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Dis travelled in15 sec with speed 720 km/h is720/15 =48 km.................................. Let the dis. Betwn initial position of jet and person be x The dis. Betwn initial positionof jet and person = 48+x Tan60 = h/x =>root 3 = h/x =>x = h/root3 Tan 30 = h/48+x =>1/root3 = h×root 3/48 root 3 + h =>48 root3+h = 3h => 48 root3 = 2h => h = 24 root3 αɳรωε૨

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If for some angle ,cot 2¤=1/√3,then the value of sin 3¤,where 2¤is<or=to 90°

Posted by Pooja Singh??? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhinav Yadav 6 years, 10 months ago

sin 3 theta is 1

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Find the value of a, for which point P (a 3, 2)is the mid -point of the line segment joining the points Q(-5,4)and R (-1,0).

Posted by Jisai Tripura 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Rituraj Dadhich 6 years, 10 months ago

Value of a is -9

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Find the greatest six digit number that is exactly divisible by 18 ,24,36?

Posted by Abhishek Giri 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 10 months ago

First find the LCM of 18 , 24 and 36
18 = 2×9 =2×3×3
24=2×12 = 2×2×6 = 2×2×2×3
36=2×18 =2×2×9 =2×2×3×3
LCM=2×2×2×3×3×3
= 8×27
= 216
We need 6 digit greatest number so multiply it my a number
216 × 4629 = 999864

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A vertical a vertical Tower stands on a horizontal plane and is surmounted by a vertical flagstaff of height 5m from a point on the plane the angles of the elevation the bottom and the top of the flagstaff are 30 degree and 60 degree find the height of the tower

Posted by Back Bencher 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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An arithmetic progression 5,12,19......has 50 terms. Find its last term. Hence find the sum of its last 15 terms.

Posted by Esha Pal 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have {tex}a = 5{/tex} and {tex}d = 12 - 5 = 7{/tex} and {tex}n = 50{/tex}
{tex}a_n = a + (n - 1)d{/tex}
{tex}\therefore{/tex} a₅₀ = 5 + (50 -1 )7
= 5 + 49 {tex}\times{/tex} 7
= 5 + 343
= 348
Also the first term of the A.P of last 15 terms be a₃₆
a₃₆ = 5 + (36 - 1)7
= 5 + 35 {tex}\times{/tex} 7
= 5 + 245
= 250
Now, sum of last 15 terms
{tex}\therefore \quad S _ {15} = \frac { 15 } { 2 } [ 2 \times 250 + ( 15 - 1 ) 7 ]{/tex}
{tex}= \frac { 15 } { 2 } ( 500 + 14 \times 7 ){/tex}
{tex}= \frac { 15 } { 2 } ( 500 + 98 ){/tex}
{tex}= \frac { 15 } { 2 } \times 598{/tex}
= {tex}15 \times 299{/tex}
= 4485
Hence, sum of last 15 terms = 4485

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Is it possible to design a rectangular mango grove whose length is twice its breadth and the areas is 800m^2? If so, find its length and breadth.

Posted by Harish Mangaraj 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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in the given figure if AD=AE= 2 find area DB EC

Posted by Akash Gill 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Ab2 =ay2+bc2÷4-bc.xy

Posted by Shri Krishan 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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A sum of ₹700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is ₹20 less than its preceeding prize, find the value of each of the prizes

Posted by Nitu Pandey 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 10 months ago

This is an AP

here n=7,d=-20,Sn=700

Sn=7/2(2a+6x-20)=700

7(a-60)=700

a-60=100 ,a=160

So prizes are: 160,140,120,100,80,60,40

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Find the sim of all three digiy number which leaves the remainder 3 when divided by 7

Posted by Abhilash Pathak 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Abhinand K 6 years, 10 months ago

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Abhilash Pathak 6 years, 10 months ago

Find the sum of the three digit number which leaves the remainder 3 when divided by 7

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Find the mode of following frequency distribution Mark | no.of student 10-20 | 12 20-30 | 35 30-40 | 45 40-50 | 25 50-60 | 13

Posted by Vishal Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Divide 204 in four parts such that they form an AP. The product of extremes is to product of means equal to 5 is to 6.

Posted by Shreya Shukla 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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In given figure ABPC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter . Find the area of the shaded region.

Posted by Baljeet Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Lionel Messi⚽️ 6 years, 10 months ago

You can see in this app question 15 chapter 12 exercise no. 12.3

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Lionel Messi⚽️ 6 years, 10 months ago

Yes

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Gaurav Seth 6 years, 10 months ago

In given figure ABPC is a quadrant of a circle of radius 14 cm and a semicircle is drawn diameter. Find the area of the shaded region.

