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Ask QuestionPosted by Guri Mundi 1 year, 10 months ago
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Posted by Somdutta Dutta 1 year, 10 months ago
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Preeti Dabral 1 year, 10 months ago
Given, {tex}3x -{/tex} {tex}\frac{y+7}{11}{/tex} {tex}+ 2 = 10{/tex}
{tex}\Rightarrow \frac{33 x-(y+7)+22}{11}=10{/tex}
{tex}\Rightarrow{/tex} {tex}33x - y - 7 + 22 = 110{/tex}
{tex}\Rightarrow{/tex} {tex}33x - y = 95{/tex} ..(i)
Also, {tex}2 y+\frac{x+11}{7}{/tex} = 10
{tex}\Rightarrow \quad \frac{14 y+x+11}{7}{/tex} = 10
{tex}\Rightarrow{/tex} {tex}14y + x + 11 = 70{/tex}
{tex}14y + x = 59{/tex}
{tex}14y = 59 - x{/tex}
{tex}\Rightarrow{/tex} y = {tex}\frac{59-x}{14}{/tex}
eq. (i) becomes
33x - {tex}\left(\frac{59-x}{14}\right){/tex} = 95
{tex}\Rightarrow \quad \frac{462 x-59+x}{14}{/tex} = 95
{tex}\Rightarrow{/tex} 463x - 59 = 1330
{tex}\Rightarrow{/tex} x = 3
When x = 3 eq. (i) becomes
33(3) - y = 95
{tex}\Rightarrow{/tex} y =4
Posted by Aaryan Gandhi 1 year, 10 months ago
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Princy Puri 1 year, 10 months ago
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Posted by Kumar ... 1 year, 10 months ago
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Preeti Dabral 1 year, 10 months ago
sec A {tex}= \frac { 15 } { 7 }{/tex}
{tex}\Rightarrow{/tex} sec(90° - B) {tex}= \frac { 15 } { 7 }{/tex} [{tex}\because{/tex} A + B = 90° {tex}\Rightarrow{/tex} A = 90° - B]
{tex}\Rightarrow{/tex} cosec B {tex}= \frac { 15 } { 7 }{/tex} [{tex}\because{/tex} sec (90° - {tex}\theta{/tex}) = cosec {tex}\theta{/tex})
Posted by Shrey Jaiswal 1 year, 10 months ago
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Preeti Dabral 1 year, 10 months ago
A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point (known as the focus) and from a fixed straight line which is known as the directrix. Parabola is an integral part of conic section topic and all its concepts parabola are covered here.
Posted by Sankaran Karan 1 year, 10 months ago
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Nancy Rana 1 year, 10 months ago
Posted by Sarika Maurya 1 year, 10 months ago
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Preeti Dabral 1 year, 10 months ago
Given series is
{tex} 1+6+11+16+\ldots . .+x=148 Here, a=1, d=6-1=11-6=16-11=5 and \mathrm{S}_{\mathrm{n}}=148 \begin{aligned} & \because \mathrm{S}_{\mathrm{n}}=\frac{\mathrm{n}}{2}[2 \mathrm{a}+(\mathrm{n}-1) \mathrm{d}] \\ & \therefore 148=\frac{\mathrm{n}}{2}[2 \times 1+(\mathrm{n}-1) 5] \\ & \Rightarrow 296=2 \mathrm{n}+5 \mathrm{n}^2-5 \mathrm{n} \\ & \Rightarrow 296=5 \mathrm{n}^2-3 \mathrm{n} \\ & \Rightarrow 5 \mathrm{n}^2-3 \mathrm{n}-296=0 \\ & \Rightarrow(\mathrm{n}-8)(5 \mathrm{n}+37)=0 \\ & \Rightarrow \mathrm{n}=8, \mathrm{n}=\frac{-37}{5} \end{aligned} {/tex}
{tex}\begin{aligned} & \therefore \mathrm{n}=8 \\ & (\because \mathrm{n} \text { cannot be negative }) \\ & \text { Now, } \mathrm{T}_{\mathrm{n}}=\mathrm{a}+(\mathrm{n}-1) \mathrm{d} \\ & \mathrm{x}=1+(8-1) \times 5 \\ & \Rightarrow \mathrm{x}=1+35 \Rightarrow \mathrm{x}=36 . \end{aligned}{/tex}
Posted by Sarika Maurya 1 year, 10 months ago
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Preeti Dabral 1 year, 10 months ago
The dimensions of the cuboid so formed are as under:
l= length=15cm,b= breadth=5cm, h= height =5cm
Surface area of the cuboid =2(15×5+5×5+15×5)cm2
=2(75+25+75)cm2=350cm2
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