CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

yupp...I used distance formulaa and mine was also 2. But my teacher said that Ans. will be 0 because we've to use Mid point formula here....But I still have a doubt.......2 or 0???⁉??

0Thank You

Deepak Bansal 7 years, 1 month ago

X =2

3Thank You

ANSWER

Prove root5 is irrational no.

Posted by Guru Patel 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 7 years, 1 month ago

let √5 be rational
then it must in the form of p/q [q is not equal to 0][p and q are co-prime]
√5=p/q
⇒ √5 × q = p
squaring on both sides
⇒ 5× q× q = p× p ------> 1
p×p is divisible by 5
p is divisible by 5
p = 5c [c is a positive integer] [squaring on both sides ]
p× p = 25× c× c --------- > 2
sub p× p in 1
5× q× q = 25× c× c
q× q = 5× c× c
⇒ q is divisble by 5
thus q and p have a common factor 5
there is a contradiction
as our assumsion p &q are co prime but it has a common factor
so √5 is an irrational

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ANSWER

Value of √7562

Posted by Deepak Mishra 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Yadav 7 years, 1 month ago

approx 86.956

0Thank You

ANSWER

Find 20th term from the last term AP 3,8,13.........253

Posted by Uday Sharma 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Abhinav Verma 7 years, 1 month ago

Given that: a=3 d=5 l=253 Now, A20=l-(n-1)d =253-(20-1)×5 =253-95 =158 So 20th term of AP is 158.

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ANSWER

Surface area

Posted by Vivek Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Aditi Choudhary 7 years, 1 month ago

Kiska

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ANSWER

What do you think about these questions

Posted by Laxmi Diwan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Devanshi Grover 7 years, 1 month ago

What questions?????????????

2Thank You

ANSWER

If a positive integer 'p' is divided by 7 ,then find the possible remainders.

Posted by Mitali Sabale 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Pragati ... 7 years, 1 month ago

0,1,2,3,4,5,6

3Thank You

ANSWER

Compute the derivative of i)f(x)=√sec√sinx

Posted by Tejaswini Sridharan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If cosec theta is equal to root 10 find other trigonometric ratios

Posted by Satwik Megeri 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have,
{tex}cosec \;A = \frac { \text { Hypotenuse } } { \text { Perpendicular } } = \frac { \sqrt { 10 } } { 1 }{/tex}
So, we draw a right triangle ABC, right-angled at B such that
Perpendicular = BC = 1 unit and, Hypotenuse{tex}= A C = \sqrt { 10 }{/tex}.
By Pythagoras theorem, we have
{tex}A C ^ { 2 } = A B ^ { 2 } + B C ^ { 2 }{/tex}
{tex}\Rightarrow \quad ( \sqrt { 10 } ) ^ { 2 } = A B ^ { 2 } + 1 ^ { 2 }{/tex}
{tex}\Rightarrow \quad A B ^ { 2 } = 10 - 1 = 9{/tex}
{tex}\Rightarrow \quad A B = \sqrt { 9 } = 3{/tex}
When we consider the trigonometric ratios of {tex}\angle A{/tex}, we have
Base = AB = 3 units, Perpendicular = BC = 1 units and, Hypotenuse{tex}= A C = \sqrt { 10 }{/tex} units
{tex}\therefore \quad \sin A = \frac { \text { Perpendicular } } { \text { Hypotenuse } } = \frac { 1 } { \sqrt { 10 } } , \cos A = \frac { \text { Base } } { \text { Hypotenuse } } = \frac { 3 } { \sqrt { 10 } }{/tex}
{tex}\tan A = \frac { \text { Perpendicular } } { \text { Base } } = \frac { 1 } { 3 } , \quad \sec A = \frac { \text { Hypotenuse } } { \text { Base } } = \frac { \sqrt { 10 } } { 3 }{/tex}.
and, {tex}\cot A = \frac { \text { Base } } { \text { Perpendicular } } = \frac { 3 } { 1 } = 3{/tex}

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ANSWER

A dice is thrown, the probability of getting number less than 4 is x and probability of getting number more than 4 is y, what is the total probabity of getting x-y

Posted by Samridhi Yadav 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Omprakash Bishnoi 7 years, 1 month ago

1/6

1Thank You

ANSWER

TanA = √3-1 then find sinA.cosA =?

Posted by Samridhi Yadav 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Expres An of an AP in term of Sn and Sn-1

Posted by Soumajit Karak 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Vivek Singh 7 years, 1 month ago

Any one

0Thank You

Vivek Singh 7 years, 1 month ago

Short

1Thank You

ANSWER

If one zero of the polynomial (a^2+ a)X^2+ 13 x + 6 x A reciprocal is other •find the value of a

Posted by Poonam Jyoti 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let {tex} \alpha{/tex} and {tex} \frac { 1 } { \alpha }{/tex} be the zeros of (a²+ 9)x²+ 13x + 6a.
Then, we have
{tex} \alpha \times \frac { 1 } { \alpha } = \frac { 6 a } { a ^ { 2 } + 9 }{/tex}
⇒ 1 = {tex} \frac { 6 a } { a ^ { 2 } + 9 }{/tex}
⇒ a² + 9 = 6a
⇒ a² - 6a + 9 = 0
⇒ a² - 3a - 3a + 9 = 0
⇒ a(a - 3) - 3(a - 3) = 0
⇒ (a - 3) (a - 3) = 0
⇒ (a - 3)²= 0
⇒ a - 3 = 0
⇒ a = 3
So, the value of a in given polynomial is 3.

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ANSWER

can anyone.give me an innovative idea for maths exhibition class 10

Posted by Krish Rawat 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Mitali Sabale 7 years, 1 month ago

Trigonometric ratios

0Thank You

Satwik Megeri 7 years, 1 month ago

Theorems

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ANSWER

Exercise 8.4 q.3 1,2

Posted by Aditya Dwivedi 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Poonam Jyoti 7 years, 1 month ago

Ncert book

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ANSWER

(1/2+3/3/8/5+11/14+5/2-1/1)÷5/2of5/2of19/7

Posted by Harsh Bardhan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The circumference of two circle are in the ratio 2:3.find the ratio of their areas

Posted by Akash Mishra 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Omprakash Bishnoi 7 years, 1 month ago

4:9

0Thank You

ANSWER

Show that any positive even integer is of the form 2q and that even positive odd integer is of the form 2q+1, where q is some integer

Posted by Abhishek Kumar 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Guru Patel 7 years, 1 month ago

R=2 2q=2 is even no. 2q+1=3 is odd no. 2q+2 =4 is even no.

2Thank You

Guru Patel 7 years, 1 month ago

R=2 2q=2 is even no.

1Thank You

Abhishek Kumar 5 years, 8 months ago

Dhbuzwyv3

1Thank You

ANSWER

A Japanese fan can be made by sliding open it's 7 small sections is of which is in the form of a sector of a circle having Central angle of 15 degree if the radius of the pen is 24cm find out the length of the laces that is required to entire boundary

Posted by Kavita Sanjay 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

secQ + tanQ =m SecQ +tanQ =n Show that mn=1

Posted by Shreya Gupta 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Vinutha Lohithesh 7 years, 1 month ago

(secQ+tanQ)(tanQ-secQ) -Sec²Q+secQtanQ-secQtanQ+tan²Q =Tan²Q-sec²Q=1

0Thank You

Vinutha Lohithesh 7 years, 1 month ago

The question is not correct It is secQ+tanQ=m and secQ-tanQ=n

1Thank You

ANSWER

What is concentric

Posted by Rizwan Alam 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Omprakash Bishnoi 7 years, 1 month ago

the circles which drawn from same centre

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Purvanshi Yadav 7 years, 1 month ago

Circles with same centre

3Thank You

ANSWER

What is modal class?

Posted by Garima Demla 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Garima Demla 7 years, 1 month ago

So...if we are given a question in which we have a table with wages like less than 10 ,less than 20 ,less than 30 ,less than 40 ,less than 50,and less than 60 with their respective no. of students like 2 ,11,25,45,57,75.....so here what is the modal class ..."75" or "less than 60"???

0Thank You

Guru Patel 7 years, 1 month ago

Modal is highest no. Of frequency

2Thank You

Bhavay Khanna 7 years, 1 month ago

Mode

3Thank You

ANSWER

Prove that 2 equilateral triangles are similar

Posted by Purvanshi Yadav 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Omprakash Bishnoi 7 years, 1 month ago

angles of equilateral triangle are equal than ABC~PQR by sss rule

1Thank You

Pragati ... 7 years, 1 month ago

Equilateral triangles have equal sides so that all angles are equal let one triangle is ABC And another is PQR <A =<P <B=<Q <C=<R By AAA criterian similarity Triangle ABC~triangle PQR Hence Proved

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ANSWER

want to understand completing square method in an easy way

Posted by Ritesh Nirman 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Rohan Patil 7 years, 1 month ago

Yea

1Thank You

ANSWER

ABC is an ososceles triangle right angled at B two equilateral triangle BDC and AEC are constructed with side BC and AC prove that area of teiangle BCD = 1/2 area of triangle ACE

Posted by Priyanshu Sinha 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let AB = x, BC = x

Area of an equilateral triangle of side a = {tex}\frac { \sqrt { 3 } } { 4 }{/tex}a²
Area of {tex}\triangle{/tex}BCD = {tex}\frac { \sqrt { 3 } } { 4 }{/tex}x² ..(i)
Now side AC = {tex}\sqrt { x ^ { 2 } + x ^ { 2 } } = \sqrt { 2 x ^ { 2 } } = x \sqrt { 2 }{/tex} (by pythagoras theorem)
Area of {tex}\triangle{/tex}ACE = {tex}\frac { \sqrt { 3 } } { 4 } ( \sqrt { 2 } x ) ^ { 2 }{/tex} = 2
{tex}\frac { \sqrt { 3 } } { 4 }{/tex}x² = 2. Area of BCD [from (i)]
{tex}\therefore{/tex} ar{tex}\triangle{/tex}BCD = {tex}\frac{1}{2}{/tex}area of {tex}\triangle{/tex}ACE.