<hr />

We know,

AC = r

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On selling a T.V at 5% gain and a fridge at 10% gain. A shopkeeper gains 2000 rs. But if he sells the T.V at 10% gain and a fridge at 5% loss. He gains 1500 rs on the transaction. Find the actual price of T.V and fridge

Posted by Mausam Chahal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

Let the price of a T.V. be Rs x and that of a fridge be Rs y. Then, we have

Hence, the actual price of T.V =20, 000 and, the actual price of fridge =RS 10,000

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Some students planned a picnic. The total budget for food was 2000 rs . Due to confusion 5 students failed to attend the picnic and thus the cost of food for each member increased by 20 rs . How many students attended the picnic and how much each students pay for the food

Posted by Mausam Chahal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

Q.Some students planned a picnic. The total budget for food was Rs.2000. But, 5 students failed to attend the picnic and thus the cost for food for each member increased by Rs.20. How many students attended the picnic and how much did each student pay for the food?

<hr />

Let x be the number of students who planned a picnic.

Original cost of food for each member = Rs. 2000/x

Five students failed to attend the picnic. So, (x-5) students attended the picnic.

New cost of food for each member = Rs. 2000/(x-5)

According of the given condition,

Number of students who attended the picnic = x-5 = 23-5= 20

Amount paid by each student for the food = Rs. 2000/(25-5) = Rs. 2000/20 = Rs.100

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In a circle of diameter 40 cm a rhombus is inscribed with all its vertices on the circle . Find the area of rhombus

Posted by Mausam Chahal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

When a rhombus is inscribed with all its vertices than its diagonals will be the diameter of the circle
length of the diagonal= 40cm
area of rhombus = 1/2 x diagonals²
= 1/2 x 40 x 40
= 800 cm²

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If -4 is a root of the equation x2+px-4=0and the equation x2+px+q=0 has equal roots .Find the values of p and q.

Posted by Mausam Chahal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Mausam Chahal 6 years, 10 months ago

I don't understand

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Mr.Raj Sharma 6 years, 10 months ago

x²+px-4=0 putting the value x=-4 (-4)²+p(-4)-4=0 16(2)-4p-4=0 32-4p-4=0 28-4p=0 28=4p p=28/4 p=7 now.x²+px+q has equal roots so (b)²-4ac=0 (p) ²-4(1)(q)=0 (7)²-4q=0 49-4q=0 49=4q q=49/4 THAT'S THE SOLUTION

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The sum of n,2n, 3n terms of an A.P are S1,S2, S3 . Prove that S3 = 3(S2-S1)

Posted by Mausam Chahal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Ayesha P 6 years, 10 months ago

S1= sum of n terms = n|2{2a+(n-1)d} S2= sum of 2n terms = 2n|2{2a+(2n-1)d} S3= sum of 3n terms= 3n|2{2a+(3n-1)d} Lhs=3(S2-S3)=2n|2 {2a+(2n-1)d} - n|2 {2a+(n-1)d} =3n|2{2a+(3n-1)d} Hence S3=3(S2-S1)

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Gaurav Seth 6 years, 10 months ago

Let the first term of the A.P. be a and the common difference be d.

According the question,

We have to prove that S₃ = 3 ( S₂ – S₁).

R.H.S = 3 (S₂ – S₁)

= S₃

= L.H.S

⇒ S₃ = 3 ( S₂ – S₁)

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Water is flowing at the rate of 2.52km/h through a cylindrical pipe into a cylindrical tank ,the radius of whose base is 40 cm. If the increase in the level of water in the tank , in half an hour is 3.15 m . Find the internal diamrter of the pipe.

Posted by Mausam Chahal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

Let the internal diameter of the pipe be r m.

water flows in 1 hour = 2.52 km.

Internal diameter of pipe = 4 cm.

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in a city 30% are females 40% are male and remaining are the children . What percent are children

Posted by Surendra Majhi 6 years, 10 months ago

CBSE > Class 10 > Mathematics

5 answers

Dhruv Prajapati 6 years, 10 months ago

30% will be the answer because the maximum probability is of 1 or 100% and since male and female constitutes 70%. Therefore, the remaining 30% will be children.

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Chetna Saini 6 years, 10 months ago

30%

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Honey ??? 6 years, 10 months ago

I think it would be more than 30%

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Mansi ??⚘?? 6 years, 10 months ago

30%

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Honey ??? 6 years, 10 months ago

Children also come in males and females