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Point on y-axis,then x=0 Therefore p(0,y) AB=BC √(6-0)²+(5-y)²=√(-4-0)²+(3-y)² Sq.both side (6)²+(5-y)²=(4)²+(3-y)² 36+25+y²-10y=16+9+y²-6y 61-25=10y-6y 36=4y y=9

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Anyone knows French

Posted by Twinkle Star ( Atul )....... ?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Avanish Yadav 6 years, 10 months ago

heean

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What is a homologous serious of carbon compound

Posted by Twinkle Star ( Atul )....... ?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Mani Raj 6 years, 10 months ago

It is a series of compound in which some functional group subsitutes for hydrogen in a carbon chain e.g.-ch3cooh, C2H5OH

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??Róyál⛔⛔ ????Himánshú⚡⚡ 6 years, 10 months ago

The series which differ for ch2 of any functinal group

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Karthik N Agasimani 6 years, 10 months ago

Same in structure

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Ram ram friends

Posted by Twinkle Star ( Atul )....... ?? 5 years, 8 months ago

CBSE > Class 10 > Mathematics

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Badusha Badu 6 years, 10 months ago

????

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Also me too

Posted by Nitish Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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Anyone knows about alternative segment theorm

Posted by ??Róyál⛔⛔ ????Himánshú⚡⚡ 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

??Róyál⛔⛔ ????Himánshú⚡⚡ 6 years, 10 months ago

The alternate segment theorem states that an angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.

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Khushboo Giri 6 years, 10 months ago

In any circle, the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment, i.e. the angle subtended by the chord in the opposite side of the previous angle.

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Twinkle Star ( Atul )....... ?? 6 years, 10 months ago

No please also tell me

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If alpha and beta are the zeroes of the quadratic polynomial x2+px+q then prove that alpha2÷beta2+beta2÷alpha2=p2÷q2-4p2÷q+2

Posted by Pratyush Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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What is the value of √[sin^2(30)*cos ^2(60)]

Posted by Ninja Servers 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Pankaj Sagar 6 years, 10 months ago

√sin²30°×cos²60° Sol. Sin30°=1/2 therfor sin²30=(1/2)² Cos60°=1/2 similar cos²60=(1/2)² √sin²30×cos²60 √(1/2)²×(1/2)² √1/4×1/4 √1/16 1/4 answer

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Tow chords AB&CD intersect each other at point p . Prove that triangleAPC similar to triangle DPB

Posted by Kumar Rohit 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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??Róyál⛔⛔ ????Himánshú⚡⚡ 6 years, 10 months ago

Your questin was right

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Khushboo Giri 6 years, 10 months ago

<PAC=<PBD(interior alternate angles) <PCA=<PDB(interior alternate angle) Therefore, ∆APC~∆DPB(byAA)

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Khushboo Giri 6 years, 10 months ago

Given: AB&CD are chords. PT:∆APC~∆DPB construction: Join AC&BD such that AC||BD. Prove: In∆APC &DPB :<ACP=<BDP(interior alternate angle) :<PAC=<PBD(interior alternate angle) :THEREFORE, ∆APC~∆DPB(byAA)

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tan ^2 + cot ^2 = 2 then tan + cot =

Posted by Rajiv Ranjan 6 years, 10 months ago

CBSE > Class 10 > Mathematics