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By using the formula of area of triangle 1/2{(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}. Area of triangle=0{because points are collinear}. We get the value of x.

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For what value of p,x=b is a zero of polynomial x^2-(a+b)x+a(p-2b)?

Posted by Mohammad Kaif 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Neha Sirur 6 years, 11 months ago

P=3b

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Maths compartment solution lat year paper

Posted by Nitin Yadav 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

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Which term of Ap will be zero 24,21,18,15....?

Posted by Aditya Kumar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Chhavi Sharma 6 years, 11 months ago

a=24 d=-3 a(n) =0 0=a+(n-1)d 0=24+(n-1)×-3 -24/-3=(n-1) 8+1=n n=9

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CosA/1+sinA + 1+SinA/cosA= 2secA

Posted by Samriddhi Shrivastava 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Baamaa'S Beta 6 years, 11 months ago

CosA 1+sinA ---------- + ----------- = 2secA 1+ SinA cos A cos^2 + (1+sinA)^2 -------------------------- (1+sinA)(cosA) Cos^2 + 1+ sin^2 +2sinA ---------------------------------------- (1+sinA)(cosA) 2(1 + SinA) ------------------- (+sinA)(cosA) =2/cosA =2secA ♡♡♡

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1+secA/SecA = sin²A/1-cosA prove

Posted by Samriddhi Shrivastava 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ruhi Fatima 5 years, 2 months ago

I don't now the answer

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Which term of the AP 3, 15, 27, 39,.....will be 132 more than its 54th term?

Posted by Jaanvi Singh 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

S.P Singh 6 years, 11 months ago

After now it will be 132+639=771

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S.P Singh 6 years, 11 months ago

A = 3
n = 54
d = 12
we know that
a + ( n - 1 ) d
= 3 + ( 54 - 1 ) 12
= 3 + 53 × 12
= 3 + 636
= 639
Now
32 + 639 = 771
771 = 3 + (n - 1) 12
768/12 + 1 = n
64 + 1 = n
n = 65
Therfore 65th term term 132 more than 54th term.

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The Numerator of a fraction is 3 less than its denominator.If 2 is added to both the Numerator and the denominator,then the sum of the new fraction and original fraction is 29/20.find the original fracrion

Posted by Sankar Naveen 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Kumar 6 years, 11 months ago

The value of root 5 minus 5 1.5 47000

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AD is an altitude of a equilateral triangleABC on AD as a base another equilateral triangleADE is constructed Ar(ADE):Ar(ABC)

Posted by Sri Kumar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 11 months ago

Guess the question is incomplete.

The solution is as per this question:

Question:AD is an altitude of an equilateral triangle ABC. On AD as a base,another equilateral triangle ADE is constructed.Prove that area(ADE):area(ABC)=3:4.

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We have,
ΔABC is an equilateral triangle
Then, AB = BC = AC
Let, AB = BC = AC = 2x
Since, AD ⊥ BC then BD = DC = x
In ΔADB, by Pythagoras theorem

By area of similar triangle theorem

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Solve by substitution method 3x-y=3 9x-3y=9

Posted by Niharika Niharika 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Gaurav Seth 6 years, 11 months ago

Given,

3x - y = 3,.............(i)

9x - 3y = 9............(ii)

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Harshit Khandelwal 6 years, 11 months ago

It has Infinite many Solutions

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Two horses are considered for a race.The probability of selection of the first horse is 14 and that of the second is 13.What is the probability that : (a) both of them will be selected. (b) only one of them will be selected. (c) none of them will be selected.

Posted by Yuvraj Bhati 6 years, 11 months ago

CBSE > Class 10 > Mathematics

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Sec+Tan=p then find cosec

Posted by Deepak Kumar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Devyansh Joshi 45 6 years, 11 months ago

Sec + tan = p ..(1) Using identity sec^-tan^=1 (sec + tan)+(sec- tan)=1 P+(sec - tan)=1 sec-tan=1/p ...(2) Adding(1)&(2)... sec +tan+sec-tan= p+1/p 2sec=p^+1/0 sec= p^+1/2p Put this value in (1) ... P^+1/2p+tan=p tan =p-(p^+1/2p) = 2p^-p^-1/2p =p^-1/2p ( cot = 1/tan = 2p/p^-1) cot = cosec/sec = 2p/p^-1/p^+1/2p =2p/p^-1×p^+1/2p (reciprocal)...... = p^+1/p^-1 ans......

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Cot(90-0)/tan0+cosec(90-0)Sin0/tan(90-0)=sec,20

Posted by Satish Randhir 6 years, 11 months ago

CBSE > Class 10 > Mathematics