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The common difference between a1 and a2 Common difference = a2 - a1 =(3y + 5) - (3y - 1) =3y + 5 - 3y + 1 =6. ――1 Now the common difference between a3 and a2 Common difference =a3 - a2 =(5y + 1) - (3y + 5) =5y + 1 - 3y - 5 = 2y - 4 ――2 On equating 1 and 2 we get 2y - 4 = 6 2y = 10 y = 5 So the value of y is 5

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SinA+cosA=√2cosA ,prove that cosA-sinA=√2sinA

Posted by Prince Katariya 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Purvanshi Yadav 7 years, 1 month ago

SinA+cosA=√2cosA SinA=√2cosA-cosA SinA=(√2-1)cosA SinA=(√2-1÷1×√2+1÷√2+1)×cosA SinA=(2-1÷√2+1)×cosA SinA=cosA÷√2+1 (√2-1)×sinA=cosA √2sinA+sinA=cosA √2sinA=cosA-sinA

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Sin360 is what

Posted by Amarnath Shukla 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Amarnath Shukla 7 years, 1 month ago

Correct

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Himanshu Bhatia 7 years, 1 month ago

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A balloon is connected to a meteorological ground station by a cable of length 215m inclined at 60° to the horizontal. Determine the height of the balloon from the ground. Assume that there is no stack in the cable

Posted by Deepak Kumar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let height of balloon from ground = h m
Length of cable {tex}= 215 m{/tex}
In {tex}\Delta ABC{/tex}
{tex}\sin {60^o} = \frac{{AB}}{{AC}}{/tex}
{tex} \Rightarrow \frac{{\sqrt 3 }}{2} = \frac{h}{{215}}{/tex}
{tex} \Rightarrow h = \frac{{215\sqrt 3 }}{2}{/tex}
{tex} \Rightarrow h = \frac{{215 \times 1.73}}{2} = 185.9{/tex}

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If sinQ =cosQ ,find the value

Posted by Firoz Ahmed 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Omprakash Bishnoi 7 years, 1 month ago

kiski value nikale

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Amarnath Shukla 7 years, 1 month ago

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Find the value of k, if the quadratic equations 3x square -k under root +4 has eual root

Posted by Preeti Roy 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Amarnath Shukla 7 years, 1 month ago

4under root 3

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the differnce of squres of two number is 180. the squre of the smaller number is 8 times the lager number find the two number

Posted by Kajal Roy 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Ankita Vijay 7 years, 1 month ago

18,12 or 18, -12

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A cod of a circle of radius 10cm subtant of right angle at the center then the length chord find

Posted by Laxmi Diwan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Mohak Raval 7 years, 1 month ago

10√2

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When a no. Is divided by 11 it leaves remainder 8. If it is divided by 13 it leaves remainder 5. If it is divided by 17 it leaves remainder 3.Then find the no.?? Please this question are very toughf

Posted by Raushan Patel 7 years, 1 month ago

CBSE > Class 10 > Mathematics

5 answers

Raushan Patel 7 years, 1 month ago

Ye question real no. Ka h

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Raushan Patel 7 years, 1 month ago

Suresh sir hi diye h...?

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Pratyush Prakash 7 years, 1 month ago

suresh sir se poocho bhai

2Thank You

Sakshi Shobha 7 years, 1 month ago

Ye question hai konsi book say NCERT ya R D sharma????

1Thank You

Raushan Patel 7 years, 1 month ago

Their answer is 1669 but how?

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ANSWER

Vvv

Posted by Sujal Gupta 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Ankeet Pandey 7 years, 1 month ago

What you say , I don't understand

1Thank You

Deepak Prasad 7 years, 1 month ago

You need xxx

2Thank You

Sachdhar Choudhary 7 years, 1 month ago

Vvvv

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√x+y=7 X+√y=11

Posted by Rounak Rai 5 years, 8 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Given that HCF (253,440) = 11 and LCM (253,440)=253 x R, find the value of R

Posted by Astha Banerjee 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Sinchana Sheshadri 7 years, 1 month ago

HCF×LCM= 253×440 11×253R=111320. (÷11) 253R= 10120. (÷253) R= 40

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Saurav Raj 7 years, 1 month ago

55555

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500%80

Posted by Gautam Renu 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Aashu Kumar 7 years, 1 month ago

400

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Aashu Kumar 7 years, 1 month ago

500/100×80 =400

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Chetan Choudhary 7 years, 1 month ago

400

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From a point on a bridge across a river, the angle of depression of the banks on opposite sides of the river 30° and 40° respectively .if the bridge is at a hieght of 2.5 m from the banks, find the width of the river . use √3 = 1.732 Solve please

Posted by Sahil Gupta 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Chetan Choudhary 7 years, 1 month ago

What is the value of tan 40°

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One card is drawn from a well suffled deck of 52cards. Find probability of geeting . (1) a king of red colour

Posted by Prashant Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Simran Gambhir 7 years, 1 month ago

2/52=1/26

1Thank You

Mansi ??⚘?? 7 years, 1 month ago

P(getting a king of red colour)=1/52

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Rd sharma solutions of chapter polynomial

Posted by Sudhanshu Gupta 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Sachdhar Choudhary 7 years, 1 month ago

0Thank You

Sandeep Jaiswal 5 years, 8 months ago

Hyy

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ANSWER

Chapter 8 exercise 8.1

Posted by Aishwarya Kashyap 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Äãßhù @@Sswäg 7 years, 1 month ago

It is provided in the app in ncert solution !!

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If cos A=2/5 find the value of 4+4tan2a

Posted by Harshitha Harshitha 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Ankita Vijay 7 years, 1 month ago

4/625

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Amarjeet Yadav 7 years, 1 month ago

I dont know

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Are there any major changes in Board exams this year ? ?

Posted by Garima Demla 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Raunak _ Pandey ?? 7 years, 1 month ago

I don't think so !!!

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Find the condition that the zeros of the polynomial f(x)=x3+3px2+3qx+r may be in A.P.

Posted by Shivansh Srivastava 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

The given quadratic polynomial is:
f(x) = x³ + 3px² + 3qx + r
we have to show that the zeroes of given polynomial are in the form of AP.
Let, a - d, a, a + d be the zeroes of the polynomial, then
The sum of zeroes = {tex}\frac{{ - b}}{a}{/tex}
a + a - d + a + d = -3p
3a = - 3p
a = - p
Since, a is the zero of the polynomial f(x),
Therefore, f(a) = 0
f(a) = a³ + 3pa² + 3qa + r = 0
{tex}\Rightarrow{/tex} a³ + 3pa² + 3qa + r = 0
{tex}\Rightarrow{/tex} (-p)³ + 3p(-p)² + 3q(-p) + r = 0
{tex}\Rightarrow{/tex} -p³ + 3p³ - 3pq + r = 0
{tex}\Rightarrow{/tex} 2p³ - 3pq + r = 0
Which is the required condition.