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Ask QuestionPosted by Surender Singh Tanwar 6 years, 10 months ago
- 1 answers
Posted by M A Santos 6 years, 10 months ago
- 3 answers
Posted by Shivam Mapara 6 years, 10 months ago
- 1 answers
Posted by Lustig Yashu? 6 years, 10 months ago
- 1 answers
Posted by Priyanshi Jain 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
Point P(x, 0) is equidistant from point A(- 2, 0) and B(6, 0) i.e. AP = BP
{tex}\Rightarrow AP^2=BP^2{/tex}
{tex}\Rightarrow (-2-x)^2+(0-0)^2=(6-x)^2+ (0-0)^2{/tex}(by distance formula)
{tex}\Rightarrow [(-1)(2+x)]^2=(6-x)^2{/tex}
{tex}\Rightarrow 4+4x+x^2=36- 12x +x^2{/tex}
{tex}\Rightarrow 4+4x=36- 12x {/tex}
{tex}\Rightarrow 36- 12x -4-4x=0{/tex}
{tex}\Rightarrow 32- 16x =0{/tex}
{tex}\Rightarrow 32= 16x {/tex}
{tex}\Rightarrow x=2{/tex}
Hence, point P(2,0) is equidistant from point A(- 2, 0) and B(6, 0).
Posted by Ritik Singh 6 years, 10 months ago
- 3 answers
Ritik Singh 6 years, 10 months ago
Lustig Yashu? 6 years, 10 months ago
Posted by Trinath Trinath Reddy 6 years, 10 months ago
- 1 answers
Posted by M A Santos 6 years, 10 months ago
- 0 answers
Posted by Varsha Yadav 6 years, 10 months ago
- 0 answers
Posted by Aryan Rana 6 years, 10 months ago
- 1 answers
Yogita Ingle 6 years, 10 months ago
f(x) = kx2 + 2x - 3
put x = 2
f(2) = k(2)2 + 2(2)- 3
= 4k +4 - 3
= 4k + 1
If x = 2 is solution of given equation then f(2) = 0
4k + 1 = 0
4k = -1
k = -1/4
Posted by Reena Sarkar 6 years, 10 months ago
- 0 answers
Posted by Reena Sarkar 6 years, 10 months ago
- 0 answers
Posted by Lustig Yashu? 6 years, 10 months ago
- 1 answers
Posted by Ramfal Singh 6 years, 4 months ago
- 1 answers
Sia ? 6 years, 4 months ago
Given A(3, 1), B(5, 1), C(a, b) and D(4, 3) are the vertices of parallelogram.
We know that, Diagonals of parallelogram bisect each other
{tex}\therefore{/tex} {tex}\left(\frac{3+a}{2}, \frac{1+b}{2}\right){/tex} = {tex}\left(\frac{5+4}{2}, \frac{1+3}{2}\right){/tex}
Equating x and y terms, we get
3 + a = 9 and 1 + b = 4
a = 6 and b = 3
Therefore, a = 6, b = 3
Posted by Samyak Kankaria 6 years, 10 months ago
- 0 answers
Posted by Prince Garg 6 years, 10 months ago
- 2 answers
Posted by Sahil Goyal 6 years, 10 months ago
- 0 answers
Posted by Manish Gupta 6 years, 10 months ago
- 1 answers
Yogita Ingle 6 years, 10 months ago
he distance between the points A(0,0) and B(x , -4) is 5 units
√ (0-x)2 + ( 0 - (-4)2 = 5
√ x2 + 16 = 5
Squaring on both side, we get
x2 + 16 = 25
x 2 = 25 - 16
x2 = 9
x = 3
Posted by Dolma Lhamo 6 years, 10 months ago
- 2 answers
Posted by Prashant Singh 6 years, 10 months ago
- 0 answers
Posted by Tamanna Sharma 6 years, 10 months ago
- 1 answers
Posted by Harshdeep Singh 6 years, 10 months ago
- 0 answers
Posted by Akshita Khandelwal 6 years, 10 months ago
- 4 answers
Posted by Prachi Gupta 6 years, 10 months ago
- 0 answers

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Kartik Sharma 6 years, 10 months ago
0Thank You