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Ask QuestionPosted by Shruti Raj 6 years, 10 months ago
- 3 answers
Gaurav Seth 6 years, 10 months ago
Given: ∆ABC ~ ∆ QRP,
AREA(∆ABC) / AREA(∆QRP)= 9/4,
AB = 18cm
BC = 15cm,
length of PR = ?
Answer is 10 cm
Posted by Sparsh Sahu 6 years, 10 months ago
- 5 answers
Posted by Vipul Chaudhary 6 years, 10 months ago
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Posted by Shivani Gupta 6 years, 10 months ago
- 2 answers
Gaurav Seth 6 years, 10 months ago
Suppose the line x - y - 2 = 0 divides the line segment joining A(3, -1) and B(8, 9) in the ratio K:1 at point P. Then the coordinates of P are
So, the required ratio is 2 : 3
Posted by Iftekhar Hussain 6 years, 10 months ago
- 3 answers
Avinash Saigal 6 years, 10 months ago
Posted by Mohit Soni 6 years, 10 months ago
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Posted by Tanya Goyal 6 years, 10 months ago
- 2 answers
Yogita Ingle 6 years, 10 months ago
From the figure, it can be observed that points X, Y, Z are dividing the line segment in a ratio 1:3, 1:1, 3:1 respectively.
Coordinates of x = {tex}\;\left(\frac{1\times2+3(-2)}{1\;+\;3},\frac{1\times8\;+3\times2}{1+\;3}\right)=\;\left(-1,\;\frac72\right){/tex}
Coordinate of Y = {tex}\;\left(\frac{2 +(-2)}{2},\frac{2 +8}{2}\right)=(0,5){/tex}
Coordinate of Z = {tex}\;\left(\frac{3\times2+1(-2)}{1\;+\;3},\frac{3\times8\;+1\times2}{1+\;3}\right)=\;\left(\;1,\;\frac{13}2\right){/tex}
Puja Sahoo? 6 years, 10 months ago
Posted by Garima Sharma 6 years, 10 months ago
- 1 answers
Anshika / U Can Call Me Alien ???? 6 years, 10 months ago
Posted by Paras Atri 6 years, 10 months ago
- 5 answers
Anshika / U Can Call Me Alien ???? 6 years, 10 months ago
Yogita Ingle 6 years, 10 months ago
sorry by mistake used 2k - 9 in place of 2k - 3.
So, solve same by same method.
Yogita Ingle 6 years, 10 months ago
5, (2k -9), 9 is an ap
d = (2k -9) - 5 = 2k-9 - 5 = 2k - 14 .... (i)
also d = 9 - (2k-9) = 9 - 2k - 9 = - 2k ...... (ii)
From (i) and (ii)
2k - 14 = -2k
2k + 2k = 14
4k = 14
k = 14/4 = 7/2
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Shruti Raj 6 years, 10 months ago
0Thank You