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  • 1 answers

Sia ? 6 years, 4 months ago

Given linear equation is
(3k + 1)x + 3 y - 2 = 0 .......... (i)
(k2 + 1)x + (k - 2)y - 5 = 0 ............ (ii)
Compare with a1x + b1y + c = 0 and a2x + b2y and c2 = 0
a1 = 3k + 1 , b1 = 3 , c1 = -2
and a2 = k2+ 1 , b2 = k - 2, c2 = -5
The given system of equations will have no solution, if
{tex} \frac { a_1 } { a_2 } = \frac { b_1 } { b_2} \neq \frac { c_1 } { c_2 }{/tex}
{tex} \frac { 3 k + 1 } { k ^ { 2 } + 1 } = \frac { 3 } { k - 2 } \neq \frac { - 2 } { - 5 }{/tex}
{tex}\Rightarrow \quad \frac { 3 k + 1 } { k ^ { 2 } + 1 } = \frac { 3 } { k - 2 } \text { and } \frac { 3 } { k - 2 } \neq \frac { 2 } { 5 }{/tex}
Now, {tex}\frac { 3 k + 1 } { k ^ { 2 } + 1 } = \frac { 3 } { k - 2 }{/tex}
{tex}\Rightarrow{/tex} (3k + 1)(k - 2)=3(k2 + 1)
{tex}\Rightarrow{/tex} 3k2 - 5k - 2 =3k2 + 3
{tex}\Rightarrow{/tex} -5k - 2 =3
{tex}\Rightarrow{/tex} -5k = 5
{tex}\Rightarrow{/tex} k = -1
Clearly, {tex}\frac { 3 } { k - 2 } \neq \frac { 2 } { 5 }{/tex} for k = -1.
Hence, the given system of equations will have no solution for k = -1.

  • 1 answers

Sithara Parwin 6 years, 10 months ago

Thief has a lead of 50*2 = 100m Relative distance covered by cop in 1st min = 60-50 = 10 Relative distance covered by cop in 2nd min = 65-50 = 15 Relative distance covered by cop in 3rd min = 70 -50 = 20 10, 15, 20 ... is an AP whose sum is 100 a= 10 , d = 5 Sum = 100 100 = n/2(2a + (n-1)d) = n/2(20 +(n-1)5 ) 100= n/2(20 + 5n -5) 200 = n(15 + 5n) divide by 5 40 = n(n + 3) n^2 + 8n - 5n - 40 =0 n(n+8) - 5(n+8)= 0 >> n = 5 as it cant be negative Therefore cop catches after 5 min + 2min (when cop was at rest) = 7min
  • 1 answers

Md Sohel 6 years, 10 months ago

Apply distance formula and take x=0
  • 3 answers

Nitin Dadhich 6 years, 10 months ago

Soneb prefer sample paper of 2019

Md Sohel 6 years, 10 months ago

Miss your answer is wrong

Puja Sahoo? 6 years, 10 months ago

(p²+1)/(p²-1)
  • 1 answers

Nitin Dadhich 6 years, 10 months ago

1 is answet ... If more problem then click thanks on my answer
  • 0 answers
  • 1 answers

Lucky? Dangi 6 years, 10 months ago

tan = 5- cot cot=5-tan ab khud karle value put kerke
  • 1 answers

Nitin Dadhich 6 years, 10 months ago

Which subject
  • 2 answers

Arnav Kachariya 6 years, 10 months ago

Arihant

Sahil Rajput 6 years, 10 months ago

Ncert solution me diya hai .. 3.4
  • 2 answers

Nitin Dadhich 6 years, 10 months ago

n2+2n

Vishnu Vardhan 6 years, 10 months ago

N square
  • 2 answers

Anushka ?? 6 years, 10 months ago

X²-1
Root x^2-1
  • 0 answers
  • 1 answers

Puja Sahoo? 6 years, 10 months ago

Book me hai
  • 3 answers

Sonu Kumari 6 years, 10 months ago

Make a quad and mark pts abcd then take triangle abc and put formula of area of triangle ok and then solve it or u can also prefer ncert in chapter seven exercise 7.3 questions 4 ok

Ramesh Singh 6 years, 10 months ago

Diagonal banakar quadrilateral ko do triangle banao then coordinate geometry ka area ka formula lagao
72 sq. units
  • 1 answers

Ramesh Singh 6 years, 10 months ago

See ncert ex no.9 page 13
  • 1 answers

Puja Sahoo? 6 years, 10 months ago

Question to puta likho.....???
  • 0 answers
  • 2 answers

Aanchal Yadav 6 years, 10 months ago

No any relation is not given

Ramesh Singh 6 years, 10 months ago

Check que kuch given v hoga any relation

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