CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

(asintheda + bcostheda) ka whole square + (acostheda - bsintheda) ka whole square = a square + b square. Now, (asintheda +bcostheda)^2 (acostheda - bsintheda) ^2 = a^2 + b^2 => c^2 +(acostheda - bsintheda)^2= a^2 + b^2 => acostheda - bsintheda = +_ root under a^2 +b^2 - c^2 ...........proved

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5 years old previous paper

Posted by Anurag Savita 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Madhu Mani 6 years, 10 months ago

Mycbse guide have previous year question paper

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Formula ofmode

Posted by Utsav Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Abhay Kumar 6 years, 10 months ago

Right formula

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Deepak Kadian 6 years, 10 months ago

L +. (f1 - f0 /. 2f1 - f2 - f0 ). *. H

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At some time of the day,the length of the shadow of a tower is equal to its height. Find the sun's altitude at that time.

Posted by Malkeet Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Md Roushan Alam 6 years, 10 months ago

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Lakshay Sehrawat 6 years, 10 months ago

We have to find here,theta Suppose,height of tower=x Also,height of tower equals to the height shadow of tower. So, use phythagoras theorem H^2=P^2,+B^2 H^2=x^2+x^2 H=√2x As,sin theta=Perpendicular/Hypotenuse Sin theta =x/√2x It will come 1/√2. As,1/√2= sin 60° Then, sun altitude will be 60°

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Aryan Singy 6 years, 10 months ago

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X square +(a/a+b+a+b/a)x+1=0

Posted by Prachi Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Let find hcf of 134791,6341,6339by euclid divisions

Posted by Mohit Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Shaheen Hussain 6 years, 10 months ago

Putting on formula a= b.q+r

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Lakshay Sehrawat 6 years, 10 months ago

This type of question have some trick to solve.

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Sec theta + tan theta = 3 then fund cosec tgeta

Posted by Karan Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Lakshay Sehrawat 6 years, 10 months ago

Tan theta =3-sec theta Tan=sin/cos Sin/cos=3-sec theta Sin=(3-sec theta)cos theta After solving , Sin=3cos theta - sec theta cos theta Sin=3cos theta -1/cos theta×cos theta Sin=3cos theta - 1 Cosec theta = 1/sin theta Cosec theta =1/3cos theta-1

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Lakshay Sehrawat 6 years, 10 months ago

Question is Sec theta +tan theta =3,then find cosec theta .

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the probability of occurrence of event a is denoted by p(a). so, the range of p(a) is

Posted by Pradeep Chaudhary 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Lakshay Sehrawat 6 years, 10 months ago

Between 0 and 1

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Karan Singh 6 years, 10 months ago

Between 0 and 1

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If x=2/3 and x=-3 are the roots of quadratic equation ax^2+bx+c find the values of a and b

Posted by Nitish Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Mohit Kumar 6 years, 10 months ago

Use the D=b²-4ac

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Please prove that , sinA ÷ 1-cosA + tanA ÷ 1+cosA = secA×cosecA + cotA

Posted by Vanshika Wadhwa 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The length of a chain used as a boundary of a semicircle park is108cm find the area of the park

Posted by Mahi Qadri 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Insha Fatima 6 years, 10 months ago

Find out the radius with the help of circumference and eventually use it to find the area .

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????? ❤️ 6 years, 10 months ago

2551.5 cm square

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Show that in right teiangle , the square of the herpotincese is equal to the sume of the square of the other two sides.

Posted by Vishu Suryavanshi 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Lakshay Sehrawat 6 years, 10 months ago

It is given in ncert dont ask fully non sense question

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D.J Alok 6 years, 10 months ago

Its given in ncert...

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Determine the Ap whose third term is 16 and the 7th term exceeds the 5th term by12

Posted by Sïńğhåńïýå Råhüľ 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Palak Gupta 6 years, 10 months ago

a3=16 a+2d=16 eq.1 a7 =a5+12 a+6d=a+4d+12 2d=12 d=6 Put the value of d in eq.1 a+2d=16 a+2(6)=16 a=16-12 a=4 The A.P. form 4,10,16,,.........

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If triangle ABC similar triangle RQP ,Angle A =80°,& angle B=60°,what is the value of angle P

Posted by Gourav Bhati 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

@ Aashu 6 years, 10 months ago

Value of angle P is 40 degree.....

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A man repays a loan of ₹ 1800 by paying ₹ 40 in the first month and then increase the payment by ₹ 20 every month. How long will it take him to clear the loan?

Posted by Aksahy Mishra 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If two tangents PA and PB are tangents from an otside piont P such that PA= 15 cm and angle APB=60°. Find the length of the chord AB .

Posted by Mansi ??⚘?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Piyush Raj Sahni 6 years, 10 months ago

45cm

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Aksahy Mishra 6 years, 10 months ago

PA=AB because it is tangents and they are bisect the radius therefore, AB=15cm

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Is 63a term of ap -1,4,9,14......8

Posted by Shivaraj Kharone 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Mansi ??⚘?? 6 years, 10 months ago

No it is not a term of A.P

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@ Aashu 6 years, 10 months ago

No 63 is not the term of following Ap

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Honey ??? 6 years, 10 months ago

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Find the length of the shadow of a 20m tall pole , on the ground when the sun elevation is 45°

Posted by Mansi ??⚘?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

5 answers

@ Aashu 6 years, 10 months ago

Length of the shadow is 20 m ...

