CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

N=20 and 5 both Solve with the help of sum formulae Sn=n/2{2a+(n-1)d} -50=n/2{2*-6+(n-1)1/2. .. . d=1/2 -100=-25n+n^2+..... n^2-25n+100=0..... n^2-2on-5n+100=0..... n(n-20)-5(n-20)=0 n=20and n=5

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there are three villages a b and c such that the distance from a to b is 7 km b2c 5 km c2a 8 km the gramapanchayath wants to dig a well in such a way that the distance of the well from each village is equal

Posted by Radhakrishnan Nair 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Harsh Chahar 6 years, 10 months ago

Position of well is the centre of circle that passes through these three points a b and c

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Cbse 2014 question paper

Posted by Muskan Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

??Róyál⛔⛔ ????Himánshú⚡⚡ 6 years, 10 months ago

????

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What is the hcf of smallest prime number and the smallest composite number

Posted by Ashok Kumer 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Shruti Rai 6 years, 10 months ago

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Priyanshi Khandelwal 6 years, 10 months ago

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Ashok Kumer 6 years, 10 months ago

2 and 4

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Can you tell me that where we can apply lcm and hcf in ch1 word problems

Posted by Komal Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Komal Singh 6 years, 10 months ago

No it is applied in few cases only

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Shivay Brahmåñ 6 years, 10 months ago

If you see in question the least less minimum apply lcm and if you see the word maximum more high apply hcf

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Read

Posted by Ankit Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Priyanshi Khandelwal 6 years, 10 months ago

?????

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Geetanand Yadav 6 years, 10 months ago

?????

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Of the numerator and denominator of a fraction is 3 less than twice the denominator if each of the numerator and denominator is decreased by 1 the fraction becomes 1 by 2 find the fraction

Posted by Muskan Gandhi 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Geetanand Yadav 6 years, 10 months ago

Given in NCERT but value may be different

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Show that any positive odd integer is in the form 4q+1 or 4q+3 when q is some integer

Posted by Rithiga Mohan Raj 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Geetanand Yadav 6 years, 10 months ago

Let a=bq+r(where r=0,1,2,3) But in this we have only to take odd numbers So r=1,3 Put the value of r you will get the answer hope it helps you.....

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If sin(thita) = cos(thita), then find the value of 2tan(thita)+cos(square thita)

Posted by Ritik Paswan 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Ritik Paswan 6 years, 10 months ago

But it's answer is 5/2?

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Chetna ☺️ 6 years, 10 months ago

√2 + 2/2

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Shivay Brahmåñ 6 years, 10 months ago

2+sin^2thetha

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If a and b are zeroes of the polynomial x^2+ax-b then find the value of a and b......plzzz tell me wid complete solution

Posted by Gungun ❤❤❤ 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Geetanand Yadav 6 years, 10 months ago

First do sum of zeroes than product of zeroes you will get two equation compare it you will get the answer

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Find the coordinates of the point on y_axis which is nearest to the point(-2,5)

Posted by Niyati Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the area of minor segment of a circle of radius 42 CM if length of the corresponding arc is 44 CM

Posted by Yash Sonawane 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Geetanand Yadav 6 years, 10 months ago

Area of minor segment=πr^2theta/360-r^2/2*sin theta

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If one zero of p(x) = 4xsquare-(8ksquare-4k)x-9 is negative of the other find the value of k

Posted by Thakur Sakshi Singh 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let, the two zeroes of the polynomial f(x) = 4x² - 8kx - 9 be α and -α.
Comparing f(x) = 4x² - 8kx - 9 with ax²+bx+c we get
a = 4; b = -8k and c = -9.
Sum of the zeroes = α + (-α) ={tex}-\frac ba=\;-\frac{-8k}4 {/tex}
0 = 2k
k = 0

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If 4tan =3 Evaluate (4sin-cos+1 ÷4sin +cos-1)

Posted by Akshata Akshata 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Diksha Kharwal 6 years, 10 months ago

Mera to 24/5 aa rha hai

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Ayush Ak 6 years, 10 months ago

Tan theta = 3/4 =P/B Therefore P=3x B=4x H²=3²+4²=25 H=5 Sintheta =3/5 ,. Cos theta = 3/5 (4)(3/5) -4/5 +1 ÷(4)(/5)+4 =13/11

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Shivay Brahmåñ 6 years, 10 months ago

The correct answer os 13/11 Tan theth =p/b p=3 b=4 h=5 pit the value of these and answer is 13/11

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Diksha Kharwal 6 years, 10 months ago

24/5 is the answer

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ABC is a triangle in which angle B = 90°. A circle is drawn with AB as diameter intersecting the hypotenuse AC at P. Prove that the tangent drawn to the circle at P, bisects BC.

Posted by Bhavya Garg 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given: ΔABC in which ∠B = 90°

Circle with diameter AB intersect the hypotenuse AC at P.

A tangent SPQ at P is drawn to meet BC at Q.

To prove: Q is mid point of BC.

Construction: Join PB.

Proof: SPQ is tangent and AP is chord at contact point P.

Therefore,∠2 = ∠3 [ since Angles in alternate segment of circle are equal]

∠2 = ∠1 [Vertically opposite angles]

∠3 = ∠1 …(i) [From above two relations]

∠ABC = 90° [Given]

OB is radius , therefore BC will be tangent at B.

Therefore,∠3 = 90° - ∠4 …(ii)

∠APB = 90° [∠ in a semi circle]

⇒ ∠C = 90° - ∠4....(iii)

From (ii) and (iii), ∠C = ∠3

Using (i), ∠C = ∠1

⇒ CQ = QP …(iv) [Sides opp. to = ∠s in ΔQPC]

∠4 = 90° - ∠3 [From fig.]

