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  • 3 answers

Raj Raj 6 years, 10 months ago

3a+4b=10 equation. 1 a+b=-b/a a+b=6 equation 2 Multiply 2nd eq by3 3a+3b=18 By eliminate equ1&2 remain b=-8 By putting the value of b in equ1 we get a=14 ab=c/a 14×-8=k K=-112

Puja Sahoo? 6 years, 10 months ago

K=-112

M A Santos 6 years, 10 months ago

K=5
  • 3 answers

@Jay Bunkar 6 years, 10 months ago

Therom pr questions kro mene bhi bhot practice ki thi

Puja Sahoo? 6 years, 10 months ago

Practice them more

Sahil Singh 6 years, 10 months ago

Theorem is important
  • 1 answers

Raj Raj 6 years, 10 months ago

Volume of cone=πr²×120÷360 =3.14×12×12×120÷360 =3.14×48 =150.72cm²
  • 4 answers

Jatt Putt Aryan???? 6 years, 10 months ago

Sorry BA perpendicular

Anushka Jugran❣️ 6 years, 10 months ago

I have done the similar question in which v have to prove area equal to r(tan@+sec@-1+@22/180×7)

Puja Sahoo? 6 years, 10 months ago

Hmm, ek bat bolo, bs agar, BO perpendicular, hai OA ko to ye hypotenuse kaise hoga

Jatt Putt Aryan???? 6 years, 10 months ago

Answer my question
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  • 2 answers

Ankush Upadhyay 6 years, 10 months ago

(cos/sin).cos+ sin cos^2/ sin+ sin (cos^2+ sin^2)/ sin 1/sin cosec

Jatt Putt Aryan???? 6 years, 10 months ago

Sin@+Cos@×cos@/[email protected]@+cos²@/sin@.....(sin²@+cos²@)/[email protected]/[email protected]@
  • 1 answers

Jatt Putt Aryan???? 6 years, 10 months ago

In triangle ABC, tan 45 = height/base = AB/BC or, 1 = AB/BC [ As tan 45 degree = 1] or, AB = BC ..........(i) Again, triangle ABD, tan 30 = AB/BD or, [tan 30 =1/1.732] or[ As AB = BC from (i) above] or, 1.732 AB = AB +1 or, 1.732 AB - AB = 1 or, AB(1.732-1) = 1 or, AB * 0.732 = 1 or AB = 1/0.732 = 1.366 Hence height of the hill 1.366 km
  • 1 answers

Jatt Putt Aryan???? 6 years, 10 months ago

The alternate segment theorem states that in any circle , the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment
  • 2 answers

S N Mahato 6 years, 10 months ago

This will not ask in xm

Jatt Putt Aryan???? 6 years, 10 months ago

Infinity
  • 1 answers

Jatt Putt Aryan???? 6 years, 10 months ago

Sec2@sec2@[email protected]@(sec2@-1)..... (1+tan2@)(tan2@).....1(tan2@)+tan2@(tan2@)......tan2@+tan4@(H.P)
  • 1 answers

Abi Shinchan 6 years, 10 months ago

What do u actually want
  • 5 answers

Anjeela Khan?? 6 years, 10 months ago

12

Akshata Singh 6 years, 10 months ago

Ok

Aman Singh 6 years, 10 months ago

12 by using distance formula

Akshata Singh 6 years, 10 months ago

Method kya h ans lane ka

Jatt Putt Aryan???? 6 years, 10 months ago

12
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Aastha Gupta ? 6 years, 10 months ago

We know that, Hcf x lcm =product of given 2 numbers =12x lcm=1800 Lcm=1800/12 Lcm=150. Answer.

