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  • 4 answers

Parth Sabhaya 4 years, 9 months ago

The Answer is SecA = 4/√7

Pandit Chat 5 years ago

sinA=3/4,calculate secA

Harsh Bhardwaj 5 years ago

sinA= 3/4 , calculate secA

Ratikanta Pradhan Rocky 6 years, 10 months ago

4/√7
  • 3 answers

Aryan Rana 6 years, 10 months ago

Lcm =336×54 upon 6 aage solve kr lena bhai??

Riya Pal 6 years, 10 months ago

9072

Lustig Yashu? 6 years, 10 months ago

Hcf*Lcm=product of to number 6*Lcm=336*54
  • 1 answers

Sia ? 6 years, 7 months ago

A(1, -2), B(2, 3), C(k, 2) and D(-4, -3)are the vertices of a parallelogram.
{tex}\Rightarrow{/tex}AB = CD and AD = BC
Consider AD = BC
{tex}\Rightarrow{/tex}AD2 = BC2
{tex}\Rightarrow{/tex}(-4 -1)2 + (-3 + 2)2 = (k - 2)2 + (2 - 3)2
{tex}\Rightarrow{/tex}(-5)2 = (k - 2)2
{tex}\Rightarrow{/tex} k - 2 = -5
{tex}\Rightarrow{/tex} k = -3

  • 1 answers

Lustig Yashu? 6 years, 10 months ago

Root5 =p/q Squaring both side Root5^2=P^2/q^2 (Root se square cancel) 5=P^2/q^2(exachange the place of 5andq^2) q^2=p^2/5 (p^2 is divisble by 5 so p is also divisble by 5 Lets p^2=5x) q^2=(5x)^2/5 q^2=25x/5 q^2=5X q^2/5=X q^2 is divible by 5 so q is also divisble by 5
  • 0 answers
  • 2 answers

Avinash Saigal 6 years, 10 months ago

No

Avinash Saigal 6 years, 10 months ago

Na
  • 2 answers

Aryan Rana 6 years, 10 months ago

K=7

Avinash Saigal 6 years, 10 months ago

K must not equal to 6 . Any value except 6
  • 0 answers
  • 1 answers

Sia ? 6 years, 4 months ago

Let the speed of stream be x km/h
Speed of boat in still stream = 9 km/h
Speed of boat down the stream = 9 + x km/h
Speed of boat upstream = 9 - x
{tex}\therefore{/tex} Time  taken by boat to go to downstream 15 km = {tex}\frac { 15 } { 9 + x }{/tex} hours.
{tex}\therefore{/tex} Time  taken by boat to go 15 km of stream = {tex}\frac { 15 } { 9 - x }{/tex} hours.
Total time {tex}= \frac { 15 } { 9 + x } + \frac { 15 } { 9 - x } = 3 \frac { 45 } { 60 } = 3 \frac { 3 } { 4 } = \frac { 15 } { 4 }{/tex}
Dividing by 15
{tex}\frac { 1 } { 9 + x } + \frac { 1 } { 9 - x } = \frac { 1 } { 4 } \text { or } \frac { 9 + x + 9 - x } { ( 9 + x ) ( 9 - x ) } = \frac { 1 } { 4 }{/tex}
{tex}\Rightarrow \frac { 18 } { 81 - x ^ { 2 } } = \frac { 1 } { 4 }{/tex} or 81 - x2 = 72
{tex}\therefore{/tex} x2 = 81 - 72 = 9 {tex}\therefore{/tex} x = +3 and x = -3
But x {tex}\neq{/tex} -3
{tex}\therefore{/tex} Speed of stream = 3 km/h

  • 0 answers
  • 1 answers

Manish Gupta 6 years, 10 months ago

Really
  • 3 answers

Manish Gupta 6 years, 10 months ago

How terminating is there when only 2 and 5 are there but 3is also there

Safeeq Ahamed 6 years, 10 months ago

After 4 places

Adhya Singh 6 years, 10 months ago

After 3 decimals
  • 1 answers

Sia ? 6 years, 4 months ago

 According to question we are given that Cards marked with numbers 5 to 50 are placed in a box and mixed thoroughly. A card is drawn from the box at random. Therefore All possible outcomes are 5, 6, 7, 8 …………… 50.

Number of all possible outcomes = 46

  1. Out of the given numbers, the prime numbers less than 10 are 5 and 7.
    Suppose  E1 be the event of getting a prime number less than 10.
    Then, number of favorable outcomes = 2
    Therefore,  P(getting a prime number less than 10) = P(E) = {tex}\frac{ 2}{46}=\frac{1}{23}{/tex}
  2. Out of the given numbers, the perfect squares are 9, 16, 25, 36 and 49.
    Suppose E2 be the event of getting a perfect square.
    Then, number of favorable outcomes = 5
    Therefore, P(getting a perfect square) = P(E) = {tex}\frac{5}{46}{/tex}
  • 3 answers

Sahil Rajput 6 years, 10 months ago

K=6

Adhya Singh 6 years, 10 months ago

My answer is also k=6 but I have dout

?Aryan ? 6 years, 10 months ago

K=6
  • 2 answers

Ship.. ??? 6 years, 10 months ago

Bonus

Avinash Saigal 6 years, 10 months ago

Yaa you are right . Total frequency is given as 100 but after adding them it is 110
  • 1 answers

Sia ? 6 years, 4 months ago

We have, 612 and 1314

{tex} \therefore \quad 612 = ( 2 \times 2 \times 3 \times 3 \times 17 ) = \left( 2 ^ { 2 } \times 3 ^ { 2 } \times 17 \right){/tex}
and {tex}1314 = ( 2 \times 3 \times 3 \times 73 ) = \left( 2 \times 3 ^ { 2 } \times 73 \right){/tex}.
{tex}\therefore{/tex} HCF (612,1314) = product of common terms with lowest power
{tex}= \left( 2 \times 3 ^ { 2 } \right) = ( 2 \times 9 ) {/tex}
HCF (612,1314) = 18
and LCM (612, 1314) = product of prime factors with highest power
{tex}= \left( 2 ^ { 2 } \times 3 ^ { 2 } \times 17 \times 73 \right) = ( 4 \times 9 \times 17 \times 73 ){/tex}
LCM (612, 1314) = 44676.
Hence, HCF(612, 1314) = 18
and LCM(612, 1314) = 44676.

  • 5 answers

Simran Arora 6 years, 10 months ago

It was ok ok Not too difficult not too easy

Adhya Singh 6 years, 10 months ago

Is All set contains different questions?

Anushka K 6 years, 10 months ago

It was easy but may be I will not score good marks.

?Aryan ? 6 years, 10 months ago

True

Kartik Sharma 6 years, 10 months ago

it was very easy
  • 1 answers

Yogita Ingle 6 years, 10 months ago

a = 15 d = -3 an = 0
an = a+ (n - 1)d
15+(n -1)(-3)  = 0
15 - 3n + 3 = 0
- 3n + 18 = 0
-3n = -18
n = 18/3 = 6
 

  • 0 answers

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