD = EF Also CE = DF (Distance between two parallel lines) ΔAFD ≅ ΔBEC (RHS congruence rule) ⇒ AF = BE Consider right angled ΔDFB BD2 = BF2 + DF2 [By Pythagoras theorem] = (EF – BE)2 + CE2 [Since DF = CE] = (AB – BE)2 + CE2 [Since EF = AB] ⇒ BD2 = AB2 + BE2 – 2 AB × BE + CE2 → (2) Add (1) and (2), we get AC2 + BD2 = (AB2 + BE2 + 2 AB × BE + CE2) + (AB2 + BE2 – 2 AB × BE + CE2) = 2AB2 + 2BE2 + 2CE2 AC2 + BD2 = 2AB2 + 2(BE2 + CE2) → (3) From right angled ΔBEC, BC2 = BE2 + CE2 [By Pythagoras theorem] Hence equation (3) becomes, AC2 + BD2 = 2AB2 + 2BC2 = AB2 + AB2 + BC2 + BC2 = AB2 + CD2 + BC2 + AD2 ∴ AC2 + BD2 = AB2 + BC2 + CD2 + AD2 Thus the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.

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??Amrit ???????? ????Thakur???????? 7 years, 1 month ago

Dont ask maths

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Praanshu Joshi 7 years, 1 month ago

Use appoloneous theorem

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can the number 6n, n being a natural number, end with the digit 5? Give reason

Posted by Jatin Salaria 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Rachit Dwivedi 7 years, 1 month ago

6n = (2×3)n and we know that the no. which end with 5 it must have 5 as its factor . So it does not end with 5

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Prashanshi Khushi 7 years, 1 month ago

If any number ends with 5, then it will be divisible by 5 . Here 6 is not divisible by 5 .so, that 6n can not end with 5

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ANSWER

1+sinA. 1- sinA/1+cosA.1-cosA

Posted by Sunny Kumar 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Chesta Pawan Manchanda 7 years, 1 month ago

1+sinA×1-sinA/1+cosA×1-cosA=1^2-sin^2/1^2-cosA^2 by ((a+b)(a-b)=a^2-b^2) then cos^2A/sin^2A=cot^2A hence 1+sinA×1-sinA/1+cosA×1-cosA=cot2A

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Nikhil Yadav 7 years, 1 month ago

Me to

3Thank You

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The system of linear equations 5x +my =10 and 4x +my =8 have infinitely many solutions where m and n are positive integers. Then the minimum possible value of m+n is equal to a = 9 B=5 C=6 D=10

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CBSE > Class 10 > Mathematics

0 answers

ANSWER

I can't prepare fully for anthe ."anmol"?

Posted by Diksha Y 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

In triangle ABC,right angled at B,AB=24cm BC=7cm. Determine (i) sin A, cosA (ii) sin C, cosC

Posted by Abhay Randhawa 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Harshita Srivastava 7 years, 1 month ago

SinA=7/25,cosA=24/25,sinC=24/25,cosC=7/25

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ANSWER

Find the sum of all natural numbers less than hundred which are divisible by 6

Posted by Anushree Sangai 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Chesta Pawan Manchanda 7 years, 1 month ago

N=16 ,a=6,d=6 n16=? N16=16/2(2×6+(16-1)6)=110

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Ashish © 7 years, 1 month ago

What H????

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Anushree Sangai 7 years, 1 month ago

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ANSWER

48 x ( x+14) = 16( x+14)*2

Posted by Suhail Mansoori 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

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Posted by Sahil Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

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Posted by Ankit Jaiswal 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Sparsh Rajput 7 years, 1 month ago

Yaaaa

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Ankit Jaiswal 7 years, 1 month ago

That means it is not confirm

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Sparsh Rajput 7 years, 1 month ago

Easy it is now the case of discussion By cbse

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The distance between two stations is 340km. Two trains start simultaneously form these stations on parallel tracks to cross each other. The speed of one of them that of other by 6km/hr. If the distance between the two trains after 2 hours of their start is 30km,the speed of each train is?

Posted by Shaswat Sethi 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Multiples of 2

Posted by Mohd Yousf 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Prashanshi Khushi 7 years, 1 month ago

The number which is end with even number are multiples of 2 . Ex.2,4,6,8 ,0 and so on

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Kanika Yadav 7 years, 1 month ago

2,4,6,8,10,12and so on

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Find all the zeros of 2x

Posted by Aadesh Shinde 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

In given figure, abc is a triangle right angles at B and BD perpendicular to AC. If ad =4 Cm and CD =5 CM, than find BD and ab

Posted by Bharath Srikakula 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Sparsh Rajput 7 years, 1 month ago

Hsaaaaa

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Kunal J 7 years, 1 month ago

And where is figure?

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Find hcf of the number given below:- k,2k,3k,4k and 5k. Where k is a positive integers

Posted by Tarun Rao 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

{tex}\begin{array}{l}k=\;k\times1\\2k=\;k\times2\\3k=k\times3\\4k=k\times2\times2\\5k=k\times5\end{array}{/tex}
Here k is a positive integer
Hence HCF(k,2k,3k,4k,5k)= k.

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Can you add a workbook solution for class 110th?

Posted by Ravinder Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics