CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Since mean of 20 observations is 12
Sum of the 20 observations = 12 {tex}\times{/tex} 20 = 240
New sum of 20 observations = 240 +(5 x 20) = 420 + 100 = 520
New mean = 520/20 = 26

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Integral ka matlab

Posted by Aman Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

..... ...... 7 years, 1 month ago

Integration or anti derivatives. It is in class 12.

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If x=-1 ,p(x)=2x°2+2 find it's factors

Posted by Mumaiz Peer 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Aman Singh 7 years, 1 month ago

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A sum of Rs 3750 is to be used to give ten cash prize to the student of a school for their overall academic performance . If each prive is Rs 50 less than the preceeding prize,find the value of each prize

Posted by Karan Patil 7 years, 1 month ago

CBSE > Class 10 > Mathematics

0 answers

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Ncert example 5 chapter 2 koi bta do

Posted by Aman Bhatt 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Nishant Ranjan 7 years, 1 month ago

Hard aur long dheak kar mat daro ye question aacha se padho samaj me aa jayega simple hai

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Find the value of a for which the point p(a/3,2) is the midpoint of the line segment joining the points Q(-5,4) R(-1,0)

Posted by Alfas Basheer 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

P is midpoint of QR
or, {tex}\frac { a } { 3 } = \frac { - 5 + ( - 1 ) } { 2 }{/tex}
or, {tex}\frac { a } { 3 } = \frac { - 6 } { 2 }{/tex}
or, a = -9

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split 207 into 3 parts such that these are in ap and product of the smaller parts is 4623

Posted by Madhav Jha 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let the four parts be (a - d), a and (a + d).
{tex}\therefore{/tex} a - d + a + a + d = 207
{tex}\Rightarrow{/tex} 3a = 207
{tex}\Rightarrow{/tex} a = 69
According to given information,
{tex}\Rightarrow ( a - d ) \times a = 4623{/tex}
{tex}\Rightarrow ( 69 - d ) \times 69 = 4623{/tex}
{tex}\Rightarrow{/tex} 69 - d = 67
{tex}\Rightarrow{/tex} d = 2
Thus, the three parts are a - d, a, a+ d i.e., 67, 69, 71.

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Sum of the areas of two squares is 468m,335

Posted by Sana Usmani 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Junaid Mansoori 7 years, 1 month ago

wHAT IS QUESTION..Explain it

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Pb solving

Posted by Adarsh Chouhan 7 years, 1 month ago

CBSE > Class 10 > Mathematics

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9x2-9 (p+q)x+(2p2+5pq+2q2)

Posted by Tanishka Gupta 7 years, 1 month ago

CBSE > Class 10 > Mathematics

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Make projects on probability

Posted by Sandhya Singh 7 years, 1 month ago

CBSE > Class 10 > Mathematics

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Therom 10.1

Posted by Dhanvi Dave 7 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Vaibhav Parmar 7 years, 1 month ago

see on your maths book

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Aditya Kumar 7 years, 1 month ago

Very easy theorem

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Guys kya maths ke do paper hoge means standard level or higher level

Posted by Abdul Wajid Malik 7 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Disha Rathore 7 years, 1 month ago

They will be from the session 2019-2020

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Aditya Kumar 7 years, 1 month ago

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Ajay Somra 7 years, 1 month ago

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Solve by using formula method a(x^2+1)=x(a^2+1)

Posted by Keerthi Manjunath 7 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Hardik Panwar 7 years, 1 month ago

= ax2 + a - xa2 - x = ax2 - xa2 - x + a = ax(x - a) - 1(x - a) = (x - a)*(ax - 1) To find roots, we have to equate (x - a) = 0 and (ax - 1) = 0 So, x - a = 0 and ax - 1 = 0 => x = a, ax = 1 => x = a, 1/a

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Prove that the diameter Ab of a circle bisects all those chords which are parallel to the tangent at point A

Posted by Uma Tiwari 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Aditya Kumar 7 years, 1 month ago

Draw a circle and a diameter AB. PC is a tangent which touches the circle at A. And DE is a tangent touches circle at B. By theorem 10.1 Angle A is 90 degree so by alternate interior angle angle B is also 90 degree so by this line is parallel to each other

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1,4,9,16,25 are in A.P are not?

Posted by Mumaiz Peer 7 years, 1 month ago

CBSE > Class 10 > Mathematics

6 answers

Nishant Ranjan 7 years, 1 month ago

This is not in AP

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Aditya Kumar 7 years, 1 month ago

Becz common difference [d] is not fix

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Aditya Kumar 7 years, 1 month ago

1Thank You

Feba ????? 7 years, 1 month ago

Obviously no

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Vandana Maurya 7 years, 1 month ago

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..... ...... 7 years, 1 month ago

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Places A and B are 80 km apart from each other on highway.A car starts from A and another from B at the same time if they move in same Direction they meet in 8 hours and if they move towards Each Other they meet in 1 hour 20 minutes find the speed of cars

Posted by H. K. Mehra 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Suppose x and y be two cars starting from points A and B respectively.
Let the speed of the car X be x km/hr and that of the car Y be y km/hr.
Case I: When two cars move in the same directions:
Suppose two cars meet at point Q, then,
Distance travelled by car X = {tex}AQ{/tex}
Distance travelled by car Y = {tex}BQ{/tex}
Distance travelled by car X in 8 hours = 8x km.
{tex}AQ = 8x{/tex}
Distance travelled by car Yin 8 hours = 8y km.
{tex}BQ = 8y{/tex}
Clearly {tex}AQ - BQ = AB{/tex}
{tex}8x - 8y = 80{/tex}
{tex}\Rightarrow {/tex} {tex}x - y = 10{/tex} ...(i)
Case II: When two cars move in opposite direction
Suppose two cars meet at point P, then,
Distance travelled by X car X = AP
Distance travelled by Y car Y = BP
we can write it as 1 hour = {tex}\frac{{20}}{{60}}{/tex}hours.
Therefore, Distance travelled by a car Y in {tex}\frac{4}{3}{/tex}hrs = {tex}\frac{4}{3}{/tex}x km.
AP + BP = AB
{tex}\frac{4}{3}x{/tex} km + {tex}\frac{4}{3} y{/tex} km = 80
{tex}\frac{4}{3}{/tex}{tex}(x + y) = 80{/tex}
{tex}( x + y ) = 80{/tex} × {tex}\frac{3}{4}{/tex}
{tex}x + y = 60{/tex} ...(ii)

By solving equations (i) and (ii), we get, {tex}x = 35.{/tex}
By substituting x = 35 in equation (ii), we get
{tex}x + y = 60{/tex}
{tex}35 + y = 60{/tex}
{tex}y = 60 - 35{/tex}
{tex}y = 25.{/tex}
Hence, speed of car X {tex}= 35\ km/hr.{/tex}
Speed of car Y ={tex} 25\ km/hr.{/tex}