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Ask QuestionPosted by Muskan Bedi 6 years, 10 months ago
- 5 answers
Khushboo Giri 6 years, 10 months ago
Ritika Bisht 6 years, 10 months ago
Posted by Nitish Sharma 6 years, 10 months ago
- 3 answers
Ram Kushwah 6 years, 10 months ago
One of several centers the triangle can have, the circumcenter is the point where the perpendicular bisectors of a triangle intersect. The circumcenter is also the center of the triangle's circumcircle - the circle that passes through all three of the triangle's vertices.
Geetanand Yadav 6 years, 10 months ago
Posted by Sanjeev Kumar 5 years, 8 months ago
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Ritika Bisht 6 years, 10 months ago
Posted by Jikrullah Alam 6 years, 10 months ago
- 3 answers
Posted by Rajan Tomar 6 years, 10 months ago
- 1 answers
Posted by Jagtarsingh Chohan 6 years, 10 months ago
- 1 answers
Sia ? 6 years, 6 months ago
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Posted by Zeenath Banu 6 years, 10 months ago
- 4 answers
Harsha Asiwal 6 years, 10 months ago
Posted by Swarnima Dhabre 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
Let a be any positive integer and b = 3
a = 3q + r, where q ≥ 0 and 0 ≤ r < 3
Therefore, every number can be represented as these three forms. There are three cases.
Case 1: When a = 3q,
Where m is an integer such that m = (3q)3 = 27q3
9(3q3) = 9m
Case 2: When a = 3q + 1,
a3 = (3q +1) 3
a3 = 27q3 + 27q2 + 9q + 1
a3 = 9(3q3 + 3q2 + q) + 1
a3 = 9m + 1
Where m is an integer such that m = (3q3 + 3q2+ q)
Case 3: When a = 3q + 2,
a3 = (3q +2)3
a3 = 27q3 + 54q2 + 36q + 8
a3 = 9(3q3 + 6q2 + 4q) + 8
a3 = 9m + 8
Where m is an integer such that m = (3q3 + 6q2+ 4q)
Therefore, the cube of any positive integer is of the form 9m, 9m + 1, or 9m + 8.
Posted by Sunil Verma 6 years, 10 months ago
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Posted by Jyoti Gupta 6 years, 10 months ago
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Posted by Prayansh Singh 6 years, 10 months ago
- 2 answers
Harshita Srivastava 6 years, 10 months ago
Posted by Deepanshu Kandpal 6 years, 10 months ago
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Raj Dhali 6 years, 10 months ago
Posted by Satyam Singh 6 years, 10 months ago
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Posted by Princi Lakhere 6 years, 10 months ago
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Harshita Srivastava 6 years, 10 months ago
Posted by Jaiswal Satish 6 years, 10 months ago
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Kratika Nyati 6 years, 10 months ago
Posted by Mahi ✌?? 6 years, 10 months ago
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Yogita Ingle 6 years, 10 months ago
Given, 1 + 4 + 7 + 10 +...+ x = 287
This series in AP.
Now, first term a = 1, common difference d = 4 - 1 = 3
Last term l = x
Let number of terms = n
Now, Sum of the seires Sn = 287
=> (n/2) ×{2a + (n - 1)d} = 287
=> (n/2) ×{2 + (n - 1)3} = 287
=> (n/2) ×{2 + 3n - 3} = 287
=> (n/2) ×{3n - 1} = 287
=> n ×(3n - 1) = 287 ×2
=> 3n2 - n = 574
=> 3n2 - n - 574 = 0
=> (n - 14) ×(3n + 41) = 0
=> n = 14, -41/3
Since n can not be negative,
So, n = 14
i.e. there are 14 terms in the series and x is the 14th term.
So, x = a14 = a + (14 - 1)d
=> x = a + 13d
=> x = 1 + 13 ×3
=> x = 1 + 39
=> x = 40
So, the value of x is 40
Posted by Nihal Hacker 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
lf 2x, x + 10, 3x + 2 are in A.P.,we have to find the value of x.
