CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

The angle of elevation is 45. Explanation:- Let height = base(shadow) = x Tan thita = P÷B TAN THITA = x ÷ x Tan thita = 1 Tan thita = tan 45 (TAN 45 = 1) SO, thita = 45.

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Aman Choudhary 6 years, 10 months ago

45°

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Shivam K 6 years, 10 months ago

Angle of Elevation is 45°

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A pair of fair dice is thrown once . Find the probability of getting a total of 9or more please answer fast

Posted by Khdg Gel 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Khdg Gel 6 years, 10 months ago

Pls answer fast within today

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Khdg Gel 6 years, 10 months ago

How ??

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Rohan Gupta 6 years, 10 months ago

5/18

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Khdg Gel 6 years, 10 months ago

Please answer fast

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The length of the shadow of a man is equal to the height of man

Posted by Nikhil Bhilare 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Affu 😊 6 years, 10 months ago

Angle of elevation is tan45°

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Noor Mehta 6 years, 10 months ago

Angle of elevation is 45.

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solve x^2_45x+324=0

Posted by Anmol Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 10 months ago

x2 - 45x + 324 = 0
x2 - 36x - 9x + 324 = 0
x ( x - 36) - 9 ( x - 36) = 0
(x - 36) (x -9) = 0
x - 36 = 0 and x - 9 = 0
x = 36 and x = 9

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【-】⭕ 【\】 € ¥ (＠_＠;) 6 years, 10 months ago

36,9

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The eighth term of an ap is half of its second term and the eleventh term exceed one third of its fourth term by 1 . Find 15 th term

Posted by Laxmi Devi 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let a be the first term and d be the common difference of the given A.P.
Then, 8^th term = a₈ = a + 7d
and 2^nd term = a₂ = a + d
According to given information,
{tex}a _ { 8 } = \frac { a _ { 2 } } { 2 }{/tex}
{tex}\Rightarrow{/tex} 2a₈ = a₂
{tex}\Rightarrow{/tex} 2(a + 7d) = a + d
{tex}\Rightarrow{/tex} a + 13d = 0...(i)
Now, 11^th term = a₁₁ = a + 10d and 4^th term = a₄ = a + 3d
According to the given information,
{tex}a _ { 11 } - \frac { a _ { 4 } } { 3 } = 1{/tex}
{tex}\Rightarrow{/tex} 3a₁₁ - a₄ = 3
{tex}\Rightarrow{/tex} 3(a + 10d) - (a + 3d) = 3
{tex}\Rightarrow{/tex} 3a + 30d - a - 3d = 3
{tex}\Rightarrow{/tex} 2a + 27d = 3...(ii)
Multiplying equation (i) by 2, we get
2a + 26d = 0...(iii)
Subtracting (iii) from (ii), we get
d = 3
{tex}\Rightarrow{/tex} a + 13(3) = 0
{tex}\Rightarrow{/tex} a = -39
Now, 15^th term = a₁₅ = a + 14d = -39 + 14(3) = -39 + 42 = 3

Hence, 15^th term is 3 .

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ANSWER

If m times the m th term of an AP is equal to n time it's n th term then show that (m+n) th term of an AP is zero

Posted by Mansi Saraf 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

ma_m = na_n
m[a + (m - 1)d] = n [a + (n - 1)d]
{tex} \Rightarrow {/tex} ma + m²d - md = na + n²d - nd
{tex} \Rightarrow {/tex} a(m - n) + (m² - n²)d - md + nd = 0
{tex} \Rightarrow {/tex} a(m - n) + (m - n) (m + n)d - (m - n)d = 0
{tex} \Rightarrow {/tex} (m - n) [a + (m + n - 1)d] = 0
{tex} \Rightarrow {/tex} a + (m + n - 1)d = 0
{tex} \Rightarrow {/tex} a_m+n = 0
Hence proved.

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ANSWER

Write a quadratic polynomial where sum of zeroes and product of zeroes are respectively -4 and 6

Posted by Golu Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If the roots of the equation (a-b)x²+(b-c)x+(c-a)=0 are equal,show the c,a and b are in AP

Posted by Vitthal Gajjal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Can a no. Can have 308 and 18 as its lcm nd hcf

Posted by Shifq Rahman 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Shifq Rahman 6 years, 10 months ago

Thanks✌

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Jaideep Yadav 6 years, 10 months ago

No because 308 is not divisible by 18

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Find HCF of 726and 275

Posted by Dipanshu Choudhary 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Puja Sahoo? 6 years, 10 months ago

3Thank You

ANSWER

How to find 0s for a pol all 0s

Posted by Monish Waran 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Puja Sahoo? 6 years, 10 months ago

Sry, yur question is nt clear ?

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ANSWER

A cone of maximum size is carved out from a cube of edge 14cm. Find the surface area of the remaining solid after the cone is carved out.

Posted by Khdg Gel 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Lucky? Dangi 6 years, 10 months ago

remaining surface area = tsa of cube + csa of cone- base area of cone

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Khdg Gel 6 years, 10 months ago

Thanks

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Puja Sahoo? 6 years, 10 months ago

Surface ar of solid = ar. of cube + curved surface area of cone - base of cone........ solve it yu will get the answer 1022+154 root 5.....