∠5 = 90° - ∠1

∠3 = ∠1

Therefore,∠4 = ∠5

⇒ PQ = BQ …(v) [Sides opp. to equal angles in ΔQPB]

From (iv) and (v),

BQ = CQ

Therefore, Q is mid-point of BC. Hence, proved.

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Find the value of a,for which point p(a/3,2) is the midpoint of the line segment joining the point q(-5,4) and r(-1,0)

Posted by Àmån Šhármä 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Shivay Brahmåñ 6 years, 10 months ago

a/3=-5-1/2 a/3=-6/2 a/3=-3 a=-9 ans

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Simran Mander 6 years, 10 months ago

x1+x2/2=a/3 -5+(-1)/2=a/3 -6=a/3 a=-6/3 a=-9

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Bhavya Garg 6 years, 10 months ago

A = -9/2

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The wheels of a car of diameter 80cm each. How many complete revolution does each wheel make in 10 min when the car is travelling at a speed of 66 km per hour? Plz rply fast . Urgent ?

Posted by Yash Sharma ?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivay Brahmåñ 6 years, 10 months ago

Answer is 4375. 66*10/60 as 10minute is given =1100000cm 11km=1100000cm 2*22/7*40*n=1100000 N=4375 N no of turns

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Mid point theorem

Posted by Jashan Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Pinki Kumari 6 years, 10 months ago

Refer 9 class ncert

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743,22×4,333

Posted by Shubham Dsm 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Gautam Prajapati 6 years, 10 months ago

322,037,226

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Sarika Popli 6 years, 10 months ago

322037226

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Ram Kushwah 6 years, 10 months ago

Use calculator

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Prove that tan theta minus cot theta by sin theta cos theta equal to tan square theta minus cot square theta

Posted by Radhakrishnan Nair 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Ritika Bisht 6 years, 10 months ago

Pic kese attach ki

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Ayush Ak 6 years, 10 months ago

tan theta - cot theta /sin theta cos theta =tan² theta - cot² theta Sin theta/cos theta - cos theta/sin theta ÷sintheta cos theta Sin² theta - cos² theta ÷sin² theta cos²theta RHS tan² theta - cot² theta Sin² theta /cos² theta - cos²theta /sin² theta Sin² theta - cos² theta ÷ sin² theta cos² theta Since LHS = RHS HENCE PROVED

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E and F are points on the sides PQ and PR respectively of triangle pqr for each of the following cases state whether a parallel QR question number 2 b equals to 4 cm equals to 4.5 cm equals to 8 cm and Rs equals to 9 CM prove parallel Cuba

Posted by Abhinav Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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If the diameter of the wheel of the car is 84 cm. Find the number of revolutions will have to make it to travel the distance of 13.2 km

Posted by Samyuktha Mayuri 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Shivay Brahmåñ 6 years, 10 months ago

The correct answer is 5000 2*22/7*42n=1320000 n=5000 n=no of turns 13.2 km =1320000

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Dipti Singh 6 years, 10 months ago

9 revolution

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Write the exponent of 3 in the prime factorisation of 162

Posted by Vidhya Venkatachalam 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 10 months ago

162=18 x 9

=2 x 9 x 9

= 2 X 3^4

hence exponent =4

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Show that 21 power n cannot end with the digit 0,2,4,6 and 8 for any natural number n

Posted by Vidhya Venkatachalam 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Ram Kushwah 6 years, 10 months ago

{tex}\begin{array}{l}21^{\mathrm n}=3^{\mathrm n\;}\times7^{\mathrm n}\\\mathrm{Now}\;3^{\mathrm n\;}\;\mathrm{and}\;7^{\mathrm n\;}\;\mathrm{are}\;\mathrm{always}\;\mathrm{odd}\;\mathrm{for}\;\mathrm{all}\;\mathrm{values}\;\mathrm{of}\;\mathrm n\\\mathrm{odd}\;\times\;\mathrm{odd}\;=\mathrm{odd}\\\mathrm{Hence}\;\;3^{\mathrm n\;}\times7^{\mathrm n}\;\mathrm{can}\;\mathrm{not}\;\mathrm{end}\;\mathrm{with}\;2,4,6,8\end{array}{/tex}

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Geetanand Yadav 6 years, 10 months ago

It should have an even number as factor in it .but it is not there so it cannot end with digit 0,2,4,6,8

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The 6th term of an AP is zero. Prove that it's 31st term is five times the 11th term.

Posted by Anita Raj 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Puja Sahoo? 6 years, 10 months ago

31st term is a + (31-1)d a + 30d..........(1)....... 11 th term is a +(11-1)d a + 10d so 5 times 11 term is 5a + 50d.........(2)...... so 5 times 11 term is 5a + 50d.........(2)......on comparing with 1 a + 4a + 50d as a = -5d a + 4(-5d) + 50d a - 20d + 50d a + 30d 31st term.... pehle vala answer mt dekho.... ye apka solution hai

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Puja Sahoo? 6 years, 10 months ago

Ek kam kijiye put a6 = 0, ---> a+5d=0..., (a=5d), ab find a31 and a11...... ▪a31= a+30d ....... ▪a31=5d +30d = 35 d........ and a11=a+10d ▪a11=5d +10d =15d......

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Honey ??? 6 years, 10 months ago

Pehle 31st trm nikalo phir 11th trm. Nikalo aur uske baad a=-5d put ksr dena

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Puja Sahoo? 6 years, 10 months ago

Hey, its proved bt yahan solition thoda bada hai, apko kaise dun mai

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