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Ram Kushwah 6 years, 9 months ago
{tex}\angle A{/tex} =90 and ABC is an isosceles triangle then
AB=AC
and BC2=AC2+AB2
BC2=AB2+AB2
BC2=2AB2
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Gaurav Seth 6 years, 9 months ago

- Draw a line segment AB of length 5cm.
- Taking B as point Construct an angle of measure 60o using a compass.
- Name the angle as angle ABX.
- Draw a line EF at a height of 3 cm such that it is parallel to the line segment AB. It must intersect ray BX at point C. Now join AC.
- Draw CD perpendicular to AB. CD is altitude of triangle ABC having height 3cm.
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Ram Kushwah 6 years, 9 months ago
See at following l ink I don,t have RD sharma book:
https://www.topperlearning.com/study/cbse/class-10/mathematics/text-book-solutions/r-d-sharma-mathematics-x/42/trigonometric-identities/277/b101c2s3e9

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