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The fourth term of an ap is zero prove that 25th term of the ap is 3 times its 11th term

Posted by The Anonymous Anonymous 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 2 years, 2 months ago

Given, a₄ = 0
a + (n - 1)d = 0 [n = 4]
a + 3d = 0
a = -3d
From LHS, a₂₅ = a + (n - 1)d
= a + (25 - 1)d
= a + 24d [∵∵ a = -3d]
= -3d + 24d = 21d
From RHS, a₁₁ = a + (n - 1)d
= a + (11 - 1)d = a + 10d [∵∵ a = -3d]
= -3d + 10d
= 7d
∴∴ Hence, a₂₅ = 3 ×× a₁₁

ANSWER

If Q(0,1)is equidistant from p(5,-3)R(x,6) find the value ofx.also find the distance QR and pR

Posted by Rohit Thakur 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Suhani Verma 2 years, 2 months ago

Qp= √( X-x )² + (Y-y)² = √(5-0)² + (-3-1)² = √ (5)² + (-4)² = √ 25+16 = √ 41 QR= √ (X-x)² + (Y-y)² = √ (x-0)² + (6-1)² = √ (x)² + (5)² = √ x² + 25 Qp =QR √41 = √x² +25 Both side squaring (√41)² = (√x²+25) 41 = x² + 25 41- 25=x² 16 = x² 4 = x Distance between, QR=√( 4-0)² + (6-1)² = √(4)² + (5)² =√16+25 =√41 PR=√(5-4)² + (-3-6)² =√(1)² + (-9)² =√ 1+81 =√82

ANSWER

Obtain zero of linear polynomial by geometrically and graphically

Posted by Mr. Priest 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is the empirecal formula of mean meadean mode

Posted by Saksham Dogra 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Tilak Raj 2 years, 2 months ago

3median = mode +2mean

Guri Mundi 2 years, 2 months ago

2median= mode -2mean

Naman Saxena 2 years, 2 months ago

Mode = 3median - 2mean

ANSWER

Prove that Tan∅/1-cot∅+cot∅ 1-tan∅=1+sec∅cosec∅

Posted by Likith Parikh 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Saksham Dogra 2 years, 2 months ago

1−cotθ tanθ + 1−tanθ cotθ = 1− tanθ 1 tanθ + 1−tanθ tanθ 1 = tanθ tanθ−1 tanθ + tanθ(1−tanθ) 1 = tanθ−1 tan 2 θ + tanθ(1−tanθ) 1 = tanθ−1 tan 2 θ − tanθ(tanθ−1) 1 = tanθ(tanθ−1) tan 3 θ−1 = tanθ(tanθ−1) (tanθ−1)(tan 2 θ+tanθ+1) = tanθ tan 2 θ+tanθ+1 = tanθ tan 2 θ + tanθ tanθ + tanθ 1 =tanθ+1+cotθ =1+ cosθ sinθ + sinθ cosθ =1+ sinθcosθ sin 2 θ+cos 2 θ =1+ sinθcosθ 1 =1+secθcosecθ = RHS

ANSWER

Stastics formula

Posted by Azeem Khan 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Gayatri Pathade 2 years, 2 months ago

Median=l+[n/2-cf] h ----------- F

ANSWER

Month having exactly 31 days

Posted by Harsh Rai 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Piyush Maheshwari 2 years, 2 months ago

There are 7 months that have 31 days January, March, May, July, August, October, December

Vivek Prajapati 2 years, 2 months ago

Nahi 32

Aditya Raj 2 years, 2 months ago

H

Anshika Sharma 2 years, 2 months ago

July, August January, March, May, July, August, October, December months have 31 days each. So, here July and august are the consecutive months having 31 days each.

ANSWER

Sohan painted the outside of a box on all sides except the bottom.If the cabinet measures 1m×2m×1.5m,how much surface did he paint ?

Posted by Aman Khan 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Mangifera Indica 2 years, 2 months ago

7msq

Mangifera Indica 2 years, 2 months ago

9msq

Anshika Sharma 2 years, 2 months ago

Total surface area of the cabinet = 2(l × b + b × h + h × l) Area of the cabinet that was painted = (Total surface area of the cabinet) - (Area of bottom of the cabinet) = 2(l × b + b × h + h × l) − l × b = 2(b × h + h × l) + l × b = 2 × (1 × 1.5 + 1.5 × 2) + 2 × 1 m² = 2 × 4.5 + 2 m² = 11 m²

