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Given : Angle of sector, θ = 60° and radius, r = 6cm To find : Area of sector of a circle Formula used: Area of sector,A = θ/360° × πr² Solution: Given : θ = 60° and r = 6cm Area of sector,A = θ/360° × πr² A = 60°/360° × π × 6 × 6 A =1/6 × 22/7 × 6 × 6 A = 22/7 × 36 A = (22 × 36)/7 A = 132/7 cm² Hence, area of sector of a circle with radius 6 cm and θ = 60° is 132/7 cm².

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X²-7x+12

Posted by Nitesh Kumar 3 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Lavanya Kalai 3 years, 2 months ago

X=3,4

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Rashi Aloria Rashi Aloria 3 years, 2 months ago

x 3,4

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Vivek Prajapati 3 years, 2 months ago

x=3,4

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In a triangle ABC the coordinates of points A, B and Care (3, 2) (6, 4) and (9, 3) respectively. If AD, BE and CF are the medians of the triangle ABC find the coordinates of centroid G. Also, find the areas of triangle ABG and ▲ ACD.

Posted by V.Kubendiran K.Monish 3 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Vivek Prajapati 3 years, 2 months ago

Coordinate 9 , 9/2

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Prove that :Sin theta -2sin ^3 theta /2 cos^3 theta-cos theta=tan theta

Posted by Aryan Dewangan 3 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Lavanya Kalai 3 years, 2 months ago

Sin○-2sin^3○/2cos^3○-cos○ =sin○(1-2sin^2○)/cos○(2cos^2○-1) =sin○(2cos○)/cos (2cos○) Because 2cos^2○-1 and 1-2sin^2○=cos2○ Cut cos2○ and cos2○ Hence sin/cos=tan is proved

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Jasmeen Kaur 3 years, 2 months ago

Sin○-2sin^3○/2cos^3○-cos○ =sin○(1-2sin^2○)/cos○(2cos^2○-1) =sin○(2cos○)/cos (2cos○) Because 2cos^2○-1 and 1-2sin^2○=cos2○ Cut cos2○ and cos2○ NOW,sin/cos=tan○

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Prove that 7-2√3 is irrational number

Posted by Abhay Suhag 3 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Piyush Jaiswal 3 years, 2 months ago

Because this can not be write in the form of p/q

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Yashasvi Singh 3 years, 2 months ago

Answer

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Insert commas suitably and write the name according to Indian system of numeration

Posted by Sachi Kumari 3 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Vivek Prajapati 3 years, 2 months ago

1,00,000

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Chapter 18 statistics

Posted by Priya Vaswani 3 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Sumeet Lade P 3 years, 2 months ago

Chapter 14 statistics 14.1 , 14.2,14.3 14.4 is deleted

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Vivek Prajapati 3 years, 2 months ago

Chapter 15

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Shown that x²-3 is a factor of 2x⁴+3x³-2x²-9x-12.

Posted by Karthick Babu 3 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Khushi Sharma 3 years, 2 months ago

Quotient q(x) = 2x2 + 3x + 4 Remainder r(x) = 0 Since, the remainder is 0. Hence, x2 – 3 is a factor of 2x4 + 3x3 – 2x2 – 9x – 12Read more on Sarthaks.com - https://www.sarthaks.com/129312/by-actual-division-show-that-x-2-3-is-a-factor-of-2x-4-3x-3-2x-2-9x-12

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solve the following solve the following pair of linear equation by the elimination method and the substitution method 2x-y=2 and 4x-y=4

Posted by Keshava Murthy B.C 3 years, 2 months ago

CBSE > Class 10 > Mathematics