CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Side of square = 10cm
For incircle
diameter of circle = side of square
{tex}\Rightarrow r = \frac{{10}}{2} = 5cm{/tex}
{tex} \therefore {/tex} Area of incircle {tex}= \pi {r^2}{/tex}
{tex}= 3.14 \times 5 \times 5{/tex}
78.50 cm²
For circumcircle
AC will be the diameter because {tex} \angle B = 90^\circ {/tex}
Now, In {tex} \triangle ABC{/tex}, by pythagoras theorem
AC² = AB² + BC²
{tex}\Rightarrow {/tex} AC² = 10² + 10²
{tex}\Rightarrow {/tex} AC² = 200
{tex}\Rightarrow AC = \sqrt {200} = 10\sqrt 2 cm{/tex}
{tex} \therefore {/tex} Area of circumcircle {tex}= \pi {r^2}{/tex}
{tex}= 3.14 \times {\left( {5\sqrt 2 } \right)^2}{/tex}
{tex}= 3.14 \times 50{/tex}
= 157cm²

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Prove that √2+√5 is irrational number

Posted by Esha Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

☠☠☠ ??? 6 years, 10 months ago

Not always irrational.

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Twinkle Star ( Atul )....... ?? 6 years, 10 months ago

Sum of two irrational numbers is always irrational ????

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Cbse Teacher 6 years, 10 months ago

Ans. Let √2+√5 be rational no. (If possible) √2+√5=a/b. (Where a and b are integers)

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Formula that gives relation between mean,meadian and mode is_

Posted by Diwakar Rajput ??? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Aswathy Jiji 6 years, 10 months ago

3 median = mode + 2 mean

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Cbse Teacher 6 years, 10 months ago

3median= 2mean+mode

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Shashank Mishra 6 years, 10 months ago

Mode = 3median -2mean

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ANSWER

Peoof that 5-9root3 is irrarional

Posted by Friend Anjali Bisht 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shivay Brahmåñ 6 years, 10 months ago

5-9✓3=a/b....... 5-a/b=9✓3...... 5b-a/b=9✓3....... 5b-a/9b=✓3...... ✓3 is irrational and 5b-a/9b is rational so this equation is irrational

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Find the median of the following data by makinga 'less than ogive'

Posted by Shaksi Kumari 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Aswathy Jiji 6 years, 10 months ago

Plss check if the question be incomplete

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Shivay Brahmåñ 6 years, 10 months ago

Where is data

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ANSWER

Find perimeter of triangle with vertices (0,4), (0,0)and (3,0)

Posted by Shweta Kashyap 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 10 months ago

First find length of each sides of ∆
Let A( 4 , 0) B(0, 0) and C (0 , 3)
use distance formula,
AB =√(4²+0) =4
BC= √(0+3²) = 3
CA =√(4²+3²) =5
now ,
perimeter of ∆ = 3 + 4 + 5= 12 unit

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Shashank Mishra 6 years, 10 months ago

Answer hai 30 pehle A(0,4) B(0,0) C(3,0) fir AB BC CA ki distance nikalkar jod Dena answer aa jayega

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2 sin square 60 degree plus

Posted by Sukhman Kaur Randhawa 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Elina ❤️ 6 years, 10 months ago

Right S N ....

1Thank You

S N 6 years, 10 months ago

Plz complete your question

2Thank You

Gopikarani Vb 6 years, 10 months ago

3 divided by 2

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Elina ❤️ 6 years, 10 months ago

Pura questions toh likh do plz.... Tabhi toh answer dege ....

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ANSWER

Ex 3.6 question no 1 part 8

Posted by Himanshu Nandmehal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Get NCERT solutions here : <a href="https://mycbseguide.com/ncert-solutions.html">https://mycbseguide.com/ncert-solutions.html</a>

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Ex 3.6

Posted by Himanshu Nandmehal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Himanshu Nandmehal 6 years, 10 months ago

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ANSWER

What is the perimeter of qudrant?

