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Sin² (90-70°)+cos² 70°+cot25/cot(90-25) + cot5cot85 cot10cot80 cot60 Sin² 70+cos² 70 + cot25/cot25 + cot5tan5 tan80cot80 1√3 1+1+1.1.1/√3 2+1/√3 2√3+1/√3

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Sneha Singh 6 years, 10 months ago

Is this cos square 20

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18, 15 1\2, 13 ,...,-47 find AP

Posted by Vaishnav Sengar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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What values do we have do let if there are odd terms of an AP

Posted by Vanshika Sheokand 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Top Ten Pedia 6 years, 10 months ago

Your ap will be like If three terms (a-d),a,(a+d) If three terms (a-2d),(a-d),a,(a+d),(a+2d)

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Prove : sin A - 2 sin ^3 A over 2cos^3 A -cosA = tanA

Posted by Manpreet Kaur 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Sneha Singh 6 years, 10 months ago

SinA(1-2sin²A)/cosA(2cos²A-1) =sinA{1-2(1-cos²A)}/cosA(2cos²A-1) =SinA{2cos²A-1}/cosA(2cos²A-1) =SinA/cosA=tanA

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Vanshika Sheokand 6 years, 10 months ago

SinA(1-2sin^2A)/cosA(2cos^2A-1)........sinA(sin^2A+cos^2A-2sin^2A)/cosA(2cos^2A-sin^2A-cos^2A)..................sinA(cos^2A-sin^2A)/cos(cos^2A-sin^2A)...............sinA/cosA...........tanA

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Prove : sinA - 2sin ^3 A ----------------------------- = tan A 2cos ^3 A - cos A

Posted by Manpreet Kaur 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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How i can read for board exam??

Posted by Chhaya Patel 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Dhanya Shree K 6 years, 10 months ago

Work hard. Understand each topic perfectly. Practice more on previous year question papers

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Aastha Gupta ? 6 years, 10 months ago

What are u say

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If (1,p/3)is the mid point of the line segment joining the point ( 2,0)and (0,2/9)then show that the line 5x+3y+2 =0 passes through the point (-1,3p).

Posted by Seeta Bhagat 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Baamaa'S Beta 6 years, 10 months ago

Firstly find the value of p. P/3=2/18 P=1/3 Given point=(-1,3p) =(-1,3×1/3) =(-1,1) => x=-1 and y=1 5x+3y+2=0 -5+3+2=0 0=0

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A path of width 3.5m runs around a semicircular grassy plot whose perimeter is 72m. Find the area of the path

Posted by Varsha Harish 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let x be the radius of the semi-circular path.
Given, perimeter of circular path = 72
{tex} \Rightarrow 2r + \pi r = 72{/tex}
{tex} \Rightarrow r\left( {2 + \pi } \right) = 72{/tex}
{tex} \Rightarrow r\left( {2 + \frac{{22}}{7}} \right) = 72{/tex}
{tex} \Rightarrow r \times \frac{{36}}{7} = 72{/tex}
{tex}\therefore {/tex} Radius of semi-circular grassy plot = 14m

Since a path of width 3.5 m runs around a semi-circular grassy plot whose Perimeter is 72 m
Then, radius of outer semi-circle = 14m + 3.5m = 17.5m
Area of the path = Area of outer semi-circle-Area of inner semi-circle
{tex} = \frac{1}{2}\pi {\left( {17.5} \right)^2} - \frac{1}{2}\pi {\left( {14} \right)^2}{/tex}
{tex} = \frac{1}{2} \times \frac{{22}}{7}\left[ {{{\left( {17.5} \right)}^2} - {{\left( {14} \right)}^2}} \right]{/tex}
{tex} = \frac{{11}}{7}\left[ {31.5 \times 3.5} \right]{/tex}
= 173.25m²

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What is main important question in chapter 4 quadratic equation

Posted by Chhaya Patel 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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parso mera maths ka pre board h ? how should i practice

Posted by ????? ❤️ 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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How to practice for pre board exams

Posted by Bhavana B 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhavana B 6 years, 10 months ago

Maths

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The height of tower is 10 m .calculate the height of shadow when suns altitude is 45degree

Posted by Priya Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Shreya Sharma 6 years, 10 months ago

Take base =x And do P/b tan45 =1 so Tan45=10/x 1=10/x X=10

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Aditya Kumar 6 years, 10 months ago

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How to prepare for board exams???

Posted by Bhavishya Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Bhavishya Kumar 6 years, 10 months ago

For maths and science...

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Hello Hello 6 years, 10 months ago

For which subject r u asking specially?

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A container open at the top and made up of a metal sheet is in the form of a frustum of a cone of height 16cm with diameters of its lower and upper ends are 16 and 14 respectively.find cost of metal sheet used to make the container ,if it costs rs.10 per 100cm^2(pi=3.14)

Posted by Anjana K 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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The arc of a circle is 7 x pi cm. The sector it bounds has an area of 28 x pi cm. Find the radius of circle?

Posted by Lakshaya Bhardwaj 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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2xsquare+kx+3=0 ineed this question in a very simplemanner

Posted by Abishay Narain 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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Two cubes each of volume 64 cm cube has joined end to end find the surface area of the resulting cuboid

Posted by Dev Raj 6 years, 10 months ago

CBSE > Class 10 > Mathematics

6 answers

Hema Pandey 6 years, 10 months ago

Sry side of cube is 4 and in the first line There is full stop after first 64

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Hema Pandey 6 years, 10 months ago

Volume of cube(a×a×a)=64 64 is cube of 4 . hence side of cube is 8. On joining the cube the height and breadth remain same but length become twice. Measurements of resulting cuboid are L=8 B=4 H=4 Now using,TSA of cuboid put value of l,b,h in formula u get ur answer

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Hema Pandey 6 years, 10 months ago

Your right answer is

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Hema Pandey 6 years, 10 months ago

Sry I read the wrong question

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Hema Pandey 6 years, 10 months ago

Sry L=126

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Hema Pandey 6 years, 10 months ago

On joining the cubes the resulting cuboid have same breadth and height but length become twice. So measurements of sides of resulting cuboid are L=123 B=63 H=63 Now, using TSA of cuboid you will get your answer

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If pth term of an A.P.is q and the qth term is p prove that its nth term is (p+q-n)

Posted by Hema Pandey 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let a be the first term and d be the common difference of the given A.P. Then,
p^th term = q {tex}\Rightarrow{/tex}a + (p-1) d = q ...(i)
q^th term = p {tex}\Rightarrow{/tex}a + (q-1) d = p ...(ii)
Subtracting equation (ii) from equation (i), we get
(p - q) d = (q - p) {tex}\Rightarrow{/tex} d = -1
Putting d = - 1 in equation (i), we get
a + ( p-1) × (-1) = q
⇒ a = (p + q - 1)
nth term = a + (n -1 )d
= (p + q - 1)+ (n -1) × (-1)
= p + q - 1 -n + 1
= (p + q - n)

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Simplify : 1/√2+√3-√5 + 1/√2-√3-√5

Posted by Akshat Bhatt 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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What is the formula of heron's

Posted by Prince Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Hema Pandey 6 years, 10 months ago

s=a+b+c/2. S for semi perimeter a,b,c are the side of triangle Then area=√s(s-a)(s-b)(s-c)

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If mth term of an A.P. be1/n and nth term be 1/m show that it's(mn)th term is 1

Posted by Hema Pandey 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Baamaa'S Beta 6 years, 10 months ago

1/n=a + (m-1)d..... 1/m=a+(n-1)d.... Solve this two eqn to get d=1/mn And put this value in any one of the above eqn to get the value of a which will also equals to 1/mn. * Tmn= a+(mn-1)d Put the value of a and d in this equation. you will get the answer i.e. 1 In this way you can prove this. Www.baamaasbeta.blogspot.com plz visit once.

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Hema Pandey 6 years, 10 months ago

Support material

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Solve 217x+131y =913. 131x+217y=827. Please explain me how to solve this ???

Posted by Anshika / U Can Call Me Alien ????? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Honey ??? 6 years, 10 months ago

First add both the eq. u will get x+y=5 and then subtract the eq. you will get x-y=1. and then you could solve

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Baamaa'S Beta 6 years, 10 months ago

Firstly aap in dono equations ko 1 baar add kro...or ek baar in dono eqn ko subtract kro... theek hai. Jb do eqns mil jye to use solve kr lo

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Honey ??? 6 years, 10 months ago

X=3 and y=2

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If sinA- cosA=1 then find the value of 1/ sinA+cosA

Posted by Raina Ahlawat 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Raina Ahlawat 6 years, 10 months ago

But is que ka answer 2√7/7 hi hai

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Krishna Kireeti 6 years, 10 months ago

SinA - CosA=1 So, SinA=1+CosA Upon Squaring on both sides, Sin square A = (1+CosA) square Since Sin square A = (1 - CosA)(1+CosA), (1 - CosA)(1+CosA)=(1+CosA)(1+CosA) So, 1 - CosA = 1+CosA, 2CosA=0 So, CosA=0. So A=90 degrees Substituting A=90 degrees in 1/sinA+cosA, We get 1/sinA+cosA = 1/1+0=1/1=1 Therefore the answer is 1.

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Raina Ahlawat 6 years, 10 months ago

But iska ans 2√7/7 hai

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Ahere Kashinath 6 years, 10 months ago

Answer is 1+cosA

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sin =cos

Posted by Sudhanshu Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Ashish Ashish Kumar 6 years, 10 months ago

Sin45=cos45

1Thank You

Simmi _2233 6 years, 10 months ago

Complete your question first...

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If sin (A+B)=1 and sin(A-B)=1÷2,0 <A+B <90° and A>B, then find A and B

Posted by Tejas Mane 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Aayush Thakkar 6 years, 10 months ago

B=60 A=30

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10.2question 5

Posted by Mahendra Rao 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Anshika / U Can Call Me Alien ????? 6 years, 10 months ago

Diagram should be like this :- a circle, AB ia a tangent , OC is perpendicular to AB and O' is also a point around O(centre) and join O'C

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Anshika / U Can Call Me Alien ????? 6 years, 10 months ago

This can be done by contradiction. Therefore let assume that O'C is perpendicular to Ab so we can say that angle OC'b is equal to 90°- © we know that angle ACB = 90°- ® From ©and ® O and O' are same point therefore angle O'CB = angleOCB .

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Anshika / U Can Call Me Alien ????? 6 years, 10 months ago

Which chapter?? Dude

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