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  • 2 answers

Gaurav Seth 6 years, 11 months ago

Let the vertices of triangle be A(1, -1), B(-4, 6) and C(-3, -5).
Then we have
x1 = 1, y1 = -1
x2 = -4, y2= 6
and x3= -3, y3 = -5

Puja Sahoo? 6 years, 11 months ago

24 square meters.......
  • 1 answers

Dhruv Aseri 6 years, 11 months ago

No rational
  • 2 answers

Mansi Gupta 6 years, 11 months ago

Sin^2(90-67)° -Sin^2 23° Sin^2 23°-Sin^2 23° 0

Harsh Garg 6 years, 11 months ago

Ans is 0 As Cos²67°-cos²67° = 0 [Sin(90-theta)=cos theta]
  • 3 answers

Nikita Bagh 6 years, 11 months ago

Write the question properly.☝

Puja Sahoo? 6 years, 11 months ago

Plz, check yur question.......

Rohit Sahani? 6 years, 11 months ago

I don't understand your question.
  • 6 answers

Shashikant ? 6 years, 11 months ago

Dear Puja Sahoo, area of A(6,3), B(-3,5) and C(4,-2) will be 1/2 * {6(5+2) -3(-2-3)+4(3-5)} = 1/2 * (42 + 15 - 8) = 1/2 * 49 sq units Now area of triangle PBC with (x,y) (-3,5) (4,-2) will be 1/2 * {x(5+2) -3(-2-y)+4(y-5)} = 1/2 * (7x + 7y - 14) = 7/2 * (x+y-2) sq units Hence area ? PBC / area ? ABC = 7/2 * (x + y - 2) / 49/2 So required ratio = (x + y - 2) / 7 ]proved]

Puja Sahoo? 6 years, 11 months ago

Naaa........repeat the question again......

Shashikant ? 6 years, 11 months ago

Nahi...kal ke question ka answer hai. 100m distance..okkk

Puja Sahoo? 6 years, 11 months ago

Agar, solve ho jaye ,to plz ap bata dena........

Puja Sahoo? 6 years, 11 months ago

Apke, kl ke question ka answer hai, ................-200 root 3/3. Correct hai na.....

Puja Sahoo? 6 years, 11 months ago

The coordinates of A, B, C are (6,3),(-3,5)&(4,-2)respectively and P is any point (x, y). show that the ratio of the areas of triangle PBC and ABC is [x+y-2/7]..............solve this.....
  • 1 answers

Sarthak Paliwal 6 years, 11 months ago

When you plot this point quadrilateral and join any two point as a diagonal.you will get two traingles then by joining the area of two triangle you will get area of quadrilateral. I am not giving u solution because you should try to solve it
  • 3 answers

Chetna Pandey ? 5 years, 8 months ago

30°

Yaser Siddiquee 6 years, 11 months ago

√3 sinΦ = cosΦ => √3 = cosΦ/sinΦ => cot30 = cotΦ (cot30 = √3) Therefore, Φ = 30 degree

Surendrapal Singh Singh Gaur 6 years, 11 months ago

Theeta =30°
  • 4 answers

Kshitij Vats 6 years, 11 months ago

Pls dont study at the last time as it will make you confeuse and ?all the best?

Chetna Pandey ? 6 years, 11 months ago

Just do practice......

Divanshu Rawat 6 years, 11 months ago

In proving identities questions first read the question carefully and cjoose what step you should taken . Change all th value in sin ans cos in mostly qusetions

Surendrapal Singh Singh Gaur 6 years, 11 months ago

As the whole concept is primarily based on NCERT so u must practise ncert questions quite well and thus learn the application of identities. BEST OF LUCK btw ?.
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  • 1 answers

Akshita Khandelwal 6 years, 11 months ago

i also have a doubt in dis pls guys help me....
  • 1 answers

Sarthak Paliwal 6 years, 11 months ago

You can prove it by congruency rule i.e. Given in ncert page no. 211
  • 1 answers

Sia ? 6 years, 6 months ago

Let a be the first term and d be the common difference of the given AP. Then,
Sn= {tex}\frac{n}{2}{/tex}{tex} \cdot {/tex}[2a+(n-l)d],
{tex}\therefore{/tex} {tex}3(S_8-S_4) = 3{/tex}[{tex}\frac{8}{2}{/tex}{tex}(2a+7d)-{/tex}{tex}\frac{4}{2}{/tex}{tex}(2a+3d)]{/tex}
= {tex}3[4(2a+7d)- 2(2a+3d)] = 6(2a+11d){/tex}
{tex}= \frac { 12 } { 2 } \cdot ( 2 a + 11 d ) = S _ { 12 }{/tex}.
Hence, S12= 3(S8-S4).

  • 1 answers

Sia ? 6 years, 4 months ago

{tex}a_1 = 3x + y {/tex}and {tex}d = x - y{/tex}
{tex}a_2 = a_1 + d = 3x + y + x - y = 4x{/tex}
{tex}a_3 = a_2 + d = 4x + x - y = 5x -y{/tex}
{tex}a_4 = a_3 + d = 5x - y + x - y = 6x -2y{/tex}
So, the four terms are {tex} 3x + y, 4x, 5x - y {/tex} and{tex} 6x - 2y{/tex}.

  • 1 answers

Raj Dhali 6 years, 11 months ago

PQ^2 = x-4 PQ=√x-4 evaluation=√7/√x-4 × √x-4/√x+3 × √x+3/√7 - 0(since cos90 is 0) =1-0=1
  • 5 answers

Mansi ??⚘?? 6 years, 11 months ago

The first four terms of an A.P is 3x + y , 4x, 5x - y & 6x - 2y

Sankalp Awasthi 6 years, 11 months ago

By the way what's the ans i wanna know....may be mine is correct

Sankalp Awasthi 6 years, 11 months ago

Perhaps.....3x+y...4x.....5x-y.....-2y.....

Mansi ??⚘?? 6 years, 11 months ago

Sorry it is first four terms

Sankalp Awasthi 6 years, 11 months ago

What u want to ask first term or nth term
  • 1 answers

Raj Dhali 6 years, 11 months ago

a and b have least prime factor an odd no. Hence both are odd no.so,a+b=odd+odd which is even.all even have least prime factor 2.hence least prime factor of a+b is 2
  • 0 answers
  • 1 answers

Amaan Sheikh 6 years, 11 months ago

-100,-98.........-2 Now find common difference a2-a1 =-98-(-100) -98+100 d=2 Now find the 12th term a+(n-1)d -100+(12-1)2 -100+22 -78 answer
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  • 2 answers

Abc . 6 years, 11 months ago

Are you asking about that sample papers which are provided by this app then you must have to buy sample papers as you have bought earlier sample paper 2-4.

Jot Virk?♠ 6 years, 11 months ago

What is ur querry

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