Posted by Harshita Saxena 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Anshika Patel 6 years, 10 months ago

2radius + (π . radius/2)

1Thank You

Gopikarani Vb 6 years, 10 months ago

2radius +(pie×radius/8)

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places a and b are two places 80 km apart a car starts from a place and another car start moving from b point at the same time if they moving same directions they meet in 8 hours and if the most to was each other day made in 1 or 20 minutes.find speed of cars

Posted by Sujal Bhardwaj 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Suppose x and y be two cars starting from points A and B respectively.
Let the speed of the car X be x km/hr and that of the car Y be y km/hr.
Case I: When two cars move in the same directions:
Suppose two cars meet at point Q, then,
Distance travelled by car X = {tex}AQ{/tex}
Distance travelled by car Y = {tex}BQ{/tex}
Distance travelled by car X in 8 hours = 8x km.
{tex}AQ = 8x{/tex}
Distance travelled by car Yin 8 hours = 8y km.
{tex}BQ = 8y{/tex}
Clearly {tex}AQ - BQ = AB{/tex}
{tex}8x - 8y = 80{/tex}
{tex}\Rightarrow {/tex} {tex}x - y = 10{/tex} ...(i)
Case II: When two cars move in opposite direction
Suppose two cars meet at point P, then,
Distance travelled by X car X = AP
Distance travelled by Y car Y = BP
we can write it as 1 hour = {tex}\frac{{20}}{{60}}{/tex}hours.
Therefore, Distance travelled by a car Y in {tex}\frac{4}{3}{/tex}hrs = {tex}\frac{4}{3}{/tex}x km.
AP + BP = AB
{tex}\frac{4}{3}x{/tex} km + {tex}\frac{4}{3} y{/tex} km = 80
{tex}\frac{4}{3}{/tex}{tex}(x + y) = 80{/tex}
{tex}( x + y ) = 80{/tex} × {tex}\frac{3}{4}{/tex}
{tex}x + y = 60{/tex} ...(ii)

By solving equations (i) and (ii), we get, {tex}x = 35.{/tex}
By substituting x = 35 in equation (ii), we get
{tex}x + y = 60{/tex}
{tex}35 + y = 60{/tex}
{tex}y = 60 - 35{/tex}
{tex}y = 25.{/tex}
Hence, speed of car X {tex}= 35\ km/hr.{/tex}
Speed of car Y ={tex} 25\ km/hr.{/tex}

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Ab is diameter of circle and ac is its chord such that angle bac is 30 degree, if the tangent at c intersect ab extended at d , then prove that bc= bd

Posted by Vikas Kashyav 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given: A circle with centre O. A tangent CD at C.

Diameter AB is produced to D.

BC and AC chords are joined, ∠BAC = 30°

To prove: BC = BD
Proof: DC is tangent at C and, CB is chord at C.
Therefore, ∠DCB = ∠BAC [∠s in alternate segment of a circle]
⇒ ∠DCB = 30° …(i) [∵ ∠BAC = 30° (Given)]
AOB is diameter. [Given]
Therefore, ∠BCA = 90° [Angle in s semi circle]
Therefore, ∠ABC = 180° - 90° - 30° = 60°
In ΔBDC,
Exterior ∠B = ∠D + ∠BCD
⇒ 60° = ∠D + 30°
⇒ ∠D = 30° …(ii)
Therefore, ∠DCB = ∠D = 30° [From (i), (ii)]
⇒ BD = BC [∵ Sides opposite to equal angles are equal in a triangle]
Hence, proved.

