CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let a and d be the first term and common difference respectively of the given A.P. Then
a_n = a + (n - 1)d
{tex}\frac { 1 } { n } ={/tex} m^th term
{tex}\Rightarrow \frac { 1 } { n } {/tex}= a + ( m - 1 ) d ...(i)
{tex}\frac { 1 } { m }{/tex}= nth term
{tex}\Rightarrow \frac { 1 } { m } {/tex}= a + ( n - 1 ) d ...(ii)
On subtracting equation (ii) from equation (i), we get
{tex}\frac { 1 } { n } - \frac { 1 } { m } = {/tex} [a+ (m-1) d] -[ a+ (n -1)d]
= a + md - d - a - nd + d
{tex}= ( m - n ) d{/tex}
{tex} \Rightarrow \frac { m - n } { m n } = ( m - n ) d {/tex}
{tex}\Rightarrow d = \frac { 1 } { m n }{/tex}
Putting d = {tex}\frac { 1 } { m n }{/tex} in equation (i), we get
{tex}\frac { 1 } { n } = a + \frac { ( m - 1 ) } { m n } {/tex}
{tex}\Rightarrow \frac { 1 } { n } = a + \frac { 1 } { n } - \frac { 1 } { m n } {/tex}
{tex}\Rightarrow a = \frac { 1 } { m n }{/tex}
{tex}\therefore{/tex} (mn)^th term = a + (mn - 1) d
= {tex}\frac { 1 } { m n } + ( m n - 1 ) \frac { 1 } { m n } {/tex}{tex}\left[ \because a = \frac { 1 } { m n } = d \right]{/tex}
= {tex}\frac { 1 } { m n } + \frac { mn } { m n } - \frac { 1 } { m n }{/tex}
= 1

0Thank You

ANSWER

Kya optional exercise solve karna zaruri hai

Posted by Shivam Tripathi 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Harsh Rohilla❤️??✨ 6 years, 11 months ago

Choice

1Thank You

Raushan Gautam 6 years, 11 months ago

Examination point of view se dekho to jaruri nhi hai Agar knowledge jayada chahiye to jaruri hai

2Thank You

ANSWER

Interval is. 0-10,10-20......... 90-100 No. Of Student are 5,3,4,3,3,4,7,9,7,8 Find mean

Posted by Ramanreet Sandhu 6 years, 11 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If secA+tanA=x thn find value of secA-tanA in terms of x

Posted by Millan Mann? 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayush Tomar 6 years, 11 months ago

1/x

1Thank You

ANSWER

Why the total outcomes of a dice thrown twice is 36

Posted by Monkey.D Luffy 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Tripathi 6 years, 11 months ago

Becoz dice have 6 faces and 6 outcomes

0Thank You

ANSWER

If tan(A+B)=√3 and tan (A+B)= 1\√3;0°<A+<=90°;A>B Find A and B

Posted by Sujan Nepal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Adhya Singh 6 years, 11 months ago

Tan(A+B)=√3. Tan(A-B)=1/√3 Tan(A+B)=Tan60°. Tan(A-B)=tan30° A+B=60°. A-B=30° A+B=60° A-B=30° 2A=90° A=45° A+B=60° 45°+B=60° B=60°-45° B=15°

3Thank You

Janhvi Singh 6 years, 11 months ago

tan(A+B)=tan 60' so A+B=60 similarly Tan(A+B) =tan30' so A + B =30 now solve these equations you will get answers

3Thank You

ANSWER

Find the distance between the following pairs of points. (a,b) , (_a,_b)

Posted by Surbhi Ry 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Sujan Nepal 6 years, 11 months ago

Let a,b be x1, y1 and -a,-b be x2, y2 The distance formula is √(x2-x1)²+ (y2-y1)² √(-a-a)²+(-b-b)² √2a²+2b² 2√a²+b²

2Thank You

ANSWER

Solve the following equation for x : 9 x square - 9(p+q)x+(2p square+5pq+2q square)=0

Posted by Shubham Kumar 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayush Tomar 6 years, 11 months ago

X=2p+q/3 or p+2q/3

0Thank You

ANSWER

Sin2A=2sin A is this true when A= A 0° B 30° C 45° D 60°

Posted by Sujan Nepal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

4 answers

Sujan Nepal 6 years, 11 months ago

Step by step

1Thank You

Shivam Tripathi 6 years, 11 months ago

O how

3Thank You

Sujan Nepal 6 years, 11 months ago

Sir please mention answer properly

0Thank You

..... ...... 6 years, 11 months ago

0°

2Thank You

ANSWER

Find the value of k for which the equation X square + k bracket 2 X + K - 1 bracket is equals to zero has real and equal roots

Posted by Ritu Thakur 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Ayush Tomar 6 years, 11 months ago

Use b2-4ac

0Thank You

Ayush Tomar 6 years, 11 months ago

K= 1/4

0Thank You

Mfj ?? 6 years, 11 months ago

K=+ or - 1/2

0Thank You

ANSWER

Proove that SinQ-cosQ+1/sinQ+cosQ-1=1/secQ-tanQ , using the identity sec square Q=1+tan squareQ

Posted by Hariom Dalal 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Mithi Choudhary 5 years, 3 months ago

pls answer

3Thank You

ANSWER

If sum and product of zeroes given 1/4,-1 respectively find its quadratic polynomial how do we find

Posted by Sakshi Negi 6 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Abc . 6 years, 11 months ago

Sorry the first two lines be like that ?let the two zeroes be in the form of alpha and beeta.

0Thank You

Shivam Tripathi 6 years, 11 months ago

Use formula x^2 - (a+b)x + (a×b) =0___ X^2 - (1/4)x + (-1)=0 ____ take 1/ 4 comon____ 1/4(4x^2 - x - 4 )=0 ____ 4x^2 - x - 4=0

0Thank You

Abc . 6 years, 11 months ago

Let the sum of zeroes be alpha and product of zeroes be beeta.... Then A/Q, alpha+beeta=1/4 and alphaXbeeta=-1... Now put sum and product in these ? x²-(alpha+beeta)x+alpha.beeta......we get,x²-1/4x+(-1)..i,e. the required polynomial is x²-1/4x-1.

0Thank You

ANSWER

Sin20+sin70-tan45

Posted by Sampreeta Gudi 6 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivam Tripathi 6 years, 11 months ago

Sin(90 - 20) + sin(90 - 70) - tan(90 - 45)_____ cos70 + cos20 - cot45

1Thank You

ANSWER

how many silver coins,1.75cm in diameter and of thickness 2mm, must be melted to form a cuboid of dimensions 5.5cmx10cm x 3.5cm . solve it

Posted by Arslan Siddqui 6 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Neha Sirur 6 years, 11 months ago

Radius=1.75/2=7/8 Let n be no. of coins... Vol of cyl. x n =vol of cuboid N=vol of cyl/vol of cuboid.....=22/7x7/8x7/8x2/10 whole divided by 5.5x 10x 3.5 Ans is 400

0Thank You

Shruti Raj 6 years, 11 months ago

volume of cuboid / volume of cylinder ( coin ).

0Thank You

ANSWER

What is quadratic polynomial

Posted by Sakshi Negi 6 years, 11 months ago

CBSE > Class 10 > Mathematics