CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Ask questions which are clear, concise and easy to understand.

Ask Question

If ∆FEC≅∆GDB, ∠1=∠2. Prove that ∆ADE~∆ABC

Posted by Veena Katti 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 11 months ago

Given : ∆ FEC ≅ ∆ GBD ,

SO From CPCT

WE GET,

BD = CE ----------------- ( 1 )

ALSO GIVEN : ∠ 1 = ∠ 2 ,

SO FROM BASE

ANGLE THEOREM IN ∆ ADE

WE GET

AD =AE ------------------------ ( 2 )

From equation 1 and 2 we get

ADBD = AECE , So from converse of B.P.T. we get

DE | | BC

THEN ,

∠ 1 = ∠ 3
( CORRESPONDING ANGLES AS DE | | BC AND AB IS TRANSVERSAL LINE )

AND

∠ 2 = ∠ 4 ( CORRESPONDING ANGLES AS DE | | BC AND AC IS TRANSVERSAL LINE )

FROM ABOVE TWO EQUATIONS WE CAN SAY THAT :

∆ ADE ~ ∆ ABC ( ByAArule )
( Hence proved )

1Thank You

ANSWER

Ch.13 (13.4)Surface Area and Volumes ! Q.5 A metallic right circular cone 20cm high and whose Vertical angle is 60 is cut into two parts at the middle of its height by a plane parallel to its base .If the frustum so obtained be drawn into a wire of diameter 1/16 cm, find the length of the wire.

Posted by Mayank Yadav ? 6 years, 11 months ago

CBSE > Class 10 > Mathematics

4 answers

Gaurav Seth 6 years, 11 months ago

Solution: Volume of frustum will be equal to the volume of wire and by using this relation we can calculate the length of the wire.

In the given figure; AO = 20 cm and hence height of frustum LO = 10 cm

In triangle AOC we have angle CAO = 300 (halft of vertical angle of cone BAC)

Therefore;

tan30°=OCAO

Or, 1√3=OC20

Or, OC=20√3

Using similarity cirteria in triangles AOC and ALM it can be shown that LM=10√3(because LM bisects the cone through its height)

Similarly, LO = 10 cm

Volume of frustum can be calculated as follows:

V=13πh(r21+r22+r1r2)

=13π×10[(20√3)2+(10√3)2+20√3×10√3]

=13π×10(4003+1003+2003)

=70009 π cm3

Volume of cylinder is given as follows:

=πr2h

Or, π(132)2×h=70009 π

Or, h=70009×1024

=796444.44 cm=7964.4 m

3Thank You

Anwaya Kumar Nayak 6 years, 11 months ago

Sune puja mu rati re hi pathei paribi ebe nuhen mora ebe tution achi BYE?????

2Thank You

Chetna Pandey 6 years, 11 months ago

Puja ji niche aa jao

2Thank You

Chetna Pandey 6 years, 11 months ago

Check this app go to ncert solution....

3Thank You

ANSWER

Find the area of the shaded region in where ABCD is a square of side 14 cm

Posted by Prasoon Kaushik 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

. . 6 years, 11 months ago

Type karne se pehle ques. dekh le bhai.

0Thank You

Anushka Jugran ? 6 years, 11 months ago

Where is the shaded regions????

1Thank You

ANSWER

Surface area and volume ke formulas class 10th

Posted by Anurag Khatri 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Check revision notes for formulae : <a href="https://mycbseguide.com/cbse-revision-notes.html">https://mycbseguide.com/cbse-revision-notes.html</a>

0Thank You

ANSWER

If p(x, y) is any point on the line joining the points A( a, 0) and B ( 0,b) then show that x/a + y/b = 1

Posted by Priya Shrma 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Priya Shrma 6 years, 11 months ago

plz solve this question for me quickly ?, I have to prepare for my maths exam which is on Tuesday. Plz someone help me ?

0Thank You

ANSWER

If the pth term of an A. P is a and qth term is b, then show that the sum of its first (p+q) th term is p+q/2(a+b+a-b/p-q)

Posted by Nasib Tamak 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let A be the first term and D be the common difference of the given AP. Then,
T_p= a {tex}\Rightarrow{/tex} A + (p - 1) D = a ...(i)
and T_q = b {tex}\Rightarrow{/tex} A + (q - 1) D = b ...(ii)
On subtracting Eq. (ii) from Eq. (i), we get
(p - q) D = a - b {tex}\Rightarrow{/tex} D = {tex}\frac { a - b } { p - q }{/tex} ...(iii)
On adding Eqs. (i) and (ii), we get
2A + (p + q - 2) D = a + b
{tex}\Rightarrow{/tex} 2A + pD + qD - 2D = a + b
{tex}\Rightarrow{/tex} 2A + pD + qD - D = a + b + D
{tex}\Rightarrow{/tex} 2A + (p + q - 1) D = a + b + D
2A + (p + q - 1) D = a + b + {tex}\left( \frac { a - b } { p - q } \right){/tex} [from Eq. (iii)] ...(iv)
Now, S_p+q = {tex}\frac { p + q } { 2 }{/tex} [2A + (p + q - 1) D]
= {tex}\frac { p + q } { 2 }{/tex} [a+ b + {tex}\frac { a - b } { p - q }{/tex}] [from Eq. (iv)]
Hence proved.