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WRite whether 2√45+3√20÷2√5 on simplification gives an irrational or a rational number

Posted by Manav Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Anshika Patel 6 years, 10 months ago

Rational (i.e. 6)

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ANSWER

Find the value of y for which the distance between the points p (2, - 3 )and q(10,y)is 10 units

Posted by Sanju Ramesh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 10 months ago

Given that distance between the points P (2, -3) and Q (10, y) is 10

Therefore using distance formula
√(2 -10)² + (-3-y)² = 10
√ (-8)² + ( 3 + y)² = 10
squaring on both side
64 + (y +3)² = 100
(y + 3)²= 36
y + 3 = ± 6
y+3=6
or y+3= -6
Therefore, y=3 or y= -9

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5-9

Posted by Sunny Jha 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Gautam Prajapati 6 years, 10 months ago

Why are u asking such type of question.........

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Elina ❤️ 6 years, 10 months ago

- 4 answer ..... So easy ....

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Prove that Sec^2 Θ + Cot^2 (90-Θ)= 2Cosec^2(90-Θ) -1

Posted by Ankul Prajapati 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shashank Mishra 6 years, 10 months ago

Sec square theta = cosec(90-theta) Tan square theta = sec square theta -1 Cot square(90-theta)=tan square theta In Sab ko equation me put Karna prove go jayega

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find the value of a for which point p(a/3 2)is the mid-point of the line segment joining the points q(-5,4) and r(-1,0)

Posted by Gurjant Singh 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

P is midpoint of QR
or, {tex}\frac { a } { 3 } = \frac { - 5 + ( - 1 ) } { 2 }{/tex}
or, {tex}\frac { a } { 3 } = \frac { - 6 } { 2 }{/tex}
or, a = -9

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If -5 is a root of quadratic equation 2x^2+px+5=0 and quadratic equation p(x^2+x)+k=0 has equal roots then find the value of k??

Posted by Jiya Jiya 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given that -5 is the root of {tex}2 x^{2}+p x-15=0{/tex}
Put x = -5 in {tex}2 x^{2}+p x-15=0{/tex}
{tex}\Rightarrow{/tex} {tex}2(-5)^{2}+p(-5)-15=0{/tex}
{tex}\Rightarrow{/tex} {tex}50-5 p-15=0{/tex}
{tex}\Rightarrow{/tex} {tex}35 - 5p = 0 {/tex}
{tex}\Rightarrow{/tex} {tex}5p = 35 {/tex}
{tex}\therefore{/tex} {tex}p = 7{/tex}
Hence the quadratic equation p {tex}(x^2 + x) + k = 0{/tex} becomes, {tex}7\left(x^{2}+x\right)+k=0{/tex}
{tex}7 x^{2}+7 x+k=0{/tex}
Here {tex}a = 7,\ b = 7\ and\ c = k{/tex} Given that this quadratic equation has equal roots
{tex}\therefore{/tex} {tex}b^{2}-4 a c=0{/tex}
{tex}\Rightarrow{/tex} {tex}7^{2}-4(7)(\mathrm{k})=0{/tex}
{tex}\Rightarrow{/tex} {tex}49 - 28k = 0 {/tex}
{tex}\Rightarrow{/tex} {tex}49 = 28k {/tex}
{tex}\therefore{/tex} k = {tex}\frac{49} {28}{/tex} = {tex}\frac{7} {4}{/tex}

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In triangle abc, the mid points of sides bc,ca,ab are d,e,f respectively. D,e,f are joined to form four triangles. prove that all four triangles are similar to triangle abc

Posted by Pranvi Monga 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Lavanya Jain 6 years, 10 months ago

Proof it by mid point theoram

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Find the value of x in given figure

Posted by Anish Gupta 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Affu 😊 6 years, 10 months ago

Figure??????

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Puja Sahoo ? 6 years, 10 months ago

Where is the fig....???

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A motor boat whose speed is 24km/h in still water takes 1 hour more to go 32 km upsream than to return downstream to the same spot.find the speed of the stream

Posted by Samrat Kkkkk 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 10 months ago

Let the speed of the stream be s km/h.
Speed of the motor boat 24 km / h
Speed of the motor -boat upstream 24 s
Speed of the motor boat downstream 24 s
According to the given condition,

Since, speed of the stream cannot be negative, the speed of the stream is 8 km/h.