CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Theorm : In a right triangle, the sq. Of the hyp. is equal to the sum of the sq. Of the other two sides. Proof : In a right ∆ ABC right angled at B. Prove : AC ka 2 = AB ka 2 + BC ka 2 BD is parrallel to AC ∆ADB ~ ∆ ABC AD/AB = AB/AC ( side are propotional) AD.AC = AB ka 2 ∆BDC ~∆ABC CD/BC =BC / AC CD. AC = BC ka 2 AD.AC. + CD.AC = AB ka 2 + BC ka 2 AC (AD + CD) = AB ka 2 + BC ka 2 AC.AC. = AB ka 2 + BC ka 2 AC ka 2 = AB ka 2 + BC ka 2

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If an=3+5n ,find sn

Posted by Sachin Sain 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Name the sum of Ap formula

Posted by Murattu Mugesh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Sneha Singh 6 years, 10 months ago

N/2{2a+(n-1)d}

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Paras ? ? Shah ? ? 6 years, 10 months ago

The nth term of an AP with first term (a) and common difference (d) an = a+(n-1)d an is also called the genral term of the AP. If there are n terms in the AP, then (an ) represents the last term l

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Da Ya 6 years, 10 months ago

N/2[2a+<n-1>d]

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Da Ya 6 years, 10 months ago

N/2[2a-<n-1>d]

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If x= -1/2, is a solution of the quadratic equation 3xsquare + 2kx -3=0, find the value of k

Posted by Rakesh Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Honey ??? 6 years, 10 months ago

Put the value of x in the eqn. and then solve it u will get the answer?????????????????????????

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A right angle triangle ABC right angled at C prove that tanA=cotB

Posted by Noel Biju 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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If the sum of first m term of an AP is 2msquare+3m then what is its second term?

Posted by Romal Shahare 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Anjali Mishra?? 6 years, 10 months ago

Given:Sm=2m^2+3m Tm=Sm-Sm-1 Tm=2m^2+3m-2(m-1)^2+3(m-1) Tm=2m^2+3m-2m^2-2+4m+3m-3 Tm=10m-5 T2=10(2)-5 T2=15

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Root 5 is a irrational number

Posted by Annu Meena 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Sneha Singh 6 years, 10 months ago

Let root 5 be a rational number Then, √5= a/b Now by squaring both sides 5= a²/b² = 5b² = a²............(1) Here 5 divides a², Therefore 5 also divides a. Now let a= 5c where c is an integer Now by squaring both side, = A²= 25c² = 5b² = 25c². ( A²= 5b² from above) = B² = 5c² Here 5 divides b square Therefore 5 also divides b. Here a and b both have common factor 5 So our assumption was wrong Therefore root 5 is an irrational number

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A,B,C are interior angles of ∆ABC . Prove that cosec(A+B/2) = sec C/2.

Posted by Dipali Shrivastava 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Rakesh Kumar Tiwari 6 years, 10 months ago

cosec(A+B)/2 = cosec(180-C)/2. [since A+B+C=180] = cosec (180/2 - C/2) = cosec (90 - C/2) = sec C/2

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A well of diameter 4m is dug 14m deep. The earth taken out is spread evenly all around the well to form a 40cm high embankment. Find the width of the embankment

Posted by Rakesh Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

According to the question,the well of diameter 4 metre is dug 14 metre deep.
We are given that, Depth of well = 14 m, radius = 2 m.
Volume of earth taken out {tex}= \pi r ^ { 2 } h{/tex}

{tex}= \frac { 22 } { 7 } \times 2 \times 2 \times 14{/tex}

{tex}= 176 m ^ { 3 }{/tex}

Let r be the width of embankment,then

the radius of outer circle of embankment = 2 + r

Area of upper surface of embankment {tex}= \pi \left[ ( 2 + r ) ^ { 2 } - ( 2 ) ^ { 2 } \right]{/tex}

Volume of embankment = Volume of earth taken out

or, {tex}\pi \left[ ( 2 + r ) ^ { 2 } - ( 2 ) ^ { 2 } \right] \times 0.4 = 176{/tex}

or, {tex}\pi[4 + r^2 + 4r-4] \times 0.4 = 176{/tex}

or, {tex}r ^ { 2 } + 4 r = \frac { 176 \times 7 } { 0.4 \times 22 }{/tex}

or, {tex}r ^ { 2 } + 4 r = 140{/tex}

or, {tex}r ^ { 2 } + 4 r - 140 = 0{/tex}

or, {tex}( r + 14 ) ( r - 10 ) = 0{/tex}

or, r = 10 m [as radius can't be negative]

Hence width of embankment = 10 m.