ANSWER

Given that sin theta equal a upon b then cosec theta is equals to

Posted by Aridaman Singh Bhadauria 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Hamza Ansari 2 years, 2 months ago

b/a

Zaid Agha Khan 2 years, 2 months ago

√b²-a²

ANSWER

A road which is 7m wide surrounds a circular park whose circumference is 88m .Find the area if the road

Posted by Tanmay Anand 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Gayatri Pathade 2 years, 2 months ago

462msq

Vanshika Zade 2 years, 2 months ago

If the circumference of the road is 88 cm then its radius would be 44 cm

ANSWER

Statement ( A ) (Assertion) : ( triangle A B C ) is an isosceles triangle right angled of ( C ), then ( A B^{2}=2 A C^{2} ).Statement ( R ) (Reason) : In right ( triangle A B C ), right angled at ( B , AC ^{2}=A B^{2}+B C^{2} )(a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)(b) Both Assertion (A) and Reason (R) are the true and Reason (R) is not the correct explanation of Assertion (A)(c) Assertion (A) is true but Reason (R) is false(d) Assertion (A) is false but Reason ( (R) ) is true

Posted by Shubham Pathak 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Sarika Maurya 2 years, 2 months ago

Option (d) Assertion (A) is false but Reason (R) is true

ANSWER

Find the values of of a , b, and c , such that the numbers. a , 10 , b , c , 31 are in AP

Posted by Ajay Chaudhary 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Class 2 years, 2 months ago

a+d=10 a+4d=31 Subtracting we get 3d=21 d=7, a=3 hence a=3,b=17,c=24

ANSWER

The number of revolutions made by a circular wheel of radius 0.25 m in rolling a distance of 11 km.

Posted by Shourya Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Vivek Prajapati 2 years, 2 months ago

500

ANSWER

R_p_o

Posted by Saurabh Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Chapter 12 and 13

Posted by Utkarsh Yadav 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Utkarsh Yadav 2 years, 2 months ago

Exercise 12. 1

ANSWER

If the nth term of A.P. 12,15,18......99 is 99. Then the value of n is equal to

Posted by Rohan Gupta 2 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Shourya Kumar 2 years, 2 months ago

an=99 a=12 d=3 an=a+(n-1)d 99=12+(n-1)×3 (n-1)×3=99-12 (n-1)=87÷3 n-1=29 n=29+1 [n=30].

Poornima Garg 2 years, 2 months ago

a=12 d=15-12=3 an=99 an=a+(n-1)d 99=12+(n-1)3 99=12+3n-3 99=9+3n 99-9=3n 90=3n n=30

🥱🥱 ... 2 years, 2 months ago

itna to kr dia bro... solve to khud hi kr loge...

Nikhil Gautam 2 years, 2 months ago

Sir solve kar do

🥱🥱 ... 2 years, 2 months ago

use 99 as an... put terms in formula an = a + ( n - 1 ) ( d ) 99 = 12 + ( n - 1 ) ( 3 )

ANSWER

Find the common difference of an AP in which a25-a12=-52

Posted by Ankit Soni 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Shubham Pathak 2 years, 2 months ago

(a + 24d) - (a + 11d) = -52. => 13d = -52. => d = - 4

ANSWER

A straight highway leads to the foot of a tower a watchman standing at the top of a tower observes a car at an angle of depression of 30° which is approaching the foot of a tower with a uniform speed 2 minute later the angle of depression was found to be 60° the watchman suspect that some Teritarrites are approaching the tower it needs half a minute for a watchman to inform the security staff so that it may alert . On this information answer the following questions 1.Find the angle of depression from object to the point on the ground and the angle of elevation of the same point

Posted by Divya Sinha 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Divya Sinha 2 years, 2 months ago

Arihant sample paper 8 q no. 37

Divya Sinha 2 years, 2 months ago

Angle of depression from object to the point on the ground and the angle of elevation of the same point is equal

Vanshika Zade 2 years, 2 months ago

/ /+ / /. + / /. + /. /. + ------------({) _________ This is the diagram

ANSWER

Find the LCM of 12 and 13

Posted by Vijay Makwana 2 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Sarika Maurya 2 years, 2 months ago

156

Harsh Jadon 2 years, 2 months ago

156

Bhavna Vimal 2 years, 2 months ago

16464733393392

Omya Aryan 2 years, 2 months ago

156

Vijay Makwana 2 years, 2 months ago

LCM of 12 and 13

ANSWER

In a pot the sum of radii of circular top and bottom if a flower pot is 142 cm and difference of their circumference is 88cm find the diameter of circular and top and bottom

Posted by Aman Negi 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Diva Shah 2 years, 2 months ago