Khushnuda?Khushi ??? 6 years, 10 months ago

Lcm*hcf=product of 2no.s Lcm*12=1800 Lcm=1800/12 Lcm=150

Jatt Putt Aryan???? 6 years, 10 months ago

H.C.F×L.C.M= product of numbers...12×L.C.M=1800...L.C.M=1800/12.....L.C.M=150
  • 3 answers

Anjeela Khan?? 6 years, 10 months ago

I/cos thethe+ sin thethe / cos thethe 1+ sin thetha/ cos thethe=p Cosecthetha= 1/ sin thetha Secthethe + tanthethe= p..................1 Sec^2+tan^2=1 (Secthetha-tanthethe) ( secthetha+ tanthetha) ( secthetha- tanthethe)=1.................2 By adding equation 1 and 2 2secthetha= p+1/p Sectheta=p^2+1/2p (P^+1)-(2p)^2 Under root (p^2)^2+1^2×2p^2-4p^2 Under root p^4+1-2p^2 Root cancel by square P^2-1 Cosecthetha is hypho/ parpendicular So Cosecp= p^2+1/p^2-1

Anushka Jugran❣️ 6 years, 10 months ago

Ha, bahut common question hai

Jatt Putt Aryan???? 6 years, 10 months ago

(P^2+1)/(p^2-1)
  • 7 answers

Disha Patidar 6 years, 10 months ago

First apply the formula an=a+(n-1)d an=50, a=5 ,d=3. 50=5+(n-1)3 50-5=(n-1)3 45=(n-1)3 45÷3=(n-1) 15=(n-1) 15+1=n 16=n Now, apply Sn=n/2 (2a+(n-1)d Sn=16/2 (2×5+(16-1)3 Sn=8 (10+45) Sn=8×55 Sn=440 Therefore, n=16 and Sn=440 ☺☺

Anjeela Khan?? 6 years, 10 months ago

N=60 Sn= 440

Amaan Siddiqui 6 years, 10 months ago

an=a+(n_1)d

Anushka Jugran❣️ 6 years, 10 months ago

Firstly apply the formula an =a+(n-1) d and then apply the formula to find sum that is sum equal to n/2(2a+(n-1)d)

Jatt Putt Aryan???? 6 years, 10 months ago

Sorry sorry n= 16 and sn=440

Jatt Putt Aryan???? 6 years, 10 months ago

N=12 and sn = 258

Puja Sahoo? 6 years, 10 months ago

n=16, and Sn= 440
  • 4 answers

Anushka Jugran❣️ 6 years, 10 months ago

Ya, aryan is ryt

Anushka Jugran❣️ 6 years, 10 months ago

I hope that u know the method.. Take the terms as a-3d, a-d, a+d, and a+3d... And no need of saying thnx ?

Jatt Putt Aryan???? 6 years, 10 months ago

Bhai apka question galat h maine ye question padha h isme 120 nahi pehle value sirf 20 h

Anushka Jugran❣️ 6 years, 10 months ago

2,4,6,8 or 8,6,4,2
  • 2 answers
Konsa solution....pura ques type karo
Which chapter
  • 2 answers
Atleast answer to mila mujhe

Puja Sahoo? 6 years, 10 months ago

Yup, se...here ..---> (secA+tanA-1)(secA-tanA+1) -----> (secA +tanA-1){secA-(tanA-1)}..................... ----->sec square A - ( tanA - 1)square ................... ------> sec square A-(tan square A+1-2tanA) ........ ----> sec square A-tan square A - 1+ 2 tanA......... ----> 1-1+2tanA........ ----> 2tanA..... ------> 2/ cotA.. HENCE PROVED......☺☺
  • 4 answers

S N Mahato 6 years, 10 months ago

Spilt LHS in terms of sin cos...if u found difficulty ask
(SecA+TanA-1)(secA-tanA+1)=2/cotA

Simran Kaur 6 years, 10 months ago

Volume and surface area
Nooo not in these chapters but I have doubt in trigonometry
  • 1 answers

Jatt Putt Aryan???? 6 years, 10 months ago

Sq. Both side......sin2@+4cos2@+4cos@sin@=1.......... 1-cos2@+4(1-sin2@)+4cos@sin@=1......1-cos2@+4-4sin2@+4cos@sin@=1.......-cos2@-4sin2@+4cos@sina=4....(2sin@-cos@)^2=4......2sin@-cos@=2(H.P)

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