0Thank You

ANSWER

If the sum of root of the aquation 3x square-(3k-2)x-(k-6) is equal to the produt of its root ,then find k

Posted by Kuldeep Malik 6 years, 11 months ago

CBSE > Class 10 > Mathematics

7 answers

Anushka Jugran ? 6 years, 11 months ago

K is equal to 2

0Thank You

Anwaya Kumar Nayak 6 years, 11 months ago

K=2

0Thank You

Raj Kumar 6 years, 11 months ago

K=2

1Thank You

Raj Kumar 6 years, 11 months ago

K=-2

0Thank You

Anwaya Kumar Nayak 6 years, 11 months ago

Are puja amara 1st box re kiye jane amaku gali dauchi jaldi dekh

1Thank You

Puja Sahoo? 6 years, 11 months ago

K=2

1Thank You

Kartikay Gautam 6 years, 11 months ago

What is the answer of this Q?

1Thank You

ANSWER

Please provide solution. a cubic polynomial f(x) is such that cofficient of x^3 is -1 and its zeros are 1,2 & k . . if f(x) is divided by x-3, then find x

Posted by Anshika Pathak 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Gulafsha Naaz 6 years, 11 months ago

1Thank You

ANSWER

Prove that cotthita _ tan thita=2cos square thita _1÷sin thita cos tjita

Posted by Sulinder Kamboj 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Anwaya Kumar Nayak 6 years, 11 months ago

Very good puja you are hardworking and helpful also

1Thank You

Puja Sahoo? 6 years, 11 months ago

cot theta - tan theta cos theta/sin theta-sin theta/cos theta cos²theta-sin²theta/sin theta * cos theta cos²theta-1(1-sin²theta) /sin theta * cos theta cos²theta-1+cos²theta/sin theta*cos theta 2cos²theta-1/sin theta*cos theta Hence Proved.

2Thank You

ANSWER

What is the value of sin30

Posted by Sonu Kumar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

4 answers

Anushka Jugran ? 6 years, 11 months ago

1/2

0Thank You

Gajal Kumawat 6 years, 11 months ago

Value of sin 30- 1/2.

0Thank You

Ragini Jha? 6 years, 11 months ago

1/2

0Thank You

Vidhi Lalwani? 6 years, 11 months ago

U wil get it in Ncert text book

0Thank You

ANSWER

Check whether the following are quadratic equations (x-2)^2+1=2x-3

Posted by Arif Khan 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The angles of depression of the top and the bottom of an 8m tall building from the top of multi-storeyed building are 30 degree and 45 degree respectively find the height of the multi storeyed building and the distance between the two buildings.

Posted by Puna Ram 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

S.P Singh 6 years, 11 months ago

Height of multi story building and distance between two buildings = 4(3+√3)

1Thank You

ANSWER

What is the formula of distance formula

Posted by Ritik Singh 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

S.P Singh 6 years, 11 months ago

√(x2-x1)^2+(y2-y1)^2

1Thank You

Amitesh Gupta 6 years, 11 months ago

Distance = under root (x-y)^2 + (x1-y1)^2

0Thank You

ANSWER

For what value of p x=b is azero ofthe polynomial x2-a

Posted by Aby Joyan 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

√5 is irrational .prove (3-√5)is irrational

Posted by Logan Logan 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Puna Ram 6 years, 11 months ago

Let 3-_/5 be rational and co prime 3-_/5=a/b Therefore,3- a/b=_/5 _/5 = 3-a/b = 3b - a/b Since a and b are integers , we get 3 - a/b is rational, and so _/5 is rational But this contradicts the fact that _/5 is irrational. This contradiction has arison because of our incorrect assumption that 3 -_/5 is rational. So, we conclude that 3-_/5 is irrational.

1Thank You

Prerika Lamba 6 years, 11 months ago

See in ncert book in chapter 1examples

0Thank You

ANSWER

For the following distribution Mark below10 below20 below30 below40 below50 below60 No. Of students 3 12 27 57 75 80 Find the modal class

Posted by Himanshu Chaudhary 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Speed of a boat in still water is 15km/h it goes 30km upstream and return back at the same point in 4 hours 30 minute . Find the speed of the stream

Posted by Jyoti Sahni 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let the speed of the Stream be x km/hr.
{tex}\therefore {/tex} Speed of boat up stream = 15 - x
and speed of boat down stream = 15 + x
now according to the question

{tex}\frac { 30 } { 15 - x } + \frac { 30 } { 15 + x } = 4 \frac { 1 } { 2 }{/tex}

{tex}\frac { 30 ( 15 + x ) + 30 ( 15 - x ) } { 15 ^ { 2 } - x ^ { 2 } } = \frac { 9 } { 2 }{/tex}

{tex}900 \times 2 = 9 \left( 15 ^ { 2 } - x ^ { 2 } \right){/tex}

{tex}9 x ^ { 2 } = 2025 - 1800{/tex}

{tex}x ^ { 2 } = \frac { 225 } { 9 }{/tex}

{tex}x ^ { 2 } = 25 = \pm 5{/tex}

x = 5
Hence, the speed of the stream = 5 km/hr.

0Thank You

ANSWER

1/2a+b+2x=1/2a+1/b+1/2x Value of x=?

Posted by Ankita ?? Arpita☺️ 6 years, 11 months ago

CBSE > Class 10 > Mathematics