Since, 2x, x + 10, 3x + 2 are in A.P.therefore 2 (x + 10) = 2x + 3x + 2
{tex}\Rightarrow{/tex} 2x + 20 = 5x + 2
{tex}\Rightarrow{/tex} 3x = 18 {tex}\Rightarrow{/tex} x = 6
Posted by Rïshäbh Yádàv 6 years, 10 months ago
- 2 answers
Ram Kushwah 6 years, 10 months ago
A=11 D=-3
LET Tn=-150
-150 = 11+(n-1)(-3)
-150=11-3n+3
-3n=-164
n=164/3=54.66
n is not a integer so -150 is not term of AP
Aryan Khare 6 years, 10 months ago
Posted by Sonam Sharma 6 years, 10 months ago
- 3 answers
Gaurav Seth 6 years, 10 months ago
Let the length of side be x
Applying Pythagoras theorem,
(√3)²+(x/2)²=x²
3+(x²/4)=x²
(12+x²) /4=x²
12+x²=4x²
12=4x²-x²
12=3x²
4=x²
√4=x
2=x
Then length of side is 2cm
Posted by Abhijeet Raj 6 years, 10 months ago
- 2 answers
Gaurav Seth 6 years, 10 months ago
We know,
one important identity ,
sin( A + B) =sinA.cosB + cosA. sinB
let A = x
B = x
then,
sin( x + x ) = sinx.cosx + cosx .sinx
sin2x = 2sinx.cosx
verify :-
Let x = 30°
LHS = sin60° = √3/2
RHS = 2sin30°.cos30° = 2× 1/2 × √3/2 =√3/2
LHS = RHS
this is true for all real value of x then ,
sin2x = 2sinx.cosx is also an identity.
Ram Kushwah 6 years, 10 months ago
We know
sin(x+y)=sinxcosy+cosxsiny
if x=y then
sin(x+x)=sinxcosx+cosxsinx
sin2x=2sinxcosx
Posted by Pratik Chowdhury 6 years, 10 months ago
- 2 answers
Posted by Kunal Kumar Tiwari 6 years, 10 months ago
- 1 answers
Ram Kushwah 6 years, 10 months ago
sin43=sin(90-47)=cos47=a
{tex}\begin{array}{l}cot43=\sqrt{1+}\cos ec^243\\=\sqrt{1+\frac1{a^2}}=\frac1a\sqrt{1+a^2}\\\tan43=\frac1{cot43}=\frac a{\sqrt{1+a2}}\end{array}{/tex}
Posted by Harshita Nawaria 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
{tex}\frac{\operatorname{arc}(\triangle \mathrm{ABC})}{\operatorname{ar}(\triangle \mathrm{QRP})}{/tex} = {tex}\left(\frac{B C}{R P}\right)^{2}{/tex}
{tex}\Rightarrow{/tex} {tex}\frac{9}{4}{/tex} = {tex}\left(\frac{15}{P R}\right)^{2}{/tex}
{tex}\Rightarrow{/tex} PR = 10 cm
Posted by Nit Nit 6 years, 10 months ago
- 1 answers
Ram Kushwah 6 years, 10 months ago
{tex}\begin{array}{l}2^n\times5^n=10^n\\If\;n=0\;then\;10^n=1\\If\;n>0\;then\;10^n\;ends\;with\;0\\If\;n<0\;then\;10^n\;1s\;in\;form\;0.1,\;0.01--\\\end{array}{/tex}
Hence for any value of n 2^n x 5^n can not end with 5
Posted by Loguss Sancheti 6 years, 10 months ago
- 1 answers
Harshita Singh 6 years, 10 months ago
Posted by Ramesh Prajapat 6 years, 10 months ago
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Sonam Sharma 6 years, 10 months ago
Posted by Vaishnavi Agrawal 6 years, 10 months ago
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Dipti Singh 6 years, 10 months ago
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