CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let √3 is rational no. So it can be written in form of p/q . So, √3=p/q where p and q are co-prime . Square on both sides . 3=p^2/q^2 . p^2= 3q^2 . So 3is factor of p^2 ,thus it will also be the factor of p. Let p=3r . P^2= 3q^2 . (3r)^2 = 3q^2 . 9r^2 = 3q^2 . 3r^2 = q^2 . So 3is also factor of q^2 then it also be the factor of q but earlier we assumed that p and q are co-prime they do not have commen factor except 1 . So this contradiction just arisen bcz of our wrong assumption . So √3 is irrational .

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Piyush Kamboj?? 6 years, 10 months ago

Bhai bahut bada hai ye sidha board mai krunga

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Garima Choudhary 6 years, 10 months ago

Chal m batati hoon

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Garima Choudhary 6 years, 10 months ago

Yrr google pe srech maar na

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Find the area of the triangle formed by joining the mid point of the sides of the triangle whose vertices are (0,-1),(2,1) and(0,3).find the ratio of this area to area of the given triangle.

Posted by Rajhans 6432 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Esha Pal 6 years, 10 months ago

This question is from ncert exercise 7.3 q no 3

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Shrijith The Artist ??? 6 years, 10 months ago

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Find the quadratic polynomial who's Alpha equal to under root 2 and beta 1/ 3

Posted by Dev Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Garima Choudhary 6 years, 10 months ago

Firstly find alpha+beta than (alpha)(beta ) put the values in formula (x^2 — (sum of zeros ) + (product of zeros ) , (x^2 — (alpha +beta ) + (alpha )(beta )

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Do we mean adding up the series if we are asked to combine two series ?

Posted by Preeti Rahi 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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A man goes to 12m due south and then 35m due west. Jow far is he from the starting point?

Posted by Shweta Patel 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Nitin Dadhich 6 years, 10 months ago

Use Pythagoras

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Sonu Kumar 6 years, 10 months ago

37m

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The point p is equidistant from the vertices of the triangle and the angles of the triangle is 80,60,40.find the measures of the sides of the triangle?

Posted by Surya N 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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Place A and B are 100km apart on a highway . One car starts from A and from B at the same time . If the cars travels in the same direction at different speed , they in 5hrs . If they travels toward each other they meet in 1 hrs . What are the speeds of their?

Posted by Kiran Yadav 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Santosh Bhajantri 6 years, 10 months ago

10x_10y=100 x_y=10

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In triangle opq, right angke at p,op=7cm and oq-pq=1 cm determine the value of sin q and cos q

Posted by Divanshu Sharma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Eeya Modi 6 years, 10 months ago

SinQ=7/25 and cosQ=24/25

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The mth term of an ap is n and the nth term is m.find the nth term

Posted by Akhilesh Paswan 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Abha Dubey 6 years, 10 months ago

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Akanksha Dutta 6 years, 10 months ago

it will be mnth term

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Eeya Modi 6 years, 10 months ago

Bo mnth term hoga

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Eeya Modi 6 years, 10 months ago

nth term given to h

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x /a cosA + y/b sinA = 1 x/a sinA - y/ b cosA = -1 Prove that :- x^2/a^ + y^2/b^2 =2

Posted by Paulo Dybala 6 years, 10 months ago

CBSE > Class 10 > Mathematics

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From a point on a bridge across a river, the angles of depression of the banks on opposite sides of the river are 30° and 45°, respectively. If the bridge is at a height of 3 m from the banks, find the width of the river

Posted by Tanpreet Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Akanksha Dutta 6 years, 10 months ago

3 +root3

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A 5m wide cloth is used to make a comical tent of base diameter 14m and height 24 m. Find the cost of cloth used at rate of 25rupees per meter

Posted by Arannya Sen 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Puja Sahoo? 6 years, 10 months ago

Rs. 2750

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Maths chapter 2 questions no 3 ka solution . Page no 36 ncert class 10 . Take divisor 3x2 - 5

Posted by Gaurav Chilkoti 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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theorems of chapter circles

Posted by Parjap2021 Bhullar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Akanksha Dutta 6 years, 10 months ago

tangents make 90 degree with the diameter

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Akanksha Dutta 6 years, 10 months ago

tangents drawn from external point are equal

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If triangle def is similar to triangle abc, area of triangle def=4/9(area of abc) then find bc /ef

Posted by Manav Tilokani 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhavya Vardhan Jain 6 years, 10 months ago

Area ofΔabc/area of Δdef=9/4=(bc)²/(ef)² √9/√4=bc/ef 3/2=bc/ef. Ans

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Find a quadratic polynomial whose zeroes are 5+√2 and 5- √2

Posted by Yash Sharma ?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Anushka ? 6 years, 10 months ago

X square - 10x+23

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Ch 3 ex 3.5 Q 2 1 explain krdoo Koi ncert ka

Posted by Khan Fardin 6 years, 10 months ago

CBSE > Class 10 > Mathematics

0 answers

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Show that 12n cannot end with the digit0 for any natural number n

Posted by Yash Sharma ?? 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Bhavya Vardhan Jain 6 years, 10 months ago

For any digit ending with zero must have both 5 and 2 as factor but 12 have only 2 as factor not 5 so it cannot end with 0 for any natural no n

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Which term of the AP: 21,18,15,----------- is -81 also,is any term 0 koi solution bata do plz

Posted by Aryan Walia 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Tanushree Maity 6 years, 10 months ago

An= -81 -81=21+(n-1)-3 n=35

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Tushar Bhatnagar 6 years, 10 months ago

-81 ko last term lekr solve kr

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PT and PS are 2 tangents are drawn to a circle and radius r OP=2r show angle ots=ost=30

Posted by Fab S 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given,

In {tex}\triangle{/tex}OTS,
{tex}OT =OS {/tex}
{tex}\Rightarrow \quad \angle O T S = \angle O S T{/tex} ...(i)
In right {tex}\triangle OTP,{/tex}
{tex}\frac { \mathrm { OT } } { \mathrm { OP } } = \sin \angle \mathrm { TPO }{/tex}
{tex}\Rightarrow \frac { r } { 2 r } = \sin \angle \mathrm { TPO }{/tex}
{tex}\sin \angle \mathrm { TPO } = \frac { 1 } { 2 } \Rightarrow \angle \mathrm { TPO } = 30 ^ { \circ }{/tex}
Similarly {tex}\angle \mathrm { OPS } = 30 ^ { \circ }{/tex}
{tex}\Rightarrow \angle T P S = 30 ^ { \circ } + 30 ^ { \circ } = 60 ^ { \circ }{/tex}
Also {tex}\angle \mathrm { TPS } + \angle \mathrm { SOT } = 180 ^ { \circ }{/tex}
{tex}\Rightarrow \quad \angle \mathrm { SOT } = 120 ^ { \circ }{/tex}
In {tex}\triangle{/tex}SOT,
{tex}\angle \mathrm { SOT } + \angle \mathrm { OTS } + \angle \mathrm { OST } = 180 ^ { \circ }{/tex}
{tex}\Rightarrow 120 ^ { \circ } + 2 \angle \mathrm { OTS } = 180 ^ { \circ }{/tex}
{tex}\Rightarrow \angle \mathrm { OTS } = 30 ^ { \circ }{/tex} ...(ii)
From (i) and (ii)
{tex}\angle \mathrm { OTS } = \angle \mathrm { OST } = 30 ^ { \circ }{/tex}

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