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A truck covers a distance of 150km at a certain average speed and then covers another 200km at an average speed which is 20km/hr more than the first speed. If the truck covers the total distance in 5 hours find the first speed of the truck.

Posted by Aayushi Gurjar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let the average speed of truck be x km/h.
{tex}\frac { 150 } { x } + \frac { 200 } { x + 20 } = 5{/tex}
or, 150x + 3000 + 200x = 5x(x + 20)
or, {tex}x ^ { 2 } - 50 x - 600 = 0{/tex}
or, {tex}x ^ { 2 } - 60 x + 10 x - 600 = 0{/tex}
or, {tex}x ( x - 60 ) + 10 ( x - 60 ) = 0{/tex}
or, (x-60)(x + 10) = 0
or, x = 60 ; or x = -10
as, speed cannot be negative
Therefore, x=60 km/h
Hence, first speed of the truck = 60 km/h

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PE+Pnot E=1

Posted by Desi Comediean Boys 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Any tangent on a point are perpendicular to the center of the circle......... Guys 90 degree banega ya 90+90 =180 because tangent tangent se straight hai to 180

Posted by Abhishek Maurya 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Sankalp Awasthi 6 years, 10 months ago

Bt tangent circle ki radius ke context me 90 hai....so surely it will be 90 degree...

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If PAB be the secant of a circle which intersects the circle at Aand B and PT Tangent segment PT=10cm PA=5cm then find AB

Posted by Preeti Verma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Rakesh Kumar Tiwari 6 years, 10 months ago

PA×PB=PT² = 5× PB = 10² = PB = 100/5= 20 Then AB = 20-5= 15 cm

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prove that square root of 2 is irrational?

Posted by Manas Kole 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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The 17th term of an AP exceeds its 10th term by 7. Find the common difference

Posted by Ayesha Liyana 6 years, 10 months ago

CBSE > Class 10 > Mathematics

5 answers

Thirsha Udhayakumar 6 years, 10 months ago

a+16d=a + 9d +7 a+16d-a - 9d=7 7d=7 d=1

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Honey ??? 6 years, 10 months ago

You too

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Puja Sahoo? 6 years, 10 months ago

Super fast.....???

3Thank You

Puja Sahoo? 6 years, 10 months ago

d=1

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Honey ??? 6 years, 10 months ago

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In an isosceles triangle ABC with AB equal to AC. BD is perpendicular on B to the side of Ac. prove that BDsqare -CDsqare =2CD.AD

Posted by Harsh Rajpoot 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the other zero of the quadratic polynomial y square+7y_60 if one zero is _12

Posted by Anubha Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Rakesh Kumar Tiwari 6 years, 10 months ago

Sum of zeroes= -b/a = -12+X= -7/1 = X = -7+12=5

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Honey ??? 6 years, 10 months ago

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The ratio of7th to the 3rd term of an AP is 12:5. Find the ratio of 13th to the 4th term

Posted by Prabhakar Pankaja 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Yash Mulik 6 years, 10 months ago

Take a7/a3 = 12/5 you will get valuez then put those values in second part ?

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Honey ??? 6 years, 10 months ago

10:3

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SinA-sin^2A=1 then find cos^2A-cosA=?

Posted by Ramakant??? 8306360538 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Class interval. Frequescy 000-100 2 100-200. 5 200-300 X 300-400. 12 400-500. 17 500-600. 20 600-700. Y 700-800 09 800-900. 07 900-1000. O4 The median of data is 525.Find X and Y if the total frequency.

Posted by Tript Preet???? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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A box contain 12 ball out of which x are black if one ball is drawn at random from box. What is the probability it will be black ball. If 12 more black ball are put in the box. Now the drawing is black ball is double of before find the value of x . No of black ball

Posted by Lalit Choudhary 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Lalit Choudhary 6 years, 10 months ago

Total ball = 12 No. Of balck ball = x P(e) = x /12 Now, 12 black ball are added Total ball = 24 Now, black ball = x + 12 P(e) = x+12/24 Now, according to the question, X+12/24=2×x/12 X+12/24×6=x X+12=4 X=4

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