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Khdg Gel 6 years, 10 months ago

Pls answer fast within today pls

2Thank You

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Do the equation x+3y-1=3 and 2x+6y=6 represent a pair of coincident lines? Justify your answer

Posted by Yash Sharma ?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Lucky? Dangi 6 years, 10 months ago

inconsistent

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PQRS is a square lawn with side PQ=42m.Two circular flower beds are there on the sides PS and QR with centre at O,the intersections of its diagonals.Find the total area of the two flower beds(shaded parts) Please solve this question

Posted by Aryan Patel 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Lucky? Dangi 6 years, 10 months ago

area of shaded region = area of square - 2(area of flower bed ) 42×42- 2(22/7×21×21/2) =1764- 1386 =378m square

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Sir board me kitna year old paper aata hai

Posted by Sanjeet Yadav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Shyam Jaat ? (?हर हर महादेव ?) 6 years, 10 months ago

Bhai ncert hi kr le usme se aayega .

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ANSWER

9x2-9p(p+a)x+(2p2+5pq+2q2) solve equation x

Posted by Ayush Jaiswal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Lucky? Dangi 6 years, 10 months ago

iss se karle bhai bahut jaada bada ha

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Lucky? Dangi 6 years, 10 months ago

d= b2 -4ac

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Ayush Jaiswal 6 years, 10 months ago

2p+q/3 and p+2q/3

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Show that the reciprocal of irrational number is irrational .. ..

Posted by Aastha . 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

?#Hr_76# ? 6 years, 10 months ago

If any irrational no. Will be there instead of pi then...

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Yogita Ingle 6 years, 10 months ago

We know that the irrational numbers are always terminating or non repeating . So take the example of pi= 22÷7 = 3.1285714 and it's reciprocal 7÷22 = 0.31818818 which are also irrational..

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Draw a flair of tangents to a circle of radius 2cm that are inclined to each other at an angle of 90°

Posted by Sneha Ann 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the 25th term of A.P when the given A.P is 11,16,21......

Posted by Aastha . 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Yash Sharma ?? 6 years, 10 months ago

131

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Jasline Sandhu????? 6 years, 10 months ago

Hello. Honey hamare comments gayab ho gaye yaar..

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Lucky? Dangi 6 years, 10 months ago

a= 11 d= 5 a25= a+ 24d 11 + 24×5 a25 = 11+120 a25= 131

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【-】⭕ 【\】 € ¥ (＠_＠;) 6 years, 10 months ago

131

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What is the zero of the polynomial?

Posted by Vidit Khandelwal 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

【-】⭕ 【\】 € ¥ (＠_＠;) 6 years, 10 months ago

Zero of a poly. is defined as the trm when inserted in the poly. =0 and it satisfies it

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What is the weightage of maths of 2019

Posted by Harsh Jain 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Sahil Rajput 6 years, 10 months ago

80 marks?

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solve the equation 2(2×-1/×+3) -3(×+3/2×-1)=5

Posted by Diksha Sihag 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Lucky? Dangi 6 years, 10 months ago

kya mahnaat ki yrr likhne me?????

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Nandini Kakkar 6 years, 10 months ago

2(2x-1/x+3)-3(x+3/2x-1)=5 or, {2(2x-1)²-3(x+3)²}/(x+3)(2x-1)=5 or, {2(4x²-4x+1)-3(x²+6x+9)}/(2x²+6x-x-3)=5 or, 8x²-8x+2-3x²-18x-27=5(2x²+5x-3) or, 5x²-26x-25=10x²+25x-15 or, 5x²-10x²-26x-25x-25+15=0 or, -5x²-51x-10=0 or, 5x²+50x+x+10=0 or, 5x(x+10)+1(x+10)=0 or, (x+10)(5x+1)=0 Either, x+10=0 or, x=-10 Or, 5x+1=0 or, 5x=-1 or, x=-1/5 Therefore, x=10,-1/5 Ans.

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find the area of the quadrilateral abcd whose vertices are a(3 -1) b(9 -5) c(14 0) and d(9 19)

Posted by Gursagar Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Join A and C
Now, Area of quadrilateral ABCD = Area of {tex} \Delta{/tex}ABC + Area of {tex}\Delta{/tex}ACD
Area of {tex} \Delta A B C = \frac { 1 } { 2 } | 3 ( - 5 - 0 ) + 9 ( 0 + 1 ) + 14 ( - 1 + 5 ) |{/tex}
{tex}= \frac { 1 } { 2 } | - 15 + 9 + 56 |{/tex}
{tex}= \frac { 1 } { 2 } \times 50{/tex}
= 25 sq. units
Area of {tex}\Delta ACD = \frac{1}{2}|3(0 - 19) + 14(19 + 1) + 9( - 1 - 0)|{/tex}
{tex}= \frac { 1 } { 2 } | - 57 + 280 - 9 |{/tex}
{tex}= \frac { 1 } { 2 } \times 214{/tex}
= 107 sq. units
Area of quad. ABCD = Area of {tex}\Delta{/tex}ABC + Area of {tex}\Delta{/tex}ACD
= (25 + 107) sq. units
=132 sq. units