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Posted by Khushi Nagar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Express each number as a product of its prime number

Posted by Fathimath Israth 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Shourya Sir 2 years, 2 months ago

248

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ANSWER

Prove that √5 is irrational no.

Posted by Vidit Agrawal 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Sarthak Salkar 2 years, 2 months ago

Google kar

1Thank You

Khushi Nagar 2 years, 2 months ago

Sorry it's mistake in this answer by me , Assume that √5 is a rational no.

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Khushi Nagar 2 years, 2 months ago

Let we assume that √5 is an irrational no. So,√5 =p/q where p and q both are co-prime integers and q≠0 Hence,by squaring both the sides (√5)^2=p^2/q^2 5=p^2/q^2 q^2=p^2/5(this show that 5 is a divisor of p^2 and p also) Let p =5a q^2=(5a)^2/5 q^2=25a^2/5 q^2=5a^2 q^2/5=a^2(this show that 5 is a divisor of q^2 and q also) Hence ,5 is a divisor of p and q both This is because of our wrong assumption of taking √5 as rational no. Hence,√5 is an iraational no.

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Shreyansh Pandey 2 years, 2 months ago

We can use contradiction method You can get you answer in ncert book chapter no 1 easily We can assume that √5 is a rational no Then we can equate √ 5 as or in the form of P/q( where p and q are co prime ) means both no is not divisible by a single no So , √ 5=p/q Squaring on both sides (√5)²= (p/q)² 5=(p)²/(q)² 5/q²=p²

3Thank You

ANSWER

Can anyone became my study partner ....?

Posted by Khushi Nagar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Khushi Nagar 2 years, 2 months ago

Yes

2Thank You

Shreyansh Pandey 2 years, 2 months ago

Just tell me how we can communicate

0Thank You

Shreyansh Pandey 2 years, 2 months ago

Yes I can

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ANSWER

If a quadric equation X square + 4x + k is equal to 6 find the value of k

Posted by Krishna Tyagi 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the factors of 2x²+x-300=0

Posted by Bhanu Prakash 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Shreyansh Pandey 2 years, 2 months ago

If you can't do it by factorisation You can apply quadratic formula -b√b²-(4ac)/2a

2Thank You

ANSWER

Triangles chapter all exercises notes

Posted by Prakash Banasode 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

77 ➗ 9654345226426π

Posted by Jaiveer Jat 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Make a quadratic equation whose à

Posted by Neha Gupta 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find HCF and LCM of 8/10, 2/5, 4/6.

Posted by Neha Gupta 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

7+6-4+

Posted by Mamta Gupta 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sarika Maurya 2 years, 2 months ago

0Thank You

Mamta Gupta 2 years, 2 months ago

2Thank You

ANSWER

2+6-

Posted by Mamta Gupta 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sarika Maurya 2 years, 2 months ago

-4

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ANSWER

🔺️abc~🔺️PQR . If AM and PN are altitudes of 🔺️ABC and 🔺️PQR respectively and AB ^2:PQ^2 =4:9 , then AM:PN =?

Posted by Nitish Talyan 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Let p be a prime number.The quadratic equations having its root as factor of p is

Posted by Kasish Shah 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Pranav Kumar Jha 2 years, 2 months ago

x^2-(p+1)x+p=0

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Abhay Soni 2 years, 2 months ago

Please send that quadratic equation also

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ANSWER

Of x=2 and x=3 are the roots of the equation 3x^2-2mx+2n=0 then find the value of m and n

Posted by Goshiya Khan 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove 1+secA/secA = sin2A/1-cosA

Posted by Subham Raut 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Shreyansh Pandey 2 years, 2 months ago

Very easy

0Thank You

Jaiveer Jat 2 years, 2 months ago

Sin30°

0Thank You

Sanskar Pawar 2 years, 2 months ago

Solve First LHS and then RHS Separately 1+secA / secA = sin2A /1-cosA LHS =1+1/cosA .... sec A can be written as 1/cosA 1+1/cosA /1/cosA Then solve cosA +1 / cosA cos A + 1 /cosA ×cosA/1 Then , cosA and cosA cancel and it remain 1+cosA RHS = sin2A is 1- cosA Then 1- cos2A / cosA 1-cos2A is identity in 9th that is a (a - b ) 2 it is (a+b ) ( a - b ) Then, 1+ cosA × 1- cosA / 1- cos A 1- cosA 1- cos A cancel and it remain 1+ cosA Therefore LHS = RHS Hence , proved

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Shubhamnath Keshri 2 years, 2 months ago

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ANSWER

Ex 12.2

Posted by Ujjwal Dixit 2 years, 2 months ago

CBSE > Class 10 > Mathematics