1Thank You

Lakshita Saini 6 years, 10 months ago

Use sin 45° in it

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Mansi ??⚘?? 6 years, 10 months ago

I am not getting what you are saying

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Mansi ??⚘?? 6 years, 10 months ago

Can solve in detail

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Honey ??? 6 years, 10 months ago

Use tan 45°=1 and solve

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Given a rt angle ?ABC angle b=90° .with AB as diameter circle is drawn intersecting AC at P from P tangent is drawn intersecting BC. at a point R. Prove that BR=CR

Posted by Honey ??? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Honey ??? 6 years, 10 months ago

Plz answer

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Cos0 - sin0 + 1 ÷ cos0 + sin0 - 1 = Cosec0 +cot0

Posted by Om Om 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Saurabh Rajput 6 years, 10 months ago

Cos 0 se divide kar

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Exercise 6.3 question no. 4

Posted by Yuvraj Dangi 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Paras ? ? Shah ? ? 6 years, 10 months ago

QR / QS = QT / PR ( given) Qt / Qr = Pr / Ps (1) <1 = <2 ( given) Pr = Pq (2). ( side opp. To equal < are equal) From 1 and 2 Qt / Qr= Pq / Qs = Pq / Qt = Qs/ Qr (3) In ∆ PQS and TQR we get Pq /Qt = Qs / Qr < PQS = <TQR = <Q By Side angle side criterion of similarity ∆ PQS ~ ∆ TQR Hence proved ? ?

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Paras ? ? Shah ? ? 6 years, 10 months ago

In ∆ RPQ and RTS < RPQ = <RTS. (given ) <PRQ = < TRS ( common) Therefore By AA- criterion of similarity, ∆ RPQ ~ ∆ RTS

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Ishita Jain 6 years, 10 months ago

QR/QS=Qt/PR(angle1=angle2 so in triangle PQR PQ=PR becoz sides opposite to equal angles are equal ) So QR/QS=QT/QP So by the converse of bpt theoram PS is parallel to TR Then in triangle PQS and tria.TQR Angle 1 =angle 1( common) Angle QPS=angle QTR ( corresponding angle ) SO BY AA~ CRITERIA Triangle PQS~tri.TQR

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From an external point P tangents PA and PB are drawn to a circle with centre O. If <PAB = 50 then find <AOB

Posted by Paras ? ? Shah ? ? 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Gungun._ Lalwani? 6 years, 10 months ago

Complete yur ques first

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Paras ? ? Shah ? ? 6 years, 10 months ago

Some one tell me

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The area of an equilateral triangle is　1732.05　cm2 about each angular point as Centre a circle is inscribed with radius equal to half the length of the side of the triangle find the area of the triangle not included in the circle　use pie=3.14

Posted by Sachin Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Plz sm1 explain #9th Q. Of ex-13.3..(NCERT) plz explain the question... And it's solution too.

Posted by Drishti Arora 6 years, 10 months ago

CBSE > Class 10 > Mathematics

5 answers

Ishita Jain 6 years, 10 months ago

Suppose the tank is filled in x hours since water is flowing at the rate of 3km/hr therefore, Lenght of the water column=3xkm=3000x m Clearly the water column forms a cylinder of radius r=20/2cm=10cm =1/10m and h=height(length)=3000xm Hence vol. Of the water that flows in tank in x hrs πr^2h=( 22/7*1/10*1/10*3000x)cubic m Also volume of tank=(π*5*5*2). [R=5m and h=2m] Equate the volumes and then you will get your answer that is 1hr 40 min

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Raushan Gautam 6 years, 10 months ago

Internal diameter of pipe =20cm Internal radiusof pipe =10cm Water flows at the rate of 3km/h=3000×100cm Volume of water that flow through the pipe in x hours=3000×100×x Dimensions of cylindrical tank radius=5×100cm height=2×100cm Volume of pipe=volume of cylindrical tank π×10×10×3000×100×x=π×500×200 X = 5/3 hours = 100 minutes= 1hr 40 minute

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Paras ? ? Shah ? ? 6 years, 10 months ago

Diameter of the pipe = 20 cm Radius of the pipe= 10 cm Length of water column = 3km = 3x 1000x 100cm Vol. Of water flown in 1hour = π x 100 x 300000 cm3 Tank to be filled= π x 500 x 500 x 200 Time required to fill the tank of farmer = Vol. Of tank / Vol. Of water flown = π × 500 × 500 × 200/ π ×100 × 300000 hours 5/3 hours = 1/2/3 hours 1 hour 40 minutes = 60 + 40 minutes = 100

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Raushan Gautam 6 years, 10 months ago

Please wait a moment

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Drishti Arora 6 years, 10 months ago

Ansr guys.. Be quick.. I need to know it as soon as possible

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Tan A+B=√3 tan A-B#1/√3 find A and B

Posted by Nabeela Hasan 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Nabeela Hasan 6 years, 10 months ago

Thank you so much ?

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Amit Chaudhary 6 years, 10 months ago

TanA+B=√3 TanA+B=tan 60 eq...1 A+B=60.....1 TanA-B=1/√3 TanA-B=tan 30eq....2 A-B=30.....2 From eq...1 A+B=60...1 A-B=30....2 2A=90 A=90/2 A=45 Putting...1 A+B=60 45+B=60 B=15

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Can't we plot the frequency on y axis in o give representation???

Posted by Devesh Chaurasiya 6 years, 10 months ago

CBSE > Class 10 > Mathematics