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Ram Kushwah 6 years, 10 months ago
Let the {tex}\angle{/tex} B=x then {tex}\angle{/tex}C=3x
3x=2({tex}\angle{/tex}A+x)
3x=2{tex}\angle{/tex}A+2x
x=2 {tex}\angle{/tex}A , {tex}\angle{/tex}A=x/2
{tex}\angle{/tex}A+{tex}\angle{/tex}B+{tex}\angle{/tex}C=180
x/2+x+3x=180
9x/2=180,x=40
so {tex}\angle{/tex}A=20,{tex}\angle{/tex}B=40 ,{tex}\angle{/tex}C=120
1Thank You