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  • 2 answers

Yogita Ingle 6 years, 11 months ago

Let us assume that √3 is a rational number
That is, we can find integers a and b (≠ 0) such that √3 = (a/b)
Suppose a and b have a common factor other than 1, then we can divide by the common factor, and assume that a and b are coprime.
√3b = a
⇒ 3b2=a2 (Squaring on both sides) → (1)
Therefore, a2 is divisible by 3
Hence ‘a’ is also divisible by 3.
So, we can write a = 3c for some integer c.
Equation (1) becomes,
3b2 =(3c)2
⇒ 3b2 = 9c2
∴ b2 = 3c2
This means that b2 is divisible by 3, and so b is also divisible by 3.
Therefore, a and b have at least 3 as a common factor.
But this contradicts the fact that a and b are coprime.
This contradiction has arisen because of our incorrect assumption that √3 is rational.
So, we conclude that √3 is irrational.

Afzal Siddique 6 years, 11 months ago

Root3=irrational no. Hence proved.
  • 1 answers

Priyanka S 6 years, 11 months ago

(x-1)(x-1/2) solve this and divide the polynomial by the equation solved u will get the other zeroes
  • 0 answers
  • 1 answers

Roshan Meshram 6 years, 11 months ago

Let the speed of boat. X km/h The speed of boat in upstream= (24-x)km/h The speed of boat in downstream =. (24+x)km/h 24÷(24-x). 24(24+x). Multiples both sides X squares+48x-324=0. X commen (X+56) (x-6) X#0 x=0 Hence the speed of the boat is 6km/h
  • 1 answers

Navneet Verma 6 years, 11 months ago

A.P : 3,9,15,------------999. Here a= 3, d=6, An = 999. An= a+ (n-1)d 999=3 + ( n-1)6 999=3+ 6n - 6 999 = 6n- 3 999+3=6n 1002=6n 1002/6=n 167=n. Sn = n/2 [2a+(n-1) d ] S167 = 167/2 [2×3+(167-1)×6] = 167/2 [6+166×6] = 167/2 [1002] = 167/2× 1002 =167×501 = 83667. Hence proved
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  • 1 answers

Sia ? 6 years, 4 months ago

BC = 3 cm, AC = 4 cm and {tex}\triangle ACB\sim \triangle PAO{/tex}
In {tex}\triangle ACB{/tex},

{tex}\angle BCA=90^o{/tex} [angle in a semi-circle]

{tex}\therefore {/tex} AB2 = AC2 + BC2 [By Pythagoras theorem]

{tex}\Rightarrow{/tex} AB2 = 42 + 32
{tex}\Rightarrow{/tex} AB2 = 16 + 9 cm
{tex}\Rightarrow{/tex} AB2 = 25 cm
{tex}\Rightarrow{/tex} AB = 5 cm
{tex}\Rightarrow OA =\frac{AB}{2} =\frac{5}{2}cm{/tex}

Also given, {tex}\triangle ACB\sim \triangle PAO{/tex}

{tex}\therefore \frac{AB}{AC}=\frac{OP}{AP}{/tex}
{tex}\Rightarrow \frac{OP}{AP}=\frac{5}{4}{/tex}

  • 1 answers

Rohit Yadav 6 years, 11 months ago

A decimal is a fraction that is written in the form of a dot followed by one or more numbers which represent tenths, hundredths, and so on
  • 7 answers

Shriya ?? 6 years, 11 months ago

do u understand (fam is nothing i was just confusing u)

Shriya ?? 6 years, 11 months ago

i hope good give u power to understand the meaning of this and all the best for your exam

Neeraj 17_ 6 years, 11 months ago

1 thing i ask from u

Shriya ?? 6 years, 11 months ago

what can i ask no ques . but if u want to ask then u can ask

Shriya ?? 6 years, 11 months ago

okay

Neeraj 17_ 6 years, 11 months ago

?

Avinash Saigal 6 years, 11 months ago

T^2 -10=0 T^2 = 10 T = √10 T = +_ 10 That is T has two value either 10 or -10. Thank you??
  • 6 answers

Shriya ?? 6 years, 11 months ago

no

Shriya ?? 6 years, 11 months ago

okay

Shriya ?? 6 years, 11 months ago

maths ka paper aacha nahi hua kya???

Shriya ?? 6 years, 11 months ago

law

Neeraj 17_ 6 years, 11 months ago

11 which subj

Neeraj 17_ 6 years, 11 months ago

What
  • 2 answers

@Jay Bunkar 6 years, 11 months ago

K=5

Priya Sharma 6 years, 11 months ago

Value of k
  • 1 answers

Gaurav Seth 6 years, 11 months ago

Q.SinA-cosA+1/sinA+cosA-1=tanA-1+secA/tanA+1-secA

<hr />

Answer:

  • 1 answers

Allan Krish 6 years, 11 months ago

Mode=3median-2mean
  • 0 answers
  • 4 answers

Sonu 6 years, 11 months ago

1/3 PIE ×HEIGHT (R ^2+ r^2+Rr)

@ Aashu 6 years, 11 months ago

1/3pie h ( r2 + R 2 + r.R )

Aarohi Singh 6 years, 11 months ago

Ťhanks?

Rahul Raj 6 years, 11 months ago

1/3πh(R^2 + r^2 +Rr)
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  • 2 answers

Rahul Raj 6 years, 11 months ago

Now solve your self

Rahul Raj 6 years, 11 months ago

For equal roots , b^2 -4ac =0
  • 1 answers

Anjani Kumar Singh 6 years, 11 months ago

a+b^3-3ab(a+b)
  • 1 answers

Priyanka S 6 years, 11 months ago

13/21
  • 1 answers

Janhvi Bora 6 years, 11 months ago

Surface area and volume rd sharma mein kya nahi aara hai???
  • 3 answers

Neha Sirur 6 years, 11 months ago

Perimeter =4x Diffrence is 24 4x=24+4x X=x+6 which is the length of each side Sum of areas is 468m2 X^2+ (6+x)^2= 468 X^2+6x-216=0 Solve it ans is 18 and 12

Puja Sahoo? 6 years, 11 months ago

18m, and 12m.its ncert question yu can check in this app.

Neha Sirur 6 years, 11 months ago

It is ncert text bk question exercise 4.3
  • 3 answers

Neha Sirur 6 years, 11 months ago

Is it 5 to the power 2x???

Varun Punia 6 years, 11 months ago

It may be quadratic equation

Varun Punia 6 years, 11 months ago

Plz answe
  • 1 answers

Avinash Saigal 6 years, 11 months ago

assume that 5-2 root 3 is rational 5-2 root 3 = a/b , where a and b are integers .  -2 root 3 = a/b - 5 2 root 3 = 5 - ab  2 root 3 = 5b/b - a/b root 3 = 5b - a / 2b we know that a, b , 2 and 5 are integers and they are also rational  therefore root 3 will be rational  but we know that root 3 is irrational there is a contradiction so, 5 - 2 root 3 is an irrational number. Thank you??

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