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Aanchal Sharma 6 years, 9 months ago
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Aanchal Sharma 6 years, 9 months ago
Posted by Sneha Singh?????? 6 years, 9 months ago
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Data Ram Shankar Lal 6 years, 9 months ago
Jyoti Laddha 6 years, 9 months ago
Posted by Sneha Singh?????? 6 years, 9 months ago
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Ram Kushwah 6 years, 9 months ago
Let a is the side of cube
Then TSA =CSA+ {tex}2\pi r^2{/tex}
231=2/3*231+{tex}2\pi r^2{/tex}
{tex}2\pi r^2{/tex} = 231-154=77
r2=1/2*77*22/7=11*11, r=11 cm
Now CSA={tex}2\pi rh{/tex}=2/3*231=154
{tex}\begin{array}{l}h=\frac{154}{2\pi r}=\frac{77}{\pi r}\\so\;V=\pi r^2h=\pi r^2\times\frac{77}{\pi r}=77\times11\\=847\;m^3\end{array}{/tex}
Posted by Sham Shinde 6 years, 9 months ago
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Posted by Sneha Singh?????? 6 years, 9 months ago
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Ram Kushwah 6 years, 9 months ago
Let base =x
then hypo=x+1
Let altitude =h
also hypo=2h+3
h=(hypo-3)/2------(1)
=(x+1-3)/2=(x-2)/2
Now Hypo2=h2+x2
(x+1)2=1/4*(x-2)2 +x2
{tex}\begin{array}{l}4(x+1)^2=(x-2)^2+4x^2\\4x^2+8x+4=x^2-4x+4+4x^2\\x^2-12x=0\\x(x-12)=0\\x=0\;or\;12\\\end{array}{/tex}
The side can not be zero
so x= base =12 cm
Hypo=12+1=13 cm
From(1)
h=(13-3)/2= 5 cm
Posted by Amant Singh 6 years, 9 months ago
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Posted by Vivek Srivastava 6 years, 9 months ago
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Ram Kushwah 6 years, 9 months ago
Length of carpet area=22-(0.75*2=22-1.5=20.5 m
Width=15.5-2.0.75=15.5-1.5=14 m
so area A =20.5 x 14 = 287 m2
Now width of the carpet = 82 cm =0.82 m
Hence length of carpet used in 287 m2 area
{tex}\begin{array}{l}=\frac{area}{width}=\frac{287}{0.82}=350m\\\end{array}{/tex}
So cost of carpet= 350 x 60=Rs 21000
Posted by Aakansha Panchal 6 years, 9 months ago
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Khushi ? 6 years, 9 months ago
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