156 and 128

ANSWER

What is the formula of finding mean when moad and median is given

Posted by Akanksha Singh 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Saumya Singh 2 years, 2 months ago

3median =mode + 2 mean

Lakshmi Kanth T 2 years, 2 months ago

2mean = 3median - mode

Shubham Pathak 2 years, 2 months ago

3median = mode + 2mean Mean = (3median - mode)/2

Vishal Kumar 2 years, 2 months ago

Gnbs'wb

ANSWER

If p and q are the zeroes of the quadratic polynomial f(x)=2x²-7x+3, find the value of p+q - pq is

Posted by Jayant Khanna 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Lakshmi Kanth T 2 years, 2 months ago

P+q = 7/2, pq = 3/2, P+q - PQ= 7/2 - 3/2 =(7-3)/2 =4/2=2

Manish Sharma 2 years, 2 months ago

p+q=7/2. pq=3/2. p+q-pq=7/2-3/2=2

Samreen Khanam 2 years, 2 months ago

Given: p and q are the zeros of the polynomial f(x)=2xsq.-7x+3=2xsq.-(6x+1x) =2xsq.-6x-x+3=2x(x-3) -1(x-3) =(2x-1) (x-3) X=1/2 X=3 Now, P+Q=7/2 Pq=3/2 Answer

ANSWER

All the trigonometry formula to ask these que. My all 10 board student.

Posted by Dhwani Panchal 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If the nᵗʰ term of an AP is 7-4n. Find the common difference.

Posted by Aryan Rawat 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Gayatri Pathade 2 years, 2 months ago

It's -4

Mohd Arsalan 2 years, 2 months ago

-7

Prince Kumar 2 years, 2 months ago

Let An term be 1 A1=7-4*1 =3 Let An term be 2 A2=7-4*2 =7-8 =-1 Now Common difference=A2-A1 =-1-3 =-4 Hence the required common difference is -4.

Nikhil Yadav 2 years, 2 months ago

-7

ANSWER

Ajay lives in Delhi, The city of Ajay's father in laws residence is at Jaipur is 600 km from Delhi. Ajay used to travel this 600 km partly by train and partly by car. He used to buy cheap items from Delhi and sale at Jaipur and also buying cheap items from Jaipur and sale at Delhi. Once From Delhi to Jaipur in forward journey he covered 2x km by train and the rest y km by taxi. But, while returning he did not get a reservation from Jaipur in the train. So first 2y km he had to travel by taxi and the rest x km by Train. From Delhi to Jaipur he took 8 hrs but in returning it took 10 hrs.

Posted by Akshita Sood 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Anjali Gupta 1 year, 4 months ago

I Don't know

ANSWER

Sir which topic is deleted in ch no 12 areas related to circle

Posted by Ashutosh Dash 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Mohd Arsalan 2 years, 2 months ago

12.4

Nikhil Yadav 2 years, 2 months ago

12.3 and 12.4

Sumit Sharma 2 years, 2 months ago

12.4

ANSWER

The sum of the numerator and denominator of a fraction is 4 more than twice the numerator if the numerator and denominator are increase by 3 they are in the ratio 2:3 determine the fraction

Posted by Ritika 🌸❤ 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Rayapu Lakshmi Narayana Reddy 2 years, 2 months ago

Hi

ANSWER

5 sec^2 A -5tsn^2 A. Is equal to:

Posted by Abhishek Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Dhwani Panchal 2 years, 2 months ago

1

Ekesh Sharma 2 years, 2 months ago

5(sec^2- tan^2) =5(1) =5

ANSWER

The area of the circle that can be inscribed in a square of side 6cm is: : Option A) 36π cm^2 B)18π cm^2 C)12π cm^2 D)9π cm^22

Posted by Abhishek Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

A B 2 years, 2 months ago

Option:-D is correct

Omya Aryan 2 years, 2 months ago

Since, side of the square is 6cm, therefore diameter of the circle is also equal to 6cm. Then radius is 3cm. Area of circle= πr^2, then area =π×3×3= 9πcm^2. Hence, (D) is the correct option.

ANSWER

XY is a tangent to two circles of radii 12cm and 4 cm respectively.If the circles touch each other Find the area of the region bounded by the circles and tangents.

Posted by Tejaswita Singh 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 2 years, 2 months ago

Construct EC || AB AB = 15 cm = EC AD = 12 cm CB = 4 cm DE = 12 - 4 = 8 Tangent is perpendicular to radius ABCE is rectangle and DEC is a right angled triangle So DC ^ 2 = DE ^ 2 + EC ^ 2

DC = 17

ANSWER

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