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Solution verified Verified by Toppr To evaluate, tan7 ∘ tan23 ∘ tan60 ∘ tan67 ∘ tan83 ∘ We know that, tan(90−θ)=cotθ and cotθ= tanθ 1 tan7 ∘ =tan(90 ∘ −83 ∘ )=cot83 ∘ tan23 ∘ =tan(90 ∘ −67 ∘ )=cot67 ∘ ∴tan7 ∘ tan23 ∘ tan60 ∘ tan67 ∘ tan83 ∘ =cot83 ∘ cot67 ∘ tan60 ∘ tan67 ∘ tan83 ∘ = tan83 ∘ 1 tan67 ∘ 1 tan60 ∘ tan67 ∘ tan83 ∘ = tan83 ∘ tan67 ∘ tan60 ∘ tan67 ∘ tan83 ∘ =tan60 ∘ = 3 Solve any question of Introduction to Trigonometry with:-

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Shreya Khamithkar 2 years, 1 month ago

Tan(90-theta)=cot theta Change tan 83, tan(90-83)=cot 7 Then also change tan 23, tan(90-23)=cot 67, We know tan 60=√3, Put the values Tan7.cot67.tan60.tan67.cot7 =√3 We know tan theta x cot theta =1 Tan7.cot7.tan67.cot67.√3=√3 1.1.√3=√3 √3=√3 LHS=RHS *(.) Symbolises mulplication here I hope you understood my answer Thank u

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The discriminate of the quadratic equation 7x^2-5+11=0 is

Posted by Education Shree Mathi 2 years, 1 month ago

CBSE > Class 10 > Mathematics

3 answers

Vivek Prajapati 2 years, 1 month ago

Q 2 ans is parallel

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Misha Middha 2 years, 1 month ago

D=285

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Education Shree Mathi 2 years, 1 month ago

The gemotrical represtation of the pair of linear equations 6x-3y=-10 and 2x-y+9=0 represent lines

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If the ratio of the sum of first n terms of two A.P.'s is (7n+1): (4n+27), find the ratio of their mth terms.

Posted by Prince Yadav 2 years, 1 month ago

CBSE > Class 10 > Mathematics

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360 oranges are distributed equally among a certain number of boys. Had there been 3 boys less, each would have gotten 4oranges more. Find the number of boys

Posted by Aalim Aalim 2 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Radhika Agarwal 2 years, 1 month ago

18 students

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Any Single girls here 😁

Posted by Md Samser 2 years, 1 month ago

CBSE > Class 10 > Mathematics

2 answers

Masuma Syeda 2 years, 1 month ago

😑

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Monika Monika 2 years, 1 month ago

🙄

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Ch 7 ex 7.2 ka q 2 class 10

Posted by Harshit Rajput 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Prachi Chhikara 2 years, 1 month ago

find it with section formula

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Ncjcjfj

Posted by Dev Raj 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Dev Raj 2 years, 2 months ago

Sdfff

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If the quadratic equation x2 + 4x + k = 0 has real and equal roots, then

Posted by Rani Yadav 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Faisal Khan 2 years, 1 month ago

Solution verified Verified by Toppr x 2 −4x+k=0 is of the form ax 2 +bx+c=0 where a=1b=−4c=k Roots are equal⇒ Discriminant=0 ⇒b 2 −4ac=0 ⇒(−4) 2 −4×1×k=0 ⇒16−4k=0 ⇒−4k=−16 ∴k= 4 16 =4 Solve any question of Quadratic Equations with:-

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Divya Sahu 2 years, 1 month ago

a=1,b=4,c=k d=b^2-4ac 0=4^2-4×1×k 0=16-4k -4k=-16 k=16/4=4

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Kya ch 14 maths me step derivation method deleted ha????

Posted by Gurleen Kaur 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Iron Man 2 years, 1 month ago

Yes

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K.Haniskha💖💖🥰 Kandi☺️ 2 years, 1 month ago

Nai

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Parveen Virk 2 years, 2 months ago

Nai

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Priyanshu is three time as old as his brother . Five year later he will be only 2-2/1times older than his brother .How old are they now?

Posted by Lucky Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

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Find value of k, (k+1)X2+2(k-1)x+(k-2)

Posted by Khushi Garg 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Faisal Khan 2 years, 1 month ago

The given equation is (k+1)x 2 −2(k−1)x+1=0 comparing it with ax 2 +bx+c=0 we get a=(k+1),b=−2(k−1) and c=1 ∴ Discriminant, D=b 2 −4ac=4(k−1) 2 −4(k+1)×1 =4(k 2 −2k+1)−4k−4 ⇒4k 2 −8k+4−4k−4=4k 2 −12k Since roots are real and equal, so D=0⇒4k 2 −12k=0⇒4k(k−3)=0 ⇒ either k=0 or k−3=0⇒4k(k−3)=0 Hence, k=0,3.

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Vivek Prajapati 2 years, 2 months ago

k=2

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In the adjoining figure de parallel bc and all measurements are in centimetres find the length of ae

Posted by Vikas Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics