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  • 2 answers

@ Aashu 6 years, 10 months ago

March tak

Mrinalini Nair Ani 6 years, 10 months ago

By Feb-March
  • 4 answers

Riya Pal 6 years, 10 months ago

No.of pens=13 and No.of pencil=27.....?☺️☺️?

Khushi Thakur 6 years, 10 months ago

No. Of pen = a and no. Of pencil = b Case :1, a+b=40 (eq 1) Case :2, 4(a-5)=b+5 =: 4a-b=25(eq2) By elimination method, a= 13 ,b =29....

Ankit Kumar 6 years, 10 months ago

11 pen and their are 29 pencils

Bharat Kaushik 6 years, 10 months ago

11 pen and 29 pencils
  • 2 answers

Parvathi Santhosh 6 years, 10 months ago

Is 1+5=5 or 6? What do you mean?

Abhay Kumar 6 years, 10 months ago

Go to class 1 and learn number
  • 2 answers

Shivam Jha 5 years, 8 months ago

Cos a =0 :.cos a=cos 90 :.a=90

Shivam Jha 6 years, 10 months ago

0
  • 2 answers

Prince Rajput 6 years, 10 months ago

In my opinion after ncert only the exampler is important.

Deepesh Yadav 6 years, 10 months ago

It is important for the practice of board examination to train ourself for any type of questions.
  • 2 answers

Shivam Jha 6 years, 10 months ago

√2

Poonam Rathore 6 years, 10 months ago

Under root 2
  • 1 answers

Priyanshi Mishra 6 years, 10 months ago

See from cbse ncert solution
  • 1 answers

Sameer Kumar 6 years, 10 months ago

Yea, we can practice optional exercises with the main exercise because it will advance our knowledge to that topic or chapter and that will help in further examination or competition.???
  • 2 answers

Faiz Ansari 6 years, 10 months ago

I know

Faiz Ansari 6 years, 10 months ago

Its ok
  • 1 answers

Sia ? 6 years, 6 months ago

{tex}\bigtriangleup{/tex}ABC,
Ext.{tex}\angle{/tex}ACD = {tex}\angle{/tex}ABC + {tex}\angle{/tex}BAC (Exterior Angle Theorem)

{tex}\Rightarrow{/tex} {tex}\angle{/tex}ABC + {tex}\angle{/tex}ACD = {tex}\angle{/tex}ABC + {tex}\angle{/tex}ABC + {tex}\angle{/tex}BAC
(Adding {tex}\angle{/tex}ABC to both sides)
= 2 {tex}\angle{/tex}ABC + {tex}\angle{/tex}BAC = 2{tex}\angle{/tex}ABC + 2{tex}\angle{/tex}BAL
(AL is the bisector of {tex}\angle{/tex}BAC)
= 2({tex}\angle{/tex}ABC + {tex}\angle{/tex}BAL) = 2{tex}\angle{/tex}ALC
(because, In{tex}\bigtriangleup{/tex}ABL, Ext.{tex}\angle{/tex}ALC = {tex}\angle{/tex}ABC + {tex}\angle{/tex}BAL) (Exterior Angle Theorem)

  • 1 answers

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Let two zeroes are a and b ATQ a+b= 0 a+b+c = 5 c=5 abc = -80 ab5 = -80 ab = -16 b = -a ( from eq. 1) -a^2 = -16 a = +- 4 b = -+4
  • 1 answers

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Do similar as like as you prove root 2 is irrational
  • 4 answers

Sameer Kumar 6 years, 10 months ago

It depends on the mood of CBSE board

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Yes

Vishal Kumar 6 years, 10 months ago

Yes

Hello Hello 6 years, 10 months ago

Unable 2 understand ur ques
  • 4 answers

Deepesh Yadav 6 years, 10 months ago

First change both sides of equation in sin and cos then you get answer both sides equal.

Sameer Kumar 6 years, 10 months ago

At first change the whole equation into sin and cos theta .Then break the equation in simple terms and lastly you can solve your problem.??????

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Change whole eq in son and cos

Hello Hello 6 years, 10 months ago

Just revise identities and formulas and then solve d ch
  • 3 answers

Sameer Kumar 6 years, 10 months ago

I also don't know because my teacher hasn't taught that

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Last ex ke sare ques aur sari theorem

Hello Hello 6 years, 10 months ago

Mostly......base is ncert
  • 4 answers

Sameer Kumar 6 years, 10 months ago

Do practice more and more and ask the question to your teacher or friends.Also you can study in group so that your daubt will clear

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Do revision as much you can do

Aryan Khare 6 years, 10 months ago

Gungun first understand 3 important theorums unke base par hi question aate h

Sushant Nevtia 6 years, 10 months ago

You can try it firstly in ncert book When you are able to solve that you can use any refrence book
  • 6 answers

?????? (-B±√(B²-4Ac))/(2A) 6 years, 10 months ago

Easy

Sushant Nevtia 6 years, 10 months ago

We can solve it by trigonometry

Honey ??? 6 years, 10 months ago

The only thing is correct figure.Once u drawn the correct fig then u could solve it

@ Aashu 6 years, 10 months ago

So simple .....understand the question nicely then draw??

Shivam Ranjan 6 years, 10 months ago

How to make image

Aryan Khare 6 years, 10 months ago

Which concept
  • 2 answers

Ram Kushwah 6 years, 10 months ago

lcm(48,60,72)=720

so they will meet after running 720 km each Or after taking 2 rounds of field

A will take  720/48= 15 days

B will take  720/60=12 days

C will take  720/72= 10 days

Honey ??? 6 years, 10 months ago

After 720hrs
  • 1 answers

Sneha Singh 6 years, 10 months ago

Is thi 2√3-1
  • 2 answers

Honey ??? 6 years, 10 months ago

No bcoz hcf should be factor of lcm
HCF of two numbers is a factor of the LCM of those numbers. Thus, we cannot have two numbers whose HCF is 16 and LCM is 380. Because, when we divide 380 by 16, we get a remainder of 12. Thus, 16 is not a factor of 380.
  • 3 answers

Ishika Bansal 6 years, 10 months ago

Sample paper try karo 2019 ka mostly usse mein sa aayga maths and science ka
But board mein 96%+ ncert ae aata he
Depends on teacher
  • 2 answers

Honey ??? 6 years, 10 months ago

108

Anushka Jugran ? 6 years, 10 months ago

????
  • 3 answers

Ishika Bansal 6 years, 10 months ago

For collinearity of the points ,area of the triangle formed by given points is zero 1÷2{(3k-1)×(k-7+k+2)+k(-k-2-k+2)+(k-1)(k-2-k+7)}=0 {(3k-1)(2k-5)-2k²+5k-5}=0 4k²-12k=0 K=0,3 ok

Anushka Jugran ? 6 years, 10 months ago

Unable to understand ur question Bro

Honey ??? 6 years, 10 months ago

Cant understand your ques.
  • 1 answers

Gaurav Seth 6 years, 10 months ago

The volume of the solid iron cuboid = l×b×h

length of the cuboid = 4.4 m = 440 cm

breadth of the cuboid = 2.6 m = 260cm

Height of the cuboid = 1.0 m = 100 cm

Volume = 440×260×100 
= 11440000 cm ^3

Volume of the cuboid = Vol. of the cylindrical pipe 
Vol. of the cylindrical pipe = 11440000cm ^3

Inner radius of the pipe = 30 cm

Outer radius of the pipe = 35 cm

π (R^2 - r^2 ) h = 11440000

22/7 [ (35×35) - (30×30) × h = 11440000

22/7 [ 1224 - 900] × h = 11440000

22/7 [324] × h = 11440000

1018.28× h = 11440000
h = 11440000/1018.28

h = 11234.63cm
h